Explanation Procedure used: Solving radical equations: 1. Isolate a single radical on one side of the equation. 2. Square both sides of the equation. (Or raise both sides to a power that is equal to the index of the radical.). 3. If a radica1 remains, repeat steps 1 and 2. 4. Solve the resulting equation. 5. All solutions must be checked in the original equation, and only those that satisfy the original equation are actual solutions. Calculation: By using the above procedure, the given equation can be solved as follows. 3 x 2 + 4 = 2 x [ ∵ Isolating the radical ] ( 3 x 2 + 4 ) 2 = ( 2 x ) 2 [ ∵ Squaring on both sides ] 3 x 2 + 4 = 4 x 2 3 x 2 − 4 x 2 = − 4 On further simplification, − x 2 = − 4 x 2 = 4 x = 4 x = ± 2 Therefore, the values of x are x = 2 and x = − 2 . Now check whether the solution of the given equation is x = 2 or x = − 2 by substitution method. Substitute x = 2 in 3 x 2 + 4 = 2 x

College Algebra in Context with Applications for the Managerial, Life, and Social Sciences (5th Edition)

5th Edition

ISBN: 9780134179025

Author: Ronald J. Harshbarger, Lisa S. Yocco

Publisher: PEARSON

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Chapter 4.4, Problem 2E

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To solve: The equation 3x2+4−2x=0 algebraically and check the solution graphically or by substitution.

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Chapter 4.4, Problem 1E

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College Algebra in Context with Applications for the Managerial, Life, and Social Sciences (5th Edition)

Ch. 4.1 - In Exercises 116, (a) sketch the graph of each...Ch. 4.1 - In Exercises 116, (a) sketch the graph of each...Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - In Exercises 116, (a) sketch the graph of each...Ch. 4.1 - Prob. 7E Ch. 4.1 - Prob. 8E Ch. 4.1 - Prob. 9E Ch. 4.1 - Prob. 10E

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The equation 3 x 2 + 4 − 2 x = 0 algebraically and check the solution graphically or by substitution.

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To solve: The equation 3x2+4−2x=0 algebraically and check the solution graphically or by substitution.

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