The combination of 2 s orbitals to form σ bonding and σ antibonding molecular orbitals is to be shown. The overlap of 2 p orbitals to form σ bonding, π bonding, π antibonding and σ antibonding molecular orbitals is to be shown. Concept introduction: The s orbital is spherical in shape and p orbital is dumble shape. The molecular orbital resembles with atomic orbital as molecular orbital holds two electrons with opposite spins. The square of the molecular orbital wave function tells the probability of finding electrons. Sigma bonds are formed by head-on overlapping of atomic orbitals. The s orbitals are always forms sigma bond only. Pi bonds are formed by side-wise overlapping of atomic orbitals. To determine: The representation that show the combination of 2 s orbitals to form σ bonding, σ antibonding molecular orbitals and 2 p orbitals to form σ bonding, π bonding, π antibonding and σ antibonding molecular orbitals.
The combination of 2 s orbitals to form σ bonding and σ antibonding molecular orbitals is to be shown. The overlap of 2 p orbitals to form σ bonding, π bonding, π antibonding and σ antibonding molecular orbitals is to be shown. Concept introduction: The s orbital is spherical in shape and p orbital is dumble shape. The molecular orbital resembles with atomic orbital as molecular orbital holds two electrons with opposite spins. The square of the molecular orbital wave function tells the probability of finding electrons. Sigma bonds are formed by head-on overlapping of atomic orbitals. The s orbitals are always forms sigma bond only. Pi bonds are formed by side-wise overlapping of atomic orbitals. To determine: The representation that show the combination of 2 s orbitals to form σ bonding, σ antibonding molecular orbitals and 2 p orbitals to form σ bonding, π bonding, π antibonding and σ antibonding molecular orbitals.
Solution Summary: The author explains that the combination of 2s orbitals to form sigma bonding is shown.
Interpretation: The combination of
2s orbitals to form
σ bonding and
σ antibonding molecular orbitals is to be shown. The overlap of
2p orbitals to form
σ bonding,
π bonding,
π antibonding and
σ antibonding molecular orbitals is to be shown.
Concept introduction: The
s orbital is spherical in shape and
p orbital is dumble shape.
The molecular orbital resembles with atomic orbital as molecular orbital holds two electrons with opposite spins. The square of the molecular orbital wave function tells the probability of finding electrons.
Sigma bonds are formed by head-on overlapping of atomic orbitals.
The
s orbitals are always forms sigma bond only.
Pi bonds are formed by side-wise overlapping of atomic orbitals.
To determine: The representation that show the combination of
2s orbitals to form
σ bonding,
σ antibonding molecular orbitals and
2p orbitals to form
σ bonding,
π bonding,
π antibonding and
σ antibonding molecular orbitals.
Learning Goal:
This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this:
35 Cl
17
In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is:
It is also correct to write symbols by leaving off the atomic number, as in the following form:
atomic number
mass number Symbol
35 Cl or
mass number Symbol
This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons
are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written.
Watch this video to review the format for written symbols.
In the following table each column…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
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