Explanation Given: The function is shown below. y = ( 1 − x ) e a x ...... (1) Calculation: The given function is an exponential function. To obtain the critical point of the function, differentiate the equation (1) as shown below: d y d x = d d x ( 1 − x ) e a x y ′ = ( 1 − x ) d d x e a x + e a x d d x ( 1 − x ) y ′ = ( 1 − x ) a e a x + e a x ⋅ ( − 1 ) y ′ = a e a x ( 1 − x ) − e a x To obtain the critical point equate the function y ′ to 0 . a e a x ( 1 − x ) − e a x = 0 e a x ( a ( 1 − x ) ) = 0 The value of e a x cannot be equal to zero. Therefore, by zero product property the value of x is calculated as shown below: 1 − x = 0 x = 1 The critical point is x = 1

4th Edition

ISBN: 9781319055905

Author: FRANZOSA

Publisher: VST

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Question

Chapter 4.2, Problem 84E

To determine

To find:

The maximum and minimum value of the function y=(1−x)eax on the interval [0,1] and 0<a.

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Chapter 4.2, Problem 83E

Chapter 4.2, Problem 85E

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Chapter 4 Solutions

EBK CALCULUS: EARLY TRANSCENDENTALS

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The maximum and minimum value of the function y = ( 1 − x ) e a x on the interval [ 0 , 1 ] and 0 < a .

Solution Summary: The author explains that the given function is an exponential function. To obtain the critical point of the function, differentiate the equation as shown below.

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To find:

The maximum and minimum value of the function y=(1−x)eax on the interval [0,1] and 0<a.

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Chapter 4 Solutions

The maximum and minimum value of the function y = ( 1 − x ) e a x on the interval [ 0 , 1 ] and 0 &lt; a .

Solution Summary: The author explains that the given function is an exponential function. To obtain the critical point of the function, differentiate the equation as shown below.

Concept explainers

Videos

To find: The maximum and minimum value of the function y=(1−x)eax on the interval [0,1] and 0<a.

Want to see the full answer?

Chapter 4 Solutions

The maximum and minimum value of the function y = ( 1 − x ) e a x on the interval [ 0 , 1 ] and 0 < a .

To find:

The maximum and minimum value of the function y=(1−x)eax on the interval [0,1] and 0<a.