The reason for the use of gravity filtration instead of suction filtration to remove the suspended impurities and charcoal from a hot solution should be explained. Concept introduction: Gravity filtration is the process that is used to separate the solids from liquids based on the particle size with the help of gravity. This method is used when the filtrate is to be retained and the residue on the filter paper is discarded. It is a slow process and removes only large particles from the air. Suction filtration is a technique that is used to separate the mixtures of solids and liquids. This method is used when the solid is to be retained and the filtrate is discarded. It is much faster than gravity filtration.

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== Vid4Q2 Unanswered ☑ Provide IUPAC name of product in the reaction below A 3,4-dimethylcyclohexene B 1,2-dimethylcyclohexane C 1,2-dimethylcyclohexene D 3,4-dimethylcyclohexane H₂ Pd

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Chapter 4, Problem 6Q

Interpretation Introduction

Interpretation:

The reason for the use of gravity filtration instead of suction filtration to remove the suspended impurities and charcoal from a hot solution should be explained.

Concept introduction:

Gravity filtration is the process that is used to separate the solids from liquids based on the particle size with the help of gravity. This method is used when the filtrate is to be retained and the residue on the filter paper is discarded. It is a slow process and removes only large particles from the air.

Suction filtration is a technique that is used to separate the mixtures of solids and liquids. This method is used when the solid is to be retained and the filtrate is discarded. It is much faster than gravity filtration.

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== Vid4Q2 Unanswered ☑ Provide IUPAC name of product in the reaction below A 3,4-dimethylcyclohexene B 1,2-dimethylcyclohexane C 1,2-dimethylcyclohexene D 3,4-dimethylcyclohexane H₂ Pd

5. Use the MS data to answer the questions on the next page. 14.0 1.4 15.0 8.1 100- MS-IW-5644 26.0 2.8 27.0 6.7 28.0 1.8 29.0 80 4.4 38.0 1.0 39.0 1.5 41.0 1.2 42.0 11.2 43.0 100.0 44.0 4.3 79.0 1.9 80.0 2.6 Relative Intensity 40 81.0 1.9 82.0 2.5 93.0 8.7 20- 95.0 8.2 121.0 2.0 123.0 2.0 136.0 11.8 0 138.0 11.5 20 40 8. 60 a. Br - 0 80 100 120 140 160 180 200 220 m/z Identify the m/z of the base peak and molecular ion. 2 b. Draw structures for each of the following fragments (include electrons and charges): 43.0, 93.0, 95.0, 136.0, and 138.0 m/z. C. Draw a reasonable a-fragmentation mechanism for the fragmentation of the molecular ion to fragment 43.0 m/z. Be sure to include all electrons and formal charges. 6. Using the values provided in Appendix E of your lab manual, calculate the monoisotopic mass for the pyridinium ion (CsH6N) and show your work.

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