University Physics with Modern Physics, Volume 2 (Chs. 21-37); Mastering Physics with Pearson eText -- ValuePack Access Card (14th Edition)
14th Edition
ISBN: 9780134265414
Author: Hugh D. Young, Roger A. Freedman
Publisher: PEARSON
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Question
Chapter 43, Problem 43.63P
(a)
To determine
The energy delivered to the tumor per second.
(b)
To determine
The absorbed dose in
(c)
To determine
The equivalent dose in
(d)
To determine
The exposure time required for an equivalent dose of
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Chapter 43 Solutions
University Physics with Modern Physics, Volume 2 (Chs. 21-37); Mastering Physics with Pearson eText -- ValuePack Access Card (14th Edition)
Ch. 43.1 - Prob. 43.1TYUCh. 43.2 - Rank the following nuclei in order from largest to...Ch. 43.3 - Prob. 43.3TYUCh. 43.4 - Prob. 43.4TYUCh. 43.5 - Prob. 43.5TYUCh. 43.6 - Prob. 43.6TYUCh. 43.7 - Prob. 43.7TYUCh. 43.8 - Prob. 43.8TYUCh. 43 - Prob. 43.1DQCh. 43 - Prob. 43.2DQ
Ch. 43 - Prob. 43.3DQCh. 43 - Prob. 43.4DQCh. 43 - Prob. 43.5DQCh. 43 - Prob. 43.6DQCh. 43 - Prob. 43.7DQCh. 43 - Prob. 43.8DQCh. 43 - Prob. 43.9DQCh. 43 - Prob. 43.10DQCh. 43 - Prob. 43.11DQCh. 43 - Prob. 43.12DQCh. 43 - Prob. 43.13DQCh. 43 - Prob. 43.14DQCh. 43 - Prob. 43.15DQCh. 43 - Prob. 43.16DQCh. 43 - Prob. 43.17DQCh. 43 - The most common radium isotope found on earth,...Ch. 43 - Prob. 43.19DQCh. 43 - Prob. 43.20DQCh. 43 - Prob. 43.1ECh. 43 - Prob. 43.2ECh. 43 - Prob. 43.3ECh. 43 - Prob. 43.4ECh. 43 - Prob. 43.5ECh. 43 - Prob. 43.6ECh. 43 - Prob. 43.7ECh. 43 - Prob. 43.8ECh. 43 - Prob. 43.9ECh. 43 - Prob. 43.10ECh. 43 - Prob. 43.11ECh. 43 - Prob. 43.12ECh. 43 - Prob. 43.13ECh. 43 - Prob. 43.14ECh. 43 - Prob. 43.15ECh. 43 - Prob. 43.16ECh. 43 - Prob. 43.17ECh. 43 - Prob. 43.18ECh. 43 - Prob. 43.19ECh. 43 - Prob. 43.20ECh. 43 - Prob. 43.21ECh. 43 - Prob. 43.22ECh. 43 - Prob. 43.23ECh. 43 - Prob. 43.24ECh. 43 - Prob. 43.25ECh. 43 - Prob. 43.26ECh. 43 - Measurements on a certain isotope tell you that...Ch. 43 - Prob. 43.28ECh. 43 - Prob. 43.29ECh. 43 - Prob. 43.30ECh. 43 - Prob. 43.31ECh. 43 - Prob. 43.32ECh. 43 - Prob. 43.33ECh. 43 - Prob. 43.34ECh. 43 - Prob. 43.35ECh. 43 - Prob. 43.36ECh. 43 - Prob. 43.37ECh. 43 - Prob. 43.38ECh. 43 - Prob. 43.39ECh. 43 - Prob. 43.40ECh. 43 - Prob. 43.41ECh. 43 - Energy from Nuclear Fusion. Calculate the energy...Ch. 43 - Prob. 43.43ECh. 43 - Prob. 43.44ECh. 43 - Prob. 43.45ECh. 43 - Prob. 43.46ECh. 43 - Prob. 43.47PCh. 43 - Prob. 43.48PCh. 43 - Prob. 43.49PCh. 43 - Prob. 43.50PCh. 43 - Prob. 43.51PCh. 43 - Prob. 43.52PCh. 43 - Prob. 43.53PCh. 43 - Prob. 43.54PCh. 43 - Prob. 43.55PCh. 43 - Prob. 43.56PCh. 43 - Prob. 43.57PCh. 43 - Prob. 43.58PCh. 43 - Prob. 43.59PCh. 43 - Prob. 43.60PCh. 43 - Prob. 43.61PCh. 43 - Prob. 43.62PCh. 43 - Prob. 43.63PCh. 43 - Prob. 43.64PCh. 43 - Prob. 43.65PCh. 43 - Prob. 43.66PCh. 43 - Prob. 43.67PCh. 43 - Prob. 43.68PCh. 43 - DATA Your company develops radioactive isotopes...Ch. 43 - Prob. 43.70PCh. 43 - Prob. 43.71CPCh. 43 - Prob. 43.72CPCh. 43 - Prob. 43.73PPCh. 43 - Prob. 43.74PPCh. 43 - Prob. 43.75PPCh. 43 - Prob. 43.76PPCh. 43 - Prob. 43.77PP
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- (a) Background radiation due to 226Ra averages only 0.01 mSv/y, but it can range upward depending on where a 226Ra in the 80.0kg body of a man who receives a dose of 2.50mSv/y from it, noting that each 226Ra decay emits a 4.80MeV particle. You may person lives. Find the mass of neglect dose due to daughters and assume a constant amount, evenly distributed due to balanced ingestion and handily elimination. (b) Is it surprising that such a small mass could cause a measurable radiation dose? Explain.arrow_forward(a) A cancer patient is exposed to rays from a 5000Ci 60Co transillumination unit for 32.0 s. The rays are collimated in such a manner that only 1.00% of them strike the patient. Of those, 20.0% are absorbed in a tumor having a mass of 1.50 kg. What is the dose in rem to the tumor, it the average energy per decay is 1.25 MeV? None of the s from the decay reach the patient. (b) Is the dose consistent with stated therapeutic doses?arrow_forwardA beam of 168MeV nitrogen nuclei is used for cancer therapy. If this beam is directed onto a 0.200kg tumor and gives it a 2.00Sv dose, how many nitrogen nuclei were stopped? (Use an RBE of 20 for heavy ions.)arrow_forward
- Large amounts of 65Zn are produced in copper exposed to accelerator beams. While machining contaminated copper, a physicist ingests 50.0 Ci of 65Zn. Each 65Zn decay emits an average ray energy of 0.550 MeV, 40.0% of which is absorbed in the scientist’s 75.0kg body. What dose in mSv is caused by this in one day?arrow_forwardData from the appendices and the periodic table may be needed for these problems. A 60Co source is labeled 4.00 mCi, but its present activity is found to be 1.85107Bq. (a) What is the present activity in mCi? (b) How long ago did it actually have a 4.00—mCi activity?arrow_forwardCalculate the dose in Sv to the chest at a patient given an xray under the following conditions. The xray beam intensity is 1.50 W/m2, the area of the chest exposed is 0.0750 m2 35.0% of the xrays are absorbed in 20.0 kg of tissue, and the exposure time is 0.250 s.arrow_forward
- (a) Find the total energy released in MeV in each carbon cycle (elaborated in the above problem) including the annihilation energy. (b) How does this compare with the protonproton cycle output?arrow_forwardThe electrical power output of a large nuclear reactor facility is 900 MW. It has a 35.0% efficiency in converting nuclear power to electrical. (a) What is the thermal nuclear power output in megawatts? (b) How many 235U nuclei fission each second, assuming the average fission produces 200 MeV? (c) What mass of 235U is fissioned in one year of fullpower operation?arrow_forward(a) Calculate the energy released in the neutroninduced fission reaction n+239Pu96Sr+140Ba+4n, given m(96Sr)=95.921750u and m(140Ba)=139.910581u. (b) Confirm that the total number of nucleons and total charge are conserved in this reaction.arrow_forward
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