Chapter 4, Problem 4D.1E

Interpretation Introduction

Interpretation:

The mass of sodium chloride, $NaCl$ which should be dissolved in enough water to make up $300c{m}^3$ of 1.00 $M$ $NaCl{}_{\left(aq\right)}$ has to be determined.

Concept introduction:

The number of moles of any substance can be determined using the equation

$\text{Number}\text{of}\text{mole}\text{=}\frac{\text{Given}\text{mass}\text{of}\text{the}\text{substance}}{\text{Molar}\text{mass}}$

The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mole (g/mol).

$Mass=Volume\times density$

Molarity: The concentration of the solutions is given by the term of molarity and it is given by ratio between numbers of moles of solute present in litter of solution.

  $\text{Molarity}\text{=}\frac{\text{No}\text{.mole}}{\text{volume}\text{(L)}}$

Mole: The mole of the solute is calculated by multiplication of concentration of solution and volume of the solution and it is,

  $\text{Mole}\text{=}\text{Concentration}\text{(M)×}\text{volume}\text{(L)}$