Suppose that f is defined everywhere and x = 2 , 3 , 5 , 7 are critical points for f . If f ′ x is positive on the intervals − ∞ , 2 and 5 , 7 , and if f ′ x is negative on the intervals 2 , 3 , 3 , 5 , and 7 , + ∞ , then f has relative maxima at x = _______ and f has relative minima at x = ________ .
Suppose that f is defined everywhere and x = 2 , 3 , 5 , 7 are critical points for f . If f ′ x is positive on the intervals − ∞ , 2 and 5 , 7 , and if f ′ x is negative on the intervals 2 , 3 , 3 , 5 , and 7 , + ∞ , then f has relative maxima at x = _______ and f has relative minima at x = ________ .
Suppose that
f
is defined everywhere and
x
=
2
,
3
,
5
,
7
are critical points for
f
. If
f
′
x
is positive on the intervals
−
∞
,
2
and
5
,
7
,
and if
f
′
x
is negative on the intervals
2
,
3
,
3
,
5
, and
7
,
+
∞
,
then
f
has relative maxima at
x
=
_______
and
f
has relative minima at
x
=
________
.
Formula Formula A function f(x) attains a local maximum at x=a , if there exists a neighborhood (a−δ,a+δ) of a such that, f(x)<f(a), ∀ x∈(a−δ,a+δ),x≠a f(x)−f(a)<0, ∀ x∈(a−δ,a+δ),x≠a In such case, f(a) attains a local maximum value f(x) at x=a .
Given lim x-4 f (x) = 1,limx-49 (x) = 10, and lim→-4 h (x) = -7 use the limit properties
to find lim→-4
1
[2h (x) — h(x) + 7 f(x)] :
-
h(x)+7f(x)
3
O DNE
17. Suppose we know that the graph below is the graph of a solution to dy/dt = f(t).
(a) How much of the slope field can
you sketch from this information?
[Hint: Note that the differential
equation depends only on t.]
(b) What can you say about the solu-
tion with y(0) = 2? (For example,
can you sketch the graph of this so-
lution?)
y(0) = 1
y
AN
(b) Find the (instantaneous) rate of change of y at x = 5.
In the previous part, we found the average rate of change for several intervals of decreasing size starting at x = 5. The instantaneous rate of
change of fat x = 5 is the limit of the average rate of change over the interval [x, x + h] as h approaches 0. This is given by the derivative in the
following limit.
lim
h→0
-
f(x + h) − f(x)
h
The first step to find this limit is to compute f(x + h). Recall that this means replacing the input variable x with the expression x + h in the rule
defining f.
f(x + h) = (x + h)² - 5(x+ h)
=
2xh+h2_
x² + 2xh + h² 5✔
-
5
)x - 5h
Step 4
-
The second step for finding the derivative of fat x is to find the difference f(x + h) − f(x).
-
f(x + h) f(x) =
= (x²
x² + 2xh + h² -
])-
=
2x
+ h² - 5h
])x-5h) - (x² - 5x)
=
]) (2x + h - 5)
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