Energy diagram for conformational analysis of 2,2,3,3-tetramethylbutane should be sketched and also the energy difference between staggered and eclipsed conformations are needed to find out using table 4.6. Concept introduction: Conformational analysis is the study of energy verses different conformers . Conformers arise due to the free rotation of C − C bond. This rotation are measured by dihedral angle , it is the angle between two atoms attached to two different carbons of C − C rotation in Newman projection. Newman projection: Newman projection of molecule is one type of representations for the alkanes , where the projection visualization from one carbon to another carbon. In this Newman projection, front carbon which represented as dot is called proximal and the back carbon which represented as circle is called distal. The most and least energy occupied conformers are eclipsed and staggered , which are having a dihedral of ‘0’ and ‘60’ degree respectively. If the energy levels of different eclipsed conformers or staggered conformers are same then they are called degenerated . For eclipsed conformations, Torsional strain and steric interactions of atoms are the energizing factors. For staggered conformations, anti-interactions and gauche interactions of atoms are the energizing factors. Table 4.6 To sketch and find: the energy diagram for conformational analysis of 2,2,3,3-tetramethylbutane and energy difference between staggered and eclipsed conformations.

Question

Want to see the full answer?

Answer 1

Question

Chapter 4, Problem 55PP

Interpretation Introduction

Interpretation:

Energy diagram for conformational analysis of 2,2,3,3-tetramethylbutane should be sketched and also the energy difference between staggered and eclipsed conformations are needed to find out using table 4.6.

Concept introduction:

Conformational analysis is the study of energy verses different conformers. Conformers arise due to the free rotation of C−C bond. This rotation are measured by dihedral angle, it is the angle between two atoms attached to two different carbons of C−C rotation in Newman projection.

Newman projection: Newman projection of molecule is one type of representations for the alkanes, where the projection visualization from one carbon to another carbon. In this Newman projection, front carbon which represented as dot is called proximal and the back carbon which represented as circle is called distal.

The most and least energy occupied conformers are eclipsed and staggered, which are having a dihedral of ‘0’ and ‘60’ degree respectively.

If the energy levels of different eclipsed conformers or staggered conformers are same then they are called degenerated.

For eclipsed conformations, Torsional strain and steric interactions of atoms are the energizing factors.

For staggered conformations, anti-interactions and gauche interactions of atoms are the energizing factors.

Table 4.6

To sketch and find: the energy diagram for conformational analysis of 2,2,3,3-tetramethylbutane and energy difference between staggered and eclipsed conformations.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

my ccc edu - Search X Quick Access X D2L Homepage - Spring 2025 x N Netflix X Dimensional Analysis - A x+ pp.aktiv.com Q ☆ X Question 59 of 70 The volume of 1 unit of plasma is 200.0 mL If the recommended dosage for adult patients is 10.0 mL per kg of body mass, how many units are needed for a patient with a body mass of 80.0 kg ? 80.0 kg 10.0 DAL 1 units X X 4.00 units 1 1 Jeg 200.0 DAL L 1 units X 200.0 mL = 4.00 units ADD FACTOR *( ) DELETE ANSWER RESET D 200.0 2.00 1.60 × 10³ 80.0 4.00 0.0400 0.250 10.0 8.00 & mL mL/kg kg units/mL L unit Q Search delete prt sc 111 110 19

Identify the starting material in the following reaction. Click the "draw structure" button to launch the drawing utility. draw structure ... [1] 0 3 C10H18 [2] CH3SCH3 H

In an equilibrium mixture of the formation of ammonia from nitrogen and hydrogen, it is found that PNH3 = 0.147 atm, PN2 = 1.41 atm and Pн2 = 6.00 atm. Evaluate Kp and Kc at 500 °C. 2 NH3 (g) N2 (g) + 3 H₂ (g) K₂ = (PN2)(PH2)³ = (1.41) (6.00)³ = 1.41 x 104