Explanation Given information: f ( x ) = x e a x has a critical point at x = 3. Definition used: For any function f , a point p in the domain of f where f ' ( p ) = 0 or f ' ( p ) is undefined is called a critical point of the function. Calculation: f ( x ) = x e a x (Given) Differentiating with respect to ‘x’, we get f ' ( x ) = e a x + a x e a x = e a x ( 1 + a x ) f ( x )

Applied Calculus, 6e WileyPLUS + Loose-leaf

6th Edition

ISBN: 9781119408901

Author: Deborah Hughes-Hallett, Andrew M. Gleason, Patti Frazer Lock, Daniel E. Flath

Publisher: Wiley (WileyPLUS Products)

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Question

Chapter 4.1, Problem 50P

To determine

To find:

The value of a so that f(x)=xeax has a critical point at x=3.

Expert Solution & Answer

Chapter 4 Solutions

Applied Calculus, 6e WileyPLUS + Loose-leaf

Ch. 4.1 - Prob. 1P Ch. 4.1 - Prob. 2P Ch. 4.1 - Prob. 3P Ch. 4.1 - Prob. 4P Ch. 4.1 - Prob. 5P Ch. 4.1 - Prob. 6P Ch. 4.1 - Prob. 7P Ch. 4.1 - Prob. 8P Ch. 4.1 - Prob. 9P Ch. 4.1 - Prob. 10P

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The value of a so that f ( x ) = x e a x has a critical point at x = 3.

Solution Summary: The author explains that the value of a is f(x)=xeax, which is critical to the function.

Concept explainers

Videos

To find:

The value of a so that f(x)=xeax has a critical point at x=3.

Chapter 4 Solutions

The value of a so that f ( x ) = x e a x has a critical point at x = 3.

Solution Summary: The author explains that the value of a is f(x)=xeax, which is critical to the function.

Concept explainers

Videos

To find: The value of a so that f(x)=xeax has a critical point at x=3.

Chapter 4 Solutions

To find:

The value of a so that f(x)=xeax has a critical point at x=3.