
Concept explainers
(a)
To determine: The reason for less knocking tendency of isooctane than n-heptane.
Interpretation: The reason for less knocking tendency of isooctane than n-heptane is to be stated.
Concept introduction: The
(b)
To determine: An equation that shows abstraction of a hydrogen atom from tert-butyl alcohol by alkyl free radical and explanation for working of tert-butyl alcohol as an antiknock additive for gasoline.
Interpretation: An equation that shows abstraction of a hydrogen atom from tert-butyl alcohol by alkyl free radical is to be written and explanation for working of tert-butyl alcohol as an antiknock additive for gasoline is to be stated.
Concept introduction: The chemical reaction which proceeds through the formation of radicals is known as chain reaction. It involves three steps, initiation, propagation and termination. Generally, the initiation step occurs in the presence of light. The quantum yield of chain reactions is very high.
(c)
To determine: The explanation for high octane value of toluene and an equation that shows toluene react with an alkyl free radical to give relatively stable radical.
Interpretation: The explanation for high octane value of toluene and an equation that shows toluene react with an alkyl free radical to give relatively stable radical is to be stated.
Concept introduction: The chemical reaction which proceeds through the formation of radicals is known as chain reaction. It involves three steps, initiation, propagation and termination. Generally, the initiation step occurs in the presence of light. The quantum yield of chain reactions is very high.

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Chapter 4 Solutions
ORGANIC CHEMISTRY
- A mixture of C7H12O2, C9H9OCl, biphenyl and acetone was put together in a gas chromatography tube. Please decide from the GC resutls which correspond to the peak for C7,C9 and biphenyl and explain the reasoning based on GC results. Eliminate unnecessary peaks from Gas Chromatography results.arrow_forwardIs the molecule chiral, meso, or achiral? CI .CH3 H₂C CIarrow_forwardPLEASE HELP ! URGENT!arrow_forward
- Identify priority of the substituents: CH3arrow_forwardHow many chiral carbons are in the molecule? OH F CI Brarrow_forwardA mixture of three compounds Phen-A, Acet-B and Rin-C was analyzed using TLC with 1:9 ethanol: hexane as the mobile phase. The TLC plate showed three spots of R, 0.1 and 0.2 and 0.3. Which of the three compounds (Phen-A; Acet-B or Rin-C) would have the highest (Blank 1), middle (Blank 2) and lowest (Blank 3) spot respectively? 0 CH: 0 CH, 0 H.C OH H.CN OH Acet-B Rin-C phen-A A A <arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning

