Explanation Given: The given function is y = ln x x . Calculation: The given interval is [ 1 , 3 ] . Use quotient rule : ( f g ) ' = f ' ⋅ g − g ' ⋅ f g 2 y = ln x x y ' = d d x ( ln x ) ⋅ x − d d x ( x ) ⋅ ( ln x ) x 2 y ' = 1 x ⋅ x − ln x x 2 y ' = 1 − ln x x 2 For critical point y ' = 0

4th Edition

ISBN: 9781319055905

Author: FRANZOSA

Publisher: VST

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Question

Chapter 4.2, Problem 57E

To determine

The minimum and maximum values of the given function in the given interval by comparing with critical and end points.

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Chapter 4.2, Problem 56E

Chapter 4.2, Problem 58E

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In Exercises 27–58, find the critical points and the intervals on which the function is increasing or decreasing. Use the First Derivative Test to determine whether the critical point yields a local min or max (or neither).

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Chapter 4 Solutions

EBK CALCULUS: EARLY TRANSCENDENTALS

Ch. 4.1 - Prob. 1PQ Ch. 4.1 - Prob. 2PQ Ch. 4.1 - Prob. 3PQ Ch. 4.1 - Prob. 4PQ Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - Prob. 6E

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The minimum and maximum values of the given function in the given interval by comparing with critical and end points.

Solution Summary: The author calculates the minimum and maximum values of a given function in the given interval by comparing with critical and end points.

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The minimum and maximum values of the given function in the given interval by comparing with critical and end points.

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Chapter 4 Solutions