Chapter 4.4, Problem 127AYU

Current in as RL Circuit The equation governing the amount of current $I$(in amperes) after time $t$ (in seconds) in simple RL circuit consisting of a resistance $R$ (in ohms), an inductance $L$(in henrys), and an electromotive force $E$(in volts) is

$\text{I }=\frac{E}{R}\left[1-e^{-\left(R/L\right)t}\right]$

If $E=12$ volts, $R\text{ = }10$ ohms, and $L=5$ henrys, how long does it take to obtain a current of $0.5$ ampere? Of $1.0$ ampere? Graph the equation.