Credit Union Assets The total assets (in billions of dollars) held by U.S. credit unions can be approximated by the function f ( x ) = − 689.9 + 695.8 ln x , where x = 10 corresponds to the year 2010. (Data from: Credit Union National Association.) a. What were the total assets in 2011 and 2015? b. If the model remains accurate, what is the first full year in which the total assets in credit unions exceed $1450 billion?
Credit Union Assets The total assets (in billions of dollars) held by U.S. credit unions can be approximated by the function f ( x ) = − 689.9 + 695.8 ln x , where x = 10 corresponds to the year 2010. (Data from: Credit Union National Association.) a. What were the total assets in 2011 and 2015? b. If the model remains accurate, what is the first full year in which the total assets in credit unions exceed $1450 billion?
Solution Summary: The author explains how the total assets held by U.S. credit unions in 2011 and 2015 can be approximated by the function f(x)=-689.9+695.8mat
A function is defined on the interval (-π/2,π/2) by this multipart rule:
if -π/2 < x < 0
f(x) =
a
if x=0
31-tan x
+31-cot x
if 0 < x < π/2
Here, a and b are constants. Find a and b so that the function f(x) is continuous at x=0.
a=
b= 3
Use the definition of continuity and the properties of limits to show that the function is continuous at the given number a.
f(x) = (x + 4x4) 5,
a = -1
lim f(x)
X--1
=
lim
x+4x
X--1
lim
X-1
4
x+4x
5
))"
5
))
by the power law
by the sum law
lim (x) + lim
X--1
4
4x
X-1
-(0,00+(
Find f(-1).
f(-1)=243
lim (x) +
-1 +4
35
4 ([
)
lim (x4)
5
x-1
Thus, by the definition of continuity, f is continuous at a = -1.
by the multiple constant law
by the direct substitution property
Chapter 4 Solutions
Mathematics with Applications, Books a la Carte, and MyLab Math with Pearson eText - Title-Specific Access Card Package (12th Edition)
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