BASIC BIOMECHANICS
BASIC BIOMECHANICS
8th Edition
ISBN: 9781259913877
Author: Hall
Publisher: RENT MCG
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Chapter 4, Problem 9AP

How much compression is exerted on the radius at the elbow joint when the biceps brachii, oriented at a 30° angle to the radius, exerts a tensile force of 200 N? (Answer: 173 N)

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ney: Load (L) = 5 kgs = Effort E = Fulcrum Weight of forearm = 1.8 kgs L = Load Biceps brachii muscle Distance of load from elbow joint = 35 cm %3D Effort (E) = contraction of biceps brachii Distance of center of mass of forearm from elbow = 17 cm Distance of tendon from elbow = 4 cm A) Draw the free-body diagram to represent the forces and moments Load (L) = weight of object plus forearm B) Write the torque equation for static equilibrium Fulcrum (F) = elbow joint
< The three main forces that act on the patella are shown on the diagram of the knee joint below. These forces are the quadriceps muscle force (FQ), the patella ligament force (FPL), and the patellofemoral joint reaction force (FPF). The angles a and ẞ are with respect to a line that is perpendicular to FPF. Assuming a = 15°, ẞ = 20°, and FQ = 3725 N, use equations for static equilibrium to calculate (a) FPL, and (b) FPF. (Hint: To solve this problem consider using a coordinate system that is aligned with the principal axes of the patella instead of the usual vertical and horizontal axes). (c) Many people assume FQ and FPL are always equal in magnitude but this is only true under certain circumstances. Under what conditions are FQ and FPL equal in magnitude? Fo FPF FP B GriffithUNIVERSITY Queensland Australia
With the shoulder flexed at 30°, the moment arm of the deltoid muscle is 2.0 cm. Solve for the force exerted by the deltoid muscle at the glenohumeral joint give the following assumptions: The deltoid is the only active muscle at the glenohumeral joint The weight of the humerus is 48 N. The center of gravity of the humerus is located 30 cm from the shoulder center of rotation STATIC EQUILIBRIUM EQUATIONS CONSIDERING ONLY THE DELTOID MUSCLE Fo MA = 18 Cn COR B=55". 0-30° RaF 30 cm FG = 24 N
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