2nd Edition

ISBN: 9781264692620

Author: Miller

Publisher: MCG CUSTOM

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Question

Chapter 4.1, Problem 75PE

(a)

To determine

The value of f−1(32) for the selected values of x for the table defines Y1=f(x) as one to one function of x.

X Y6 14−2 −100.5 −2.512 324.5 9.5−8 −2810 26

(b)

To determine

The value of f−1(−2.5) for the selected values of x for the table defines Y1=f(x) as one to one function of x.

X Y6 14−2 −100.5 −2.512 324.5 9.5−8 −2810 26

(c)

To determine

The value of f−1(26) for the selected values of x for the table defines Y1=f(x) as one to one function of x.

X Y6 14−2 −100.5 −2.512 324.5 9.5−8 −2810 26

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Chapter 4.1, Problem 74PE

Chapter 4.1, Problem 76PE

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Chapter 4 Solutions

COLLEGE ALGEBRA CUSTOM -ALEKS ACCESS

Ch. 4.1 - Skill Practice Determine whether the function is...Ch. 4.1 - Skill Practice 2. Use the horizontal line test to...Ch. 4.1 - Prob. 3SP Ch. 4.1 - Prob. 4SP Ch. 4.1 - Skill Practice 5. Write an equation for the...Ch. 4.1 - Prob. 6SP Ch. 4.1 - Prob. 7SP Ch. 4.1 - Prob. 8SP Ch. 4.1 - Concept Connections Given the function...Ch. 4.1 - 2. The graph of a function and its inverse are...

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The value of f − 1 ( 32 ) for the selected values of x for the table defines Y 1 = f ( x ) as one to one function of x . X Y 6 14 − 2 − 10 0.5 − 2.5 12 32 4.5 9.5 − 8 − 28 10 26

Solution Summary: The author explains that the value of f-1(32) for the selected values of x is the inverse where variable value interchanges.

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The value of f−1(32) for the selected values of x for the table defines Y1=f(x) as one to one function of x.

X Y6 14−2 −100.5 −2.512 324.5 9.5−8 −2810 26

The value of f−1(−2.5) for the selected values of x for the table defines Y1=f(x) as one to one function of x.

X Y6 14−2 −100.5 −2.512 324.5 9.5−8 −2810 26

The value of f−1(26) for the selected values of x for the table defines Y1=f(x) as one to one function of x.

X Y6 14−2 −100.5 −2.512 324.5 9.5−8 −2810 26

Want to see the full answer?

Chapter 4 Solutions

The value of f − 1 ( 32 ) for the selected values of x for the table defines Y 1 = f ( x ) as one to one function of x . X Y 6 14 − 2 − 10 0.5 − 2.5 12 32 4.5 9.5 − 8 − 28 10 26

Solution Summary: The author explains that the value of f-1(32) for the selected values of x is the inverse where variable value interchanges.

Videos

The value of f−1(32) for the selected values of x for the table defines Y1=f(x) as one to one function of x. X Y6 14−2 −100.5 −2.512 324.5 9.5−8 −2810 26

The value of f−1(−2.5) for the selected values of x for the table defines Y1=f(x) as one to one function of x. X Y6 14−2 −100.5 −2.512 324.5 9.5−8 −2810 26

The value of f−1(26) for the selected values of x for the table defines Y1=f(x) as one to one function of x. X Y6 14−2 −100.5 −2.512 324.5 9.5−8 −2810 26

Want to see the full answer?

Chapter 4 Solutions

The value of f−1(32) for the selected values of x for the table defines Y1=f(x) as one to one function of x.

X Y6 14−2 −100.5 −2.512 324.5 9.5−8 −2810 26

The value of f−1(−2.5) for the selected values of x for the table defines Y1=f(x) as one to one function of x.

X Y6 14−2 −100.5 −2.512 324.5 9.5−8 −2810 26

The value of f−1(26) for the selected values of x for the table defines Y1=f(x) as one to one function of x.

X Y6 14−2 −100.5 −2.512 324.5 9.5−8 −2810 26