Circuit: The circuit is known as the combination of gates that is used to achieve a difficult logical operation. It has two general categories; they are: Combinational circuit Sequential circuit

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Answer 1

Question

Chapter 4, Problem 60E

Program Plan Intro

Circuit:

The circuit is known as the combination of gates that is used to achieve a difficult logical operation.

It has two general categories; they are:

Combinational circuit

Sequential circuit

Expert Solution & Answer

Explanation of Solution

Given circuit diagram:

Computer Science Illuminated, Chapter 4, Problem 60E

Behavior of the circuit:

From the circuit diagram:
- First, the input A is passed to NOT gate to perform the inverse of the A and produces the output as A¯.
- Next, the input A and input B is passed in the AND gate to perform the product of A and B, to produce the output as A⋅B.
- Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
  - Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
  - That is, “A¯” and “A⋅B” are passed as the input for XOR gate and produce as the output A¯⊕(A⋅B).

Truth table for the given circuit diagram:

Step 1:

The inputs are A and B for the above circuit diagram:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0
0	1
1	0
1	1

Step 2:

When the inputs are A as 0 and B as 0:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1
1	0
1	1

First, the input A as 0 is passed to NOT gate to perform the inverse of the A and produces the output as 1⊕0=1 .
Next, the input A as 0 and input B as 0 is passed to the AND gate to perform the product of A and B and produce the output as s.
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “1” and “0” are passed as inputs to XOR gate and produces output as 1⊕0=1.

Step 3:

When the inputs are A as 0 and B as 1:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0
1	1

First, the input A as 0 is passed to NOT gate to perform the inverse of the A and produces the output as 0¯=1.
Next, the input A as 0 and input B as 1 is passed to the AND gate to perform the product of the A and B and produce the output as 0⋅1= .
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “1” and “0” are passed as input for XOR gate and produce output as 1⊕0=1.

Step 4:

When the inputs are A as 1 and B as 0:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0	0	0	0
1	1

First, the input A as 1 is passed to NOT gate to perform the inverse of A and produces the output as 1 ¯=0 .
Next, the input A as 1 and input B as 0 is passed in the AND gate to perform the product of the A and B and produce the output as 1⋅0=0.
Finally, the output of NOT gate and the output of AND gate is passed as the input to XOR gate.
- Note: when both the inputs of XOR gate are the same, the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “0” and “0” are passed as input for XOR gate and produce as the output 0⊕0=0.

Step 5:

When the inputs are A as 1 and B as 1:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0	0	0	0
1	1	0	1	1

First, the input A as 1 is passed to NOT gate to perform the inverse of the A and produces the output as 1 ¯=0.
Next, the input A and input B as 1 is passed in the AND gate to perform the product of the A and B and produce the output as 1⋅1=1.
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs of XOR gate are the same, the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “0” and “1” are passed as input for XOR gate and produce as the output 0⊕1=1.

Final truth table:

Therefore, truth table of the given circuit diagram is:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0	0	0	0
1	1	0	1	1

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Answer 2

Question

Chapter 4, Problem 60E

Program Plan Intro

Circuit:

The circuit is known as the combination of gates that is used to achieve a difficult logical operation.

It has two general categories; they are:

Combinational circuit

Sequential circuit

Expert Solution & Answer

Explanation of Solution

Given circuit diagram:

Computer Science Illuminated, Chapter 4, Problem 60E

Behavior of the circuit:

From the circuit diagram:
- First, the input A is passed to NOT gate to perform the inverse of the A and produces the output as A¯.
- Next, the input A and input B is passed in the AND gate to perform the product of A and B, to produce the output as A⋅B.
- Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
  - Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
  - That is, “A¯” and “A⋅B” are passed as the input for XOR gate and produce as the output A¯⊕(A⋅B).

Truth table for the given circuit diagram:

Step 1:

The inputs are A and B for the above circuit diagram:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0
0	1
1	0
1	1

Step 2:

When the inputs are A as 0 and B as 0:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1
1	0
1	1

First, the input A as 0 is passed to NOT gate to perform the inverse of the A and produces the output as 1⊕0=1 .
Next, the input A as 0 and input B as 0 is passed to the AND gate to perform the product of A and B and produce the output as s.
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “1” and “0” are passed as inputs to XOR gate and produces output as 1⊕0=1.

Step 3:

When the inputs are A as 0 and B as 1:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0
1	1

First, the input A as 0 is passed to NOT gate to perform the inverse of the A and produces the output as 0¯=1.
Next, the input A as 0 and input B as 1 is passed to the AND gate to perform the product of the A and B and produce the output as 0⋅1= .
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “1” and “0” are passed as input for XOR gate and produce output as 1⊕0=1.

Step 4:

When the inputs are A as 1 and B as 0:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0	0	0	0
1	1

First, the input A as 1 is passed to NOT gate to perform the inverse of A and produces the output as 1 ¯=0 .
Next, the input A as 1 and input B as 0 is passed in the AND gate to perform the product of the A and B and produce the output as 1⋅0=0.
Finally, the output of NOT gate and the output of AND gate is passed as the input to XOR gate.
- Note: when both the inputs of XOR gate are the same, the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “0” and “0” are passed as input for XOR gate and produce as the output 0⊕0=0.

Step 5:

When the inputs are A as 1 and B as 1:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0	0	0	0
1	1	0	1	1

First, the input A as 1 is passed to NOT gate to perform the inverse of the A and produces the output as 1 ¯=0.
Next, the input A and input B as 1 is passed in the AND gate to perform the product of the A and B and produce the output as 1⋅1=1.
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs of XOR gate are the same, the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “0” and “1” are passed as input for XOR gate and produce as the output 0⊕1=1.

Final truth table:

Therefore, truth table of the given circuit diagram is:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0	0	0	0
1	1	0	1	1

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Answer 3

Question

Chapter 4, Problem 60E

Program Plan Intro

Circuit:

The circuit is known as the combination of gates that is used to achieve a difficult logical operation.

It has two general categories; they are:

Combinational circuit

Sequential circuit

Expert Solution & Answer

Explanation of Solution

Given circuit diagram:

Computer Science Illuminated, Chapter 4, Problem 60E

Behavior of the circuit:

From the circuit diagram:
- First, the input A is passed to NOT gate to perform the inverse of the A and produces the output as A¯.
- Next, the input A and input B is passed in the AND gate to perform the product of A and B, to produce the output as A⋅B.
- Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
  - Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
  - That is, “A¯” and “A⋅B” are passed as the input for XOR gate and produce as the output A¯⊕(A⋅B).

Truth table for the given circuit diagram:

Step 1:

The inputs are A and B for the above circuit diagram:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0
0	1
1	0
1	1

Step 2:

When the inputs are A as 0 and B as 0:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1
1	0
1	1

First, the input A as 0 is passed to NOT gate to perform the inverse of the A and produces the output as 1⊕0=1 .
Next, the input A as 0 and input B as 0 is passed to the AND gate to perform the product of A and B and produce the output as s.
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “1” and “0” are passed as inputs to XOR gate and produces output as 1⊕0=1.

Step 3:

When the inputs are A as 0 and B as 1:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0
1	1

First, the input A as 0 is passed to NOT gate to perform the inverse of the A and produces the output as 0¯=1.
Next, the input A as 0 and input B as 1 is passed to the AND gate to perform the product of the A and B and produce the output as 0⋅1= .
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “1” and “0” are passed as input for XOR gate and produce output as 1⊕0=1.

Step 4:

When the inputs are A as 1 and B as 0:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0	0	0	0
1	1

First, the input A as 1 is passed to NOT gate to perform the inverse of A and produces the output as 1 ¯=0 .
Next, the input A as 1 and input B as 0 is passed in the AND gate to perform the product of the A and B and produce the output as 1⋅0=0.
Finally, the output of NOT gate and the output of AND gate is passed as the input to XOR gate.
- Note: when both the inputs of XOR gate are the same, the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “0” and “0” are passed as input for XOR gate and produce as the output 0⊕0=0.

Step 5:

When the inputs are A as 1 and B as 1:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0	0	0	0
1	1	0	1	1

First, the input A as 1 is passed to NOT gate to perform the inverse of the A and produces the output as 1 ¯=0.
Next, the input A and input B as 1 is passed in the AND gate to perform the product of the A and B and produce the output as 1⋅1=1.
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs of XOR gate are the same, the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “0” and “1” are passed as input for XOR gate and produce as the output 0⊕1=1.

Final truth table:

Therefore, truth table of the given circuit diagram is:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0	0	0	0
1	1	0	1	1

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Answer 4

Question

Chapter 4, Problem 60E

Program Plan Intro

Circuit:

The circuit is known as the combination of gates that is used to achieve a difficult logical operation.

It has two general categories; they are:

Combinational circuit

Sequential circuit

Expert Solution & Answer

Explanation of Solution

Given circuit diagram:

Computer Science Illuminated, Chapter 4, Problem 60E

Behavior of the circuit:

From the circuit diagram:
- First, the input A is passed to NOT gate to perform the inverse of the A and produces the output as A¯.
- Next, the input A and input B is passed in the AND gate to perform the product of A and B, to produce the output as A⋅B.
- Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
  - Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
  - That is, “A¯” and “A⋅B” are passed as the input for XOR gate and produce as the output A¯⊕(A⋅B).

Truth table for the given circuit diagram:

Step 1:

The inputs are A and B for the above circuit diagram:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0
0	1
1	0
1	1

Step 2:

When the inputs are A as 0 and B as 0:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1
1	0
1	1

First, the input A as 0 is passed to NOT gate to perform the inverse of the A and produces the output as 1⊕0=1 .
Next, the input A as 0 and input B as 0 is passed to the AND gate to perform the product of A and B and produce the output as s.
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “1” and “0” are passed as inputs to XOR gate and produces output as 1⊕0=1.

Step 3:

When the inputs are A as 0 and B as 1:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0
1	1

First, the input A as 0 is passed to NOT gate to perform the inverse of the A and produces the output as 0¯=1.
Next, the input A as 0 and input B as 1 is passed to the AND gate to perform the product of the A and B and produce the output as 0⋅1= .
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “1” and “0” are passed as input for XOR gate and produce output as 1⊕0=1.

Step 4:

When the inputs are A as 1 and B as 0:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0	0	0	0
1	1

First, the input A as 1 is passed to NOT gate to perform the inverse of A and produces the output as 1 ¯=0 .
Next, the input A as 1 and input B as 0 is passed in the AND gate to perform the product of the A and B and produce the output as 1⋅0=0.
Finally, the output of NOT gate and the output of AND gate is passed as the input to XOR gate.
- Note: when both the inputs of XOR gate are the same, the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “0” and “0” are passed as input for XOR gate and produce as the output 0⊕0=0.

Step 5:

When the inputs are A as 1 and B as 1:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0	0	0	0
1	1	0	1	1

First, the input A as 1 is passed to NOT gate to perform the inverse of the A and produces the output as 1 ¯=0.
Next, the input A and input B as 1 is passed in the AND gate to perform the product of the A and B and produce the output as 1⋅1=1.
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs of XOR gate are the same, the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “0” and “1” are passed as input for XOR gate and produce as the output 0⊕1=1.

Final truth table:

Therefore, truth table of the given circuit diagram is:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0	0	0	0
1	1	0	1	1

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Answer 5

Chapter 4, Problem 60E

Program Plan Intro

Circuit:

The circuit is known as the combination of gates that is used to achieve a difficult logical operation.

It has two general categories; they are:

Combinational circuit

Sequential circuit

Expert Solution & Answer

Explanation of Solution

Given circuit diagram:

Computer Science Illuminated, Chapter 4, Problem 60E

Behavior of the circuit:

From the circuit diagram:
- First, the input A is passed to NOT gate to perform the inverse of the A and produces the output as A¯.
- Next, the input A and input B is passed in the AND gate to perform the product of A and B, to produce the output as A⋅B.
- Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
  - Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
  - That is, “A¯” and “A⋅B” are passed as the input for XOR gate and produce as the output A¯⊕(A⋅B).

Truth table for the given circuit diagram:

Step 1:

The inputs are A and B for the above circuit diagram:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0
0	1
1	0
1	1

Step 2:

When the inputs are A as 0 and B as 0:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1
1	0
1	1

First, the input A as 0 is passed to NOT gate to perform the inverse of the A and produces the output as 1⊕0=1 .
Next, the input A as 0 and input B as 0 is passed to the AND gate to perform the product of A and B and produce the output as s.
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “1” and “0” are passed as inputs to XOR gate and produces output as 1⊕0=1.

Step 3:

When the inputs are A as 0 and B as 1:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0
1	1

First, the input A as 0 is passed to NOT gate to perform the inverse of the A and produces the output as 0¯=1.
Next, the input A as 0 and input B as 1 is passed to the AND gate to perform the product of the A and B and produce the output as 0⋅1= .
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “1” and “0” are passed as input for XOR gate and produce output as 1⊕0=1.

Step 4:

When the inputs are A as 1 and B as 0:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0	0	0	0
1	1

First, the input A as 1 is passed to NOT gate to perform the inverse of A and produces the output as 1 ¯=0 .
Next, the input A as 1 and input B as 0 is passed in the AND gate to perform the product of the A and B and produce the output as 1⋅0=0.
Finally, the output of NOT gate and the output of AND gate is passed as the input to XOR gate.
- Note: when both the inputs of XOR gate are the same, the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “0” and “0” are passed as input for XOR gate and produce as the output 0⊕0=0.

Step 5:

When the inputs are A as 1 and B as 1:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0	0	0	0
1	1	0	1	1

First, the input A as 1 is passed to NOT gate to perform the inverse of the A and produces the output as 1 ¯=0.
Next, the input A and input B as 1 is passed in the AND gate to perform the product of the A and B and produce the output as 1⋅1=1.
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs of XOR gate are the same, the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “0” and “1” are passed as input for XOR gate and produce as the output 0⊕1=1.

Final truth table:

Therefore, truth table of the given circuit diagram is:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0	0	0	0
1	1	0	1	1

Answer 6

Chapter 4, Problem 60E

Program Plan Intro

Circuit:

The circuit is known as the combination of gates that is used to achieve a difficult logical operation.

It has two general categories; they are:

Combinational circuit

Sequential circuit

Expert Solution & Answer

Explanation of Solution

Given circuit diagram:

Computer Science Illuminated, Chapter 4, Problem 60E

Behavior of the circuit:

From the circuit diagram:
- First, the input A is passed to NOT gate to perform the inverse of the A and produces the output as A¯.
- Next, the input A and input B is passed in the AND gate to perform the product of A and B, to produce the output as A⋅B.
- Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
  - Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
  - That is, “A¯” and “A⋅B” are passed as the input for XOR gate and produce as the output A¯⊕(A⋅B).

Truth table for the given circuit diagram:

Step 1:

The inputs are A and B for the above circuit diagram:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0
0	1
1	0
1	1

Step 2:

When the inputs are A as 0 and B as 0:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1
1	0
1	1

First, the input A as 0 is passed to NOT gate to perform the inverse of the A and produces the output as 1⊕0=1 .
Next, the input A as 0 and input B as 0 is passed to the AND gate to perform the product of A and B and produce the output as s.
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “1” and “0” are passed as inputs to XOR gate and produces output as 1⊕0=1.

Step 3:

When the inputs are A as 0 and B as 1:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0
1	1

First, the input A as 0 is passed to NOT gate to perform the inverse of the A and produces the output as 0¯=1.
Next, the input A as 0 and input B as 1 is passed to the AND gate to perform the product of the A and B and produce the output as 0⋅1= .
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “1” and “0” are passed as input for XOR gate and produce output as 1⊕0=1.

Step 4:

When the inputs are A as 1 and B as 0:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0	0	0	0
1	1

First, the input A as 1 is passed to NOT gate to perform the inverse of A and produces the output as 1 ¯=0 .
Next, the input A as 1 and input B as 0 is passed in the AND gate to perform the product of the A and B and produce the output as 1⋅0=0.
Finally, the output of NOT gate and the output of AND gate is passed as the input to XOR gate.
- Note: when both the inputs of XOR gate are the same, the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “0” and “0” are passed as input for XOR gate and produce as the output 0⊕0=0.

Step 5:

When the inputs are A as 1 and B as 1:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0	0	0	0
1	1	0	1	1

First, the input A as 1 is passed to NOT gate to perform the inverse of the A and produces the output as 1 ¯=0.
Next, the input A and input B as 1 is passed in the AND gate to perform the product of the A and B and produce the output as 1⋅1=1.
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs of XOR gate are the same, the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “0” and “1” are passed as input for XOR gate and produce as the output 0⊕1=1.

Final truth table:

Therefore, truth table of the given circuit diagram is:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0	0	0	0
1	1	0	1	1

Answer 7

Chapter 4, Problem 60E

Program Plan Intro

Circuit:

The circuit is known as the combination of gates that is used to achieve a difficult logical operation.

It has two general categories; they are:

Combinational circuit

Sequential circuit

Answer 8

Expert Solution & Answer

Explanation of Solution

Given circuit diagram:

Computer Science Illuminated, Chapter 4, Problem 60E

Behavior of the circuit:

From the circuit diagram:
- First, the input A is passed to NOT gate to perform the inverse of the A and produces the output as A¯.
- Next, the input A and input B is passed in the AND gate to perform the product of A and B, to produce the output as A⋅B.
- Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
  - Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
  - That is, “A¯” and “A⋅B” are passed as the input for XOR gate and produce as the output A¯⊕(A⋅B).

Truth table for the given circuit diagram:

Step 1:

The inputs are A and B for the above circuit diagram:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0
0	1
1	0
1	1

Step 2:

When the inputs are A as 0 and B as 0:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1
1	0
1	1

First, the input A as 0 is passed to NOT gate to perform the inverse of the A and produces the output as 1⊕0=1 .
Next, the input A as 0 and input B as 0 is passed to the AND gate to perform the product of A and B and produce the output as s.
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “1” and “0” are passed as inputs to XOR gate and produces output as 1⊕0=1.

Step 3:

When the inputs are A as 0 and B as 1:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0
1	1

First, the input A as 0 is passed to NOT gate to perform the inverse of the A and produces the output as 0¯=1.
Next, the input A as 0 and input B as 1 is passed to the AND gate to perform the product of the A and B and produce the output as 0⋅1= .
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “1” and “0” are passed as input for XOR gate and produce output as 1⊕0=1.

Step 4:

When the inputs are A as 1 and B as 0:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0	0	0	0
1	1

First, the input A as 1 is passed to NOT gate to perform the inverse of A and produces the output as 1 ¯=0 .
Next, the input A as 1 and input B as 0 is passed in the AND gate to perform the product of the A and B and produce the output as 1⋅0=0.
Finally, the output of NOT gate and the output of AND gate is passed as the input to XOR gate.
- Note: when both the inputs of XOR gate are the same, the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “0” and “0” are passed as input for XOR gate and produce as the output 0⊕0=0.

Step 5:

When the inputs are A as 1 and B as 1:

A	B	A¯	A⋅B	A¯⊕(A⋅B)
0	0	1	0	1
0	1	1	0	1
1	0	0	0	0
1	1	0	1	1

First, the input A as 1 is passed to NOT gate to perform the inverse of the A and produces the output as 1 ¯=0.
Next, the input A and input B as 1 is passed in the AND gate to perform the product of the A and B and produce the output as 1⋅1=1.
Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
- Note: when both the inputs of XOR gate are the same, the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
- That is, “0” and “1” are passed as input for XOR gate and produce as the output 0⊕1=1.