To determine Calculate the voltage v o and the current i o for the given circuit of Figure P4.94 by using superposition principle. Explanation Given data: Refer to Figure P4.94 in the textbook, The voltage source is 10 V and the current source is 2 A . Calculation: In the given circuit, since there are two sources, let v o = v o 1 + v o 2 and i o = i o 1 + i o 2 Where the voltages v o 1 and v o 2 , the currents i o 1 and i o 2 are contributions due to the voltage source 10 V and the current source 2 A . When 10 V voltage source is acting alone: In Figure 1, the current source 2A is kept open when 10 V source is active. In Figure 1, the current i o 1 is calculated as follows. i o 1 = 10 V 45 Ω + ( 5 Ω + 5 Ω ) | | 10 Ω = 10 V 45 Ω + 10 Ω | | 10 Ω = 10 V 45 Ω + 10 Ω × 10 Ω 10 Ω + 10 Ω = 0.2 A { ∵ 1 A = 1 V 1 Ω } In Figure 1, the voltage v o 1 is calculated by using voltage division rule as follows. v o 1 = ( − 10 V ) ( 20 Ω 60 Ω + 20 Ω ) = − ( 10 V ) ( 2 8 ) = − 2.5 V When 2 A current source is acting alone: In Figure 2, the voltage source is kept as short circuited when 2 A source is active. Apply Kirchhoff’s current law at node 2 in Figure 2. v 2 5 + v 2 − v 3 5 = − 2 v 2 5 + v 2 5 − v 3 5 = − 2 ( 1 5 + 1 5 ) v 2 − v 3 5 = − 2 0.4 v 2 − 0.2 v 3 = − 2 (1) Apply Kirchhoff’s current law at node 3 in Figure 2. v 3 10 + v 3 − v 2 5 + v 3 45 = 0 − v 2 5 + v 3 10 + v 3 5 + v 3 45 = 0 − 0

10th Edition

ISBN: 8220100801792

Author: Riedel

Publisher: YUZU

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Chapter 4, Problem 94P

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Calculate the voltage vo and the current io for the given circuit of Figure P4.94 by using superposition principle.

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Chapter 4, Problem 93P

Chapter 4, Problem 95P

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