EBK ORGANIC CHEMISTRY-PRINT COMPANION (
4th Edition
ISBN: 9781119776741
Author: Klein
Publisher: WILEY CONS
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Question
Chapter 4.2, Problem 5LTS
Interpretation Introduction
Interpretation:
The name for the following compound should be assigned.
Concept Introduction:
Compounds consist of carbon and hydrogen known as hydrocarbons. Saturated hydrocarbon is known as
The compounds in which a series of atoms are connected to form a ring is known as cyclic compound whereas the compounds which are open chain compounds and their atoms don't form a ring is known as acyclic compounds. The general molecular formula of a cyclic alkane is
The compounds in which two rings are connected are known as bicyclic compounds.
Rules of naming bicycloalkanes are:
- First, determine the bicycloalkane present in the structure which is considered as a parent chain (maximum number of carbon atoms). If the acyclic alkane chain has more carbon atoms, then the alkyl chain is considered a parent chain.
- For the bicyclic system, the number of carbon atoms must be identified as present in different paths connected with two bridgeheads.
- The numbering of the parent chain should be done in a way that the substituents get the lowest number.
- The appropriate name should be given to every alkyl group or bicycloalkyl group and denote its position on the parent chain with the number.
- The alkyl groups or bicycloalkyl groups are written in alphabetical order.
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20. The Brusselator. This hypothetical system was first proposed by a group work-
ing in Brussels [see Prigogine and Lefever (1968)] in connection with spatially
nonuniform chemical patterns. Because certain steps involve trimolecular reac
tions, it is not a model of any real chemical system but rather a prototype that
has been studied extensively. The reaction steps are
A-X.
B+X-Y+D.
2X+ Y-3X,
X-E.
305
It is assumed that concentrations of A, B, D, and E are kept artificially con
stant so that only X and Y vary with time.
(a) Show that if all rate constants are chosen appropriately, the equations de
scribing a Brusselator are:
dt
A-(B+ 1)x + x²y,
dy
=Bx-x²y.
di
Problem 3. Provide a mechanism for the following transformation:
H₂SO A
Me.
Me
Me
Me
Me
You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products:
xi
1. ☑
2. H₂O
хе
i
Draw the missing reagent X you think will make this synthesis work in the drawing area below.
If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank.
Click and drag to start drawing a
structure.
There is no reagent that will make this synthesis work without complications.
: ☐
S
☐
Chapter 4 Solutions
EBK ORGANIC CHEMISTRY-PRINT COMPANION (
Ch. 4.2 - Prob. 1LTSCh. 4.2 - Prob. 1PTSCh. 4.2 - Prob. 2PTSCh. 4.2 - Prob. 3ATSCh. 4.2 - Prob. 2LTSCh. 4.2 - Prob. 4PTSCh. 4.2 - Prob. 5ATSCh. 4.2 - Prob. 3LTSCh. 4.2 - Prob. 6PTSCh. 4.2 - Prob. 7ATS
Ch. 4.2 - Prob. 4LTSCh. 4.2 - Prob. 8PTSCh. 4.2 - Prob. 9PTSCh. 4.2 - Prob. 10ATSCh. 4.2 - Prob. 5LTSCh. 4.3 - Prob. 6LTSCh. 4.3 - Prob. 14PTSCh. 4.6 - Prob. 7LTSCh. 4.6 - Prob. 16PTSCh. 4.8 - Prob. 8LTSCh. 4.12 - Prob. 11LTSCh. 4.12 - Prob. 25PTSCh. 4.14 - Prob. 33CCCh. 4.14 - Prob. 34CCCh. 4.14 - Prob. 35CCCh. 4 - Prob. 36PPCh. 4 - Prob. 51PPCh. 4 - Prob. 52PPCh. 4 - Prob. 53PPCh. 4 - Prob. 54PPCh. 4 - Prob. 55PPCh. 4 - Prob. 56PPCh. 4 - Prob. 57PPCh. 4 - Prob. 58PPCh. 4 - Prob. 59PPCh. 4 - Prob. 69ACPCh. 4 - Prob. 73IPCh. 4 - Prob. 76IP
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