Physics for Scientists and Engineers with Modern Physics
4th Edition
ISBN: 9780131495081
Author: Douglas C. Giancoli
Publisher: Addison-Wesley
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Chapter 43, Problem 24P
(a)
To determine
The
(b).
To determine
The kinetic energy of the
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(c) Write down the reaction describing the decay of Na to 16NE. Calculate
the end-point energy (i.e., maximum kinetic energy) for the particle emitted by
the Na nucleus in this decay. The atomic masses of Na and 73NE are
21.99444 u and 21.99139 u, respectively.
(c) Write down the reaction describing the decay of Na to jNe. Calculate
the end-point energy (i.e., maximum kinetic energy) for the particle emitted by
the Na nucleus in this decay. The atomic masses of Na and Ne are
21.99444 u and 21.99139 u, respectively.
Complete the decay process that 1s showing below and naming the unknown product also find the kinetic energy of the most energetic product that emitted during the decay. Where My = 2.2eV/c? 213Bi — By +a+d
Chapter 43 Solutions
Physics for Scientists and Engineers with Modern Physics
Ch. 43.1 - Prob. 1AECh. 43.2 - Prob. 1CECh. 43.9 - Prob. 1DECh. 43.9 - Prob. 1EECh. 43 - Prob. 1QCh. 43 - If a proton is moving at very high speed, so that...Ch. 43 - Prob. 3QCh. 43 - Prob. 4QCh. 43 - Prob. 5QCh. 43 - Prob. 6Q
Ch. 43 - Prob. 7QCh. 43 - Prob. 8QCh. 43 - Prob. 9QCh. 43 - Prob. 10QCh. 43 - Prob. 11QCh. 43 - Prob. 12QCh. 43 - Prob. 13QCh. 43 - Prob. 14QCh. 43 - Prob. 15QCh. 43 - Prob. 16QCh. 43 - Prob. 17QCh. 43 - Prob. 18QCh. 43 - Prob. 19QCh. 43 - Prob. 20QCh. 43 - Prob. 1PCh. 43 - Prob. 2PCh. 43 - Prob. 3PCh. 43 - Prob. 4PCh. 43 - Prob. 5PCh. 43 - Prob. 6PCh. 43 - Prob. 7PCh. 43 - Prob. 8PCh. 43 - Prob. 9PCh. 43 - Prob. 10PCh. 43 - Prob. 11PCh. 43 - Prob. 12PCh. 43 - Prob. 13PCh. 43 - Prob. 14PCh. 43 - Prob. 15PCh. 43 - Prob. 16PCh. 43 - Prob. 17PCh. 43 - Prob. 18PCh. 43 - Prob. 19PCh. 43 - Prob. 20PCh. 43 - Prob. 21PCh. 43 - Prob. 22PCh. 43 - Prob. 23PCh. 43 - Prob. 24PCh. 43 - Prob. 25PCh. 43 - Prob. 26PCh. 43 - Prob. 27PCh. 43 - Prob. 28PCh. 43 - Prob. 29PCh. 43 - Prob. 30PCh. 43 - Prob. 31PCh. 43 - Prob. 32PCh. 43 - Prob. 33PCh. 43 - Prob. 34PCh. 43 - Prob. 35PCh. 43 - Prob. 36PCh. 43 - Prob. 37PCh. 43 - Prob. 38PCh. 43 - Prob. 39PCh. 43 - Prob. 40PCh. 43 - Prob. 41PCh. 43 - Prob. 42PCh. 43 - Prob. 43PCh. 43 - Prob. 44PCh. 43 - Prob. 45PCh. 43 - Prob. 46GPCh. 43 - Prob. 47GPCh. 43 - Prob. 48GPCh. 43 - Prob. 49GPCh. 43 - Prob. 50GPCh. 43 - Prob. 51GPCh. 43 - Prob. 52GPCh. 43 - Prob. 53GPCh. 43 - Prob. 54GPCh. 43 - Prob. 55GPCh. 43 - Prob. 56GPCh. 43 - Prob. 57GPCh. 43 - Prob. 58GPCh. 43 - Prob. 59GPCh. 43 - Prob. 60GPCh. 43 - Prob. 61GPCh. 43 - Prob. 62GPCh. 43 - Prob. 63GPCh. 43 - Prob. 64GPCh. 43 - What fraction of the speed of light c is the speed...Ch. 43 - Prob. 66GPCh. 43 - Prob. 67GP
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- The K0 meson is an uncharged member of the particle “zoo” that decays into two charged pions according to K0 → π+ + π−. The pions have opposite charges, as indicated, and the same mass, mπ = 140 MeV/c2. Suppose that a K0 at rest decays into two pions in a bubble chamber in which a magnetic field of 2.0 T is present (see Fig. P2.22). If the radius of curvature of the pions is 34.4 cm, find (a) the momenta and speeds of the pions and (b) the mass of the K0 meson.arrow_forwardCalculate the energy released in the + decay of 22Na, the equation for which is given in the text. The masses at 22Na and 22Ne are 21.994434 and 21.991333 u, reSpec?vely.arrow_forwardThe primary decay mode for the negative pion is +v . (a) What is the energy release in MeV in this decay? (b) Using conservation of momentum, how much energy does each of the decay products receive, given the is at rest when it decays? You may assume the muon antineutrino is massless and has momentum p = E/c , just like a photon.arrow_forward
- If 1.01030MeV of energy is released in the annihilation of a sphere of matter and antimatter, and the spheres are equal mass, what are the masses of the spheres?arrow_forwardIn a nuclear power plain, the fuel rods last 3 yr before they are replaced. The plant can transform energy at a maximum possible rate of 1.00 GW. Supposing it operates at 80.0% capacity for 3.00 yr, what is the loss of mass of the fuel?arrow_forwardDerive an approximate relationship between the energy of (decay and halflife using the following data. It may be useful to graph the leg t1/2 against Ea to find some straightline relationship. Table 31.3 Energy and HalfLife for (Decay Nuclide E( (MeV) t1/2 216Ra 9.5 0.18 (s 194Po 7.0 0.7 s 240Cm 6.4 27 d 226Ra 4.91 1600 y 232Th 4.1 1.41010yarrow_forward
- 3. (i) Show that the kinetic energy of an alpha particle produced by the decay of a stationary 210Th nuclide is given by To = Q ((mTh-ma)c² — Q) mThc² - Q where ma is the mass of the alpha particle, mTh is the mass of the thorium nuclide, and Q has its usual meaning in nuclear decays. Note that none of the particles are moving relativistically. (ii) To is measured to be 7.8985 MeV, mTh, is measured to be 210.015075 u, the mass of the alpha particle is measured to be 4.001506 u, and the mass of the electron is measured to be 0.0005486 u. Calculate the mass in atomic mass units of the neutral daughter nuclide pro- duced by the decay.arrow_forwardNonearrow_forward(Q5): How much energy is released in the following nuclear reaction: n+ U→Sr + Xe + 12 n 136 38 Assume all of the particles are at rest or have very small kinetic energy before and after the reaction. Mass of neutron is 1.008665 u, U: 235.043924 u, Sr: 87.905618 u, and Xe: 135.90721u.arrow_forward
- Certain theories predict that the proton is unstable, with a half-life of about 1032 years.Assuming that this is true, calculate the number of proton decays you would expect to occur in one year in the water of an Olympic-sized swimming pool holding 4.32 * 105 L of water.arrow_forward226 222 For the radioactive decay of radium-226, ²²Ra → ²²²Rn + He, calculate AE in 86 kilojoules when 2.2 g of radium decays. Mass of He: 4.0015 g Mass of 222Rn: 221.9703 g 86 226 Mass of 2Ra: 225.9771g Hint: Mass defect can be set up as: m = mass of products mass of reactants (Include signs, and use two decimal places. No units in answer.) Write exponential answers in this format: 6.022E23 (for 6.022x10^23). No spaces.arrow_forwardThe decay mode of the negative muon is μ- → e-+v-e +vπ. Find the energy released in MeV.arrow_forward
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