Concept explainers
(a)
Interpretation:
The enthalpy change for breaking of all bonds present in all reactants of given reaction has to be calculated.
(a)
Answer to Problem 62QRT
The enthalpy change value for breaking of bonds for bromine reaction is
Explanation of Solution
The reactions of molecular hydrogen with bromine and iodine are as follows,
Above both reactions, involves breaking of one
(b)
Interpretation:
The enthalpy change for forming of all bonds present in all products of given reaction has to be calculated.
Concept Introduction:
Refer part (a).
(b)
Answer to Problem 62QRT
The enthalpy change value for forming of bonds in bromine reaction is
Explanation of Solution
The reaction of molecular hydrogen with fluorine and chlorine is as follows,
Above both reactions involve formation of 2 hydrogen-halogen bonds. The
(c)
Interpretation:
The enthalpy change given reaction has to be calculated.
Concept Introduction:
The enthalpy change in a system
Where,
(c)
Answer to Problem 62QRT
The enthalpy change value for bromine reaction is
Explanation of Solution
The reactions of molecular hydrogen with bromine and iodine are as follows,
The enthalpy change value for each reaction is determined by considering the formula,
(d)
Interpretation:
From the two given reactions, the exothermic reaction has to be identified.
Concept Introduction:
Enthalpy is the amount energy absorbed or released in a process. Under constant pressure conditions the enthalpy change will be equal to molar q.
Exothermic reaction: Exothermic reactions are those in which evolution of heat takes place during any
Endothermic reaction: Endothermic reactions are those in which heat is absorbed during any chemical reaction. In such type of reactions, external energy is needed.
(d)
Answer to Problem 62QRT
The reaction between molecular hydrogen and bromine is more exothermic than the other one.
Explanation of Solution
The reaction of molecular hydrogen with bromine is more exothermic since
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Chapter 4 Solutions
OWLV2 FOR MOORE/STANITSKI'S CHEMISTRY:
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