Electric Motor Control
10th Edition
ISBN: 9781133702818
Author: Herman
Publisher: CENGAGE L
expand_more
expand_more
format_list_bulleted
Question
Chapter 40, Problem 9SQ
To determine
Explain the reason for the operation of field contacts (F) overlapped in Figure 40-1.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Cable A
Cable A is a coaxial cable of constant cross section. The metal
regions are shaded in grey and are made of copper. The solid central
wire has radius a = 5mm, the outer tube inner radius b = 20mm and
thickness t = 5mm. The dielectric spacer is Teflon, of relative
permittivity &r = 2.1 and breakdown strength 350kV/cm. A potential
difference of 1kV is applied across the conductors, with centre
conductor positive and outer conductor earthed.
Before undertaking any COMSOL simulations we'll first perform some theoretical analysis
of Cable A based on the EN2076 lectures, to make sense of the simulations. Calculate the
radial electric field of cable A at radial positions r b. Also calculate the
maximum operating voltage of cable A, assuming a safety margin of ×2, and indicate where
on the cable's cross section dielectric breakdown is most likely to occur.
: For the gravity concrete dam shown in the figure, the following data are available:
The factor of safety against sliding (F.S sliding)=1.2
Unit weight of concrete (Yconc)=24 KN/m³
- Neglect( Wave pressure, silt pressure, ice force and earth quake force)
μ=0.65, (Ywater) = 9.81 KN/m³
Find factor of safety against overturning (F.S overturning)
6m3
80m
Sm
I need help checking if its correct
-E1 + VR1 + VR4 – E2 + VR3 = 0 -------> Loop 1 (a)
R1(I1) + R4(I1 – I2) + R3(I1) = E1 + E2 ------> Loop 1 (b)
R1(I1) + R4(I1) - R4(I2) + R3(I1) = E1 + E2 ------> Loop 1 (c)
(R1 + R3 + R4) (I1) - R4(I2) = E1 + E2 ------> Loop 1 (d)
Now that we have loop 1 equation will procced on finding the equation of I2 current loop. However, a reminder that because we are going in a clockwise direction, it goes against the direction of the current. As such we will get an equation for the matrix that will be:
E2 – VR4 – VR2 + E3 = 0 ------> Loop 2 (a)
-R4(I2 – I1) -R2(I2) = -E2 – E3 ------> Loop 2 (b)
-R4(I2) + R4(I1) - R2(I2) = -E2 – E3 -----> Loop 2 (c)
R4(I1) – (R4 + R2)(I2) = -E2 – E3 -----> Loop 2 (d)
These two equations will be implemented to the matrix formula I = inv(A) * b
R11 R12
(R1 + R3 + R4)
-R4
-R4
R4 + R2
Chapter 40 Solutions
Electric Motor Control
Ch. 40 - What are the two basic functions of synchronous...Ch. 40 - Prob. 2SQCh. 40 - If all of the control circuits are ACand DC is not...Ch. 40 - When the rotor and stator fields lock into step,...Ch. 40 - Prob. 5SQCh. 40 - Prob. 6SQCh. 40 - In Figure 402, approximately what is the...Ch. 40 - Why are the AC ammeter and DC meter necessary in...Ch. 40 - Prob. 9SQ
Knowledge Booster
Similar questions
- 10.2 For each of the following groups of sources, determineif the three sources constitute a balanced source, and if it is,determine if it has a positive or negative phase sequence.(a) va(t) = 169.7cos(377t +15◦) Vvb(t) = 169.7cos(377t −105◦) Vvc(t) = 169.7sin(377t −135◦) V(b) va(t) = 311cos(wt −12◦) Vvb(t) = 311cos(wt +108◦) Vvc(t) = 311cos(wt +228◦) V(c) V1 = 140 −140◦ VV2 = 114 −20◦ VV3 = 124 100◦ Varrow_forwardApply single-phase equivalency to determine the linecurrents in the Y-D network shown in Fig. P10.13. The loadimpedances are Zab = Zbc = Zca = (25+ j5) Warrow_forward10.8 In the network of Fig. P10.8, Za = Zb = Zc = (25+ j5) W.Determine the line currents.arrow_forward
- Using D flip-flops, design a synchronous counter. The counter counts in the sequence 1,3,5,7, 1,7,5,3,1,3,5,7,.... when its enable input x is equal to 1; otherwise, the counter count 0. Present state Next state x=0 Next state x=1 Output SO 52 S1 1 S1 54 53 3 52 53 S2 56 51 0 $5 5 54 S4 53 0 55 58 57 7 56 56 55 0 57 S10 59 1 58 58 S7 0 59 S12 S11 7 $10 $10 59 0 $11 $14 $13 5 $12 S12 $11 0 513 $15 SO 3 S14 $14 S13 0 $15 515 SO 0 Explain how to get the table step by step with drawing the state diagram and finding the Karnaugh map.arrow_forwardFor the oscillator resonance circuit shown in Fig. (5), derive the oscillation frequency Feedback and open-loop gains. L₁ 5 mH (a) ell +10 V R₁ ww R3 S C2 HH 1 με 1000 pF 100 pF R₂ 1 με RA H (b) +9 V R4 CA 470 pF C₁ R3 HH 1 με R₁ ww L₁ 000 1.5 mH R₂ ww Hi 1 μF L2 m 10 mHarrow_forwardExpert handwritten solution onlyarrow_forward
- B. For the oscillator circuit shown in frequency, feedback and open-loop gains. +10 V name the circuit, derive and find the oscillation P.Av +9 V -000 4₁ 5 mH w R₁ C₂ HH 1 με w 100 pF R₂ T R CA www. 470 pF w ww www 1000 pF HH 1μF C₁ HH 1μF Ra ww HI 4₁ 000 1.5 mH H 4 AF 000 10 mHarrow_forwardI want to check if the current that I have from using the mesh analysis is correct? I1 = 0.214mA I2 = -0.429mAarrow_forwardI want to find the current by using mesh analysis pleasearrow_forward
- I want to find the current by using mesh analysis pleasearrow_forwardR₁ W +10 V R3 +9 V C₂ R₁ CA C₁ 470 pF HH 1000 pF HH 1 με C4 1 μF 1 uF C₁ R₂ R4 100 pF Find Open-loop Jain L₁ 5 mH (a) Av=S,B={" H R₁₂ ✓ ww (b) R₁ L₁ 000 1.5 mH R₂ H 1 uF 12 10 mHarrow_forwardA) Calculate the efficiency of the test transformer at the resistive loads (X-25%, 50%, 75%, 100%, 125% full load). B) From part (A) draw the plot (efficiency Vs power output) of the transformer. C) Discuss the plot of part (B).arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Delmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage Learning
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Cengage Learning