Physics for Science and Engineering With Modern Physics, VI - Student Study Guide
4th Edition
ISBN: 9780132273244
Author: Doug Giancoli
Publisher: PEARSON
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Chapter 43, Problem 32P
To determine
Whether a
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(III) What magnetic field B is needed to keep 998-GeV
protons revolving in a circle of radius 1.0 km? Use the
relativistic mass. The proton's “rest mass" is 0.938 GeV/c².
(1 GeV = 10° eV.) [Hint: In relativity, m,elv²/r = qvB_is
still valid in a magnetic field, where mrel =
Ym.]
-23 Consider the decay A0 p + with the A at rest.
(a) Calculate the disintegration energy. What is the kinetic energy
of (b) the proton and (c) the pion? (Hint: See Problem 6.)
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Chapter 43 Solutions
Physics for Science and Engineering With Modern Physics, VI - Student Study Guide
Ch. 43.1 - Prob. 1AECh. 43.2 - Prob. 1CECh. 43.9 - Prob. 1DECh. 43.9 - Prob. 1EECh. 43 - Prob. 1QCh. 43 - If a proton is moving at very high speed, so that...Ch. 43 - Prob. 3QCh. 43 - Prob. 4QCh. 43 - Prob. 5QCh. 43 - Prob. 6Q
Ch. 43 - Prob. 7QCh. 43 - Prob. 8QCh. 43 - Prob. 9QCh. 43 - Prob. 10QCh. 43 - Prob. 11QCh. 43 - Prob. 12QCh. 43 - Prob. 13QCh. 43 - Prob. 14QCh. 43 - Prob. 15QCh. 43 - Prob. 16QCh. 43 - Prob. 17QCh. 43 - Prob. 18QCh. 43 - Prob. 19QCh. 43 - Prob. 20QCh. 43 - Prob. 1PCh. 43 - Prob. 2PCh. 43 - Prob. 3PCh. 43 - Prob. 4PCh. 43 - Prob. 5PCh. 43 - Prob. 6PCh. 43 - Prob. 7PCh. 43 - Prob. 8PCh. 43 - Prob. 9PCh. 43 - Prob. 10PCh. 43 - Prob. 11PCh. 43 - Prob. 12PCh. 43 - Prob. 13PCh. 43 - Prob. 14PCh. 43 - Prob. 15PCh. 43 - Prob. 16PCh. 43 - Prob. 17PCh. 43 - Prob. 18PCh. 43 - Prob. 19PCh. 43 - Prob. 20PCh. 43 - Prob. 21PCh. 43 - Prob. 22PCh. 43 - Prob. 23PCh. 43 - Prob. 24PCh. 43 - Prob. 25PCh. 43 - Prob. 26PCh. 43 - Prob. 27PCh. 43 - Prob. 28PCh. 43 - Prob. 29PCh. 43 - Prob. 30PCh. 43 - Prob. 31PCh. 43 - Prob. 32PCh. 43 - Prob. 33PCh. 43 - Prob. 34PCh. 43 - Prob. 35PCh. 43 - Prob. 36PCh. 43 - Prob. 37PCh. 43 - Prob. 38PCh. 43 - Prob. 39PCh. 43 - Prob. 40PCh. 43 - Prob. 41PCh. 43 - Prob. 42PCh. 43 - Prob. 43PCh. 43 - Prob. 44PCh. 43 - Prob. 45PCh. 43 - Prob. 46GPCh. 43 - Prob. 47GPCh. 43 - Prob. 48GPCh. 43 - Prob. 49GPCh. 43 - Prob. 50GPCh. 43 - Prob. 51GPCh. 43 - Prob. 52GPCh. 43 - Prob. 53GPCh. 43 - Prob. 54GPCh. 43 - Prob. 55GPCh. 43 - Prob. 56GPCh. 43 - Prob. 57GPCh. 43 - Prob. 58GPCh. 43 - Prob. 59GPCh. 43 - Prob. 60GPCh. 43 - Prob. 61GPCh. 43 - Prob. 62GPCh. 43 - Prob. 63GPCh. 43 - Prob. 64GPCh. 43 - What fraction of the speed of light c is the speed...Ch. 43 - Prob. 66GPCh. 43 - Prob. 67GP
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- The primary decay mode for the negative pion is +v . (a) What is the energy release in MeV in this decay? (b) Using conservation of momentum, how much energy does each of the decay products receive, given the is at rest when it decays? You may assume the muon antineutrino is massless and has momentum p = E/c , just like a photon.arrow_forwardThe K0 meson is an uncharged member of the particle “zoo” that decays into two charged pions according to K0 → π+ + π−. The pions have opposite charges, as indicated, and the same mass, mπ = 140 MeV/c2. Suppose that a K0 at rest decays into two pions in a bubble chamber in which a magnetic field of 2.0 T is present (see Fig. P2.22). If the radius of curvature of the pions is 34.4 cm, find (a) the momenta and speeds of the pions and (b) the mass of the K0 meson.arrow_forwardHow can the lifetime of a particle indicate that its decay is caused by the strong nuclear force? How can a change in strangeness imply which force is responsible for a reaction? What does a change in quark ?avor imply about the force that is responsible?arrow_forward
- The average particle energy needed to observe uni?cation of forces is estimated to be 1019 GeV. (a) What is the rest mass in kilograms of a particle that has a rest mass of (b) How many times the mass of a hydrogen atom is this?arrow_forwardCalculate the linear momentm of 25 GeV proton assuming that rest mass energy of the proton is 1 GeV.arrow_forwardThe conservation of energy Hv=2ymc*c.A O H=2KT.BO H=EKT.CO None of these.DOarrow_forward
- 3. What is the kinetic energy in MeV of a of a π-meson that lives 1.40 × 10−16 s as measured in the laboratory, and 0.840 × 10−16 s when at rest relative to an observer, given that its rest energy is 135 MeV? Please put the solution and indicate what is the answer. Topic: realistic energy and momentumarrow_forwardA)The magnitude of the center of mass energy, √s ,determines what reactions can take place. Which has a higher CM energy: A 10 GeV (1 GeV = 109 electron Volt) electron colliding with a target (stationary) proton, or a 10 GeV proton colliding with a target electron B) What is the advantage of a collider in which 45 GeV electrons and positrons collide as compared with a beam of 90 GeV positrons hitting a stationary electron? In each case what is the CM energy available to create new particles ?arrow_forward9arrow_forward
- 4arrow_forwardThe intensity of cosmic ray radiation decreases rapidly with increasing energy, but there are occasionally extremely energetic cosmic rays that create a shower of radiation from all the particles they create by striking a nucleus in the atmosphere as seen in the figure given below. Suppose a cosmic ray particle having an energy of 1010 GeV converts its energy into particles with masses averaging 200 MeV/c2 . (a) How many particles are created? (b) If the particles rain down on a 1.00-km2 area, how many particles are there per square meter?arrow_forwardConsider the decay process K+→лº with the K+ at rest. Find - (a) the total energy of the лº meson -0 (b) its relativistic kinetic energy The rest mass energy is 494 MeV for K+, 140 MeV for 7, 135 MeV for лº.arrow_forward
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