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Concept explainers
In the chapter opening case study, we focus on the production of methane by archaea living in the rumens of domesticated ruminant animals. However, there are many other sources of methane besides livestock. These include wild ruminants, the anoxic soils of rice paddies, and deforestation. There is considerable interest in more precisely measuring the output of methane by all these sources, yet current methods have many drawbacks. Some are laborious; some have a high degree of variability; others can only be used in highly controlled environments. In 2011 a group of scientists reported their attempts to correlate methane production with the amount of archaeol in the feces of cattle. They also determined archaeol levels resulting from different feeding regimens. Archaeol is a glycerol diether that can be measured by chemical procedures such as gas chromatography. What assumption did the scientists make when they chose to measure archaeol? Why did they choose to measure a glycerol diether rather than a diglycerol tetraether in their study? Suggest one other application of this method to better understand methane release into the atmosphere.
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Chapter 4 Solutions
Prescott's Microbiology
- Identify the indicated tissue. (Tilia stem x.s.) parenchyma collenchyma sclerenchyma xylem phloem none of thesearrow_forwardIdentify the indicated structure. (Cucurbita stem l.s.) pit lenticel stomate tendril none of thesearrow_forwardIdentify the specific cell? (Zebrina leaf peel) vessel element sieve element companion cell tracheid guard cell subsidiary cell none of thesearrow_forward
- What type of cells flank the opening on either side? (leaf x.s.) vessel elements sieve elements companion cells tracheids guard cells none of thesearrow_forwardWhat specific cell is indicated. (Cucurbita stem I.s.) vessel element sieve element O companion cell tracheid guard cell none of thesearrow_forwardWhat specific cell is indicated? (Aristolochia stem x.s.) vessel element sieve element ○ companion cell O O O O O tracheid O guard cell none of thesearrow_forward
- Identify the tissue. parenchyma collenchyma sclerenchyma ○ xylem O phloem O none of thesearrow_forwardPlease answer q3arrow_forwardRespond to the following in a minimum of 175 words: How might CRISPR-Cas 9 be used in research or, eventually, therapeutically in patients? What are some potential ethical issues associated with using this technology? Do the advantages of using this technology outweigh the disadvantages (or vice versa)? Explain your position.arrow_forward
- You are studying the effect of directional selection on body height in three populations (graphs a, b, and c below). (a) What is the selection differential? Show your calculation. (2 pts) (b) Which population has the highest narrow sense heritability for height? Explain your answer. (2 pts) (c) If you examined the offspring in the next generation in each population, which population would have the highest mean height? Why? (2 pts) (a) Midoffspring height (average height of offspring) Short Short Short Short (c) Short (b) Short Tall Short Tall Short Short Tall Midparent height (average height of Mean of population = 65 inches Mean of breading parents = 70 inches Mean of population = 65 inches Mean of breading parents = 70 inches Mean of population = 65 inches Mean of breading parents = 70 inchesarrow_forwardP You are studying a population of 100 flowers that has two alleles at a locus for flower color, blue (B) and green (G). There are 15 individuals with the BB genotype, 70 individuals with the BG genotype, and 15 individuals with the GG genotype. (a) What are the allele frequencies of B and G in the starting population? Show your calculations. (2 pts) (b) Is this population in Hardy-Weinberg equilibrium? Show your calculations. (3 pts) 12pt v Paragraph BIU UA AV & VT2V f CO Varrow_forwardIn a natural population of outbreeding plants, the variance of the total number of seeds per plant is 16. From the natural population, 20 plants are taken into the laboratory and developed into separate true-breeding lines by self- fertilization-with selection for high, low, or medium number of seeds-for 10 generations. The average variance in the tenth generation in each of the 20 sets is about equal and averages 5.8 across all the sets. Estimate the broad-sense heritability for seed number in this population. (4 pts) 12pt v Paragraph BIUA V V T² v B ① O wordsarrow_forward
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