EBK APPLIED FLUID MECHANICS
7th Edition
ISBN: 8220100668340
Author: UNTENER
Publisher: PEARSON
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Chapter 4, Problem 4CAEA
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Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to find
Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of the
Procedure:
1- Cartesian system, 2D3D,
type of support
2- Free body diagram
3 - Find the support reactions
4- If you find a negative
number then flip the force
5- Find the internal force
3D
∑Fx=0
∑Fy=0
∑Fz=0
∑Mx=0
∑My=0
ΣMz=0
2D
ΣFx=0
ΣFy=0
ΣMz=0
5- Use method of section
and cut the element
where you want to find
the internal force and
keep either side of the
Chapter 4 Solutions
EBK APPLIED FLUID MECHANICS
Ch. 4 - figure 4.2 shows a vacuum tank with a flat...Ch. 4 - The flat left end of the tank shown in Fig. 4.21...Ch. 4 - An exhaust system for a room creates a partial...Ch. 4 - A piece of 14 -in Schedule 40 pipe is used as a...Ch. 4 - A pressure relief valve is designed so that the...Ch. 4 - A gas-powered cannon shoots projectiles by...Ch. 4 - The egress hatch of a manned spacecraft is...Ch. 4 - A tank containing liquid ammonia at 77F has a flat...Ch. 4 - The bottom of a laboratory vat has a hole in it to...Ch. 4 - A simple shower for remote locations is designed...
Ch. 4 - Calculate the total force on the bottom of the...Ch. 4 - If the length of the tank in Fig. 4.24 is 1.2m,...Ch. 4 - An observation port in a small submarine is...Ch. 4 - A rectangular gate is installed in a vertical wall...Ch. 4 - '4.15 A vat has a sloped side, as shown in Fig....Ch. 4 - The wall shown in Fig. 4.28 is 20 ft long, (a)...Ch. 4 - If the wall in Fig. 4.29 is 4m long, calculate the...Ch. 4 - Refer to Fig. 4.30Ch. 4 - Refer to Fig. 4.31Ch. 4 - Refer to Fig.4.32Ch. 4 - Refer to Fig 4.33Ch. 4 - Refer to Fig. 4.34Ch. 4 - Refer to Fig. 4.35 (?Ch. 4 - Swimming poo!WilierGlasswindow2 ft diameterFigure...Ch. 4 - 4.25 Refer to Fig 4.37Ch. 4 - Refer to Fig.4.38Ch. 4 - Refer to Fig.4.39Ch. 4 - Refer to Fig.4.40Ch. 4 - Refer to Fig 4.41Ch. 4 - figure 4.42i5 shows a gasoline tank filled into...Ch. 4 - If the tank in Fig. 4.42 is filled just to the...Ch. 4 - If the tank in Fig. 4.42 is only half full of...Ch. 4 - For the water tank shown in Fig. 4.43, compute the...Ch. 4 - For the water tank shown in Fig. 4.43, compute the...Ch. 4 - For the water tank shown in Fig. 4.43, compute the...Ch. 4 - For the orange-drink tank shown in Fig. 4.32,...Ch. 4 - For the orange-drink tank shown in Fig. 4.32,...Ch. 4 - For the oil tank shown in Fig. 4.35, compute the...Ch. 4 - For the oil tank shown in Fig. 4.35; compute the...Ch. 4 - figure 4.44 shows a rectangular gate holding water...Ch. 4 - figure 4.45 shows a gate hinged at its bottom and...Ch. 4 - figure 4.46 shows a tank of water with a circular...Ch. 4 - Repeat Problem 4.19(Fig. 4.31), except that the...Ch. 4 - Repeat Problem 4.22 (Fig. 4.32), except that the...Ch. 4 - Repeat Problem 4.26 (Fig. 4.38 ). except that the...Ch. 4 - Repeat Problem 4.28 (Fig. 4.40 ), except that the...Ch. 4 - Use Fig 4.47. The surface is 2.00m long.Ch. 4 - Use Fig.4.48. The surface is 2.50m long.Ch. 4 - Use Fig.4.49. The surface is 5.00 ft longCh. 4 - Use Fig.4.50. The surface is 4.50 ft long.Ch. 4 - Use Fig.4.51.The surface is 4.00 m long.Ch. 4 - Use Fig .4.52. The surface is 1.50m longCh. 4 - Use Fig. 4.53. The surface is 1.50m long.Ch. 4 - Use Fig. 4.54. The surface is 60 in longCh. 4 - Repeat Problem 4.47 using Fig. 4.47, except that...Ch. 4 - Repeat Problem 4.48 using Fig. 4.48, except that...Ch. 4 - The tank in Fig. 4.55 has a view port in the...Ch. 4 - Insulated concrete forms (ICFs) are becoming more...Ch. 4 - Lacks are installed in rivers to allow boats to...Ch. 4 - When a dam is installed in a river that has...Ch. 4 - A wealthy eccentric is interested in having an...Ch. 4 - A pneumatic cylinder like the one shown in Fig....Ch. 4 - Determine the magnitude and the location of the...Ch. 4 - For the hinged gate shown in Fig. 4.61, determine...Ch. 4 - Prob. 4.65PPCh. 4 - Write a program to solve Problem 4.41 with any...Ch. 4 - Write a program to solve Problem 4.42 (Fig. 4.46)...Ch. 4 - Write a program to solve curved surface problems...Ch. 4 - For Program 1, cause the depth h to vary over some...
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- Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of thearrow_forwardProcedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forwardProcedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forward
- For each system below with transfer function G(s), plot the pole(s) on the s-plane. and indicate whether the system is: (a) "stable" (i.e., a bounded input will always result in a bounded output), (b) "marginally stable," or (c) "unstable" Sketch a rough graph of the time response to a step input. 8 a) G(s) = 5-5 8 b) G(s) = c) G(s) = = s+5 3s + 8 s² - 2s +2 3s +8 d) G(s): = s²+2s+2 3s+8 e) G(s): = s² +9 f) G(s): 8 00 == Sarrow_forwardPlease answer the following question. Include all work and plase explain. Graphs are provided below. "Consider the Mg (Magnesium) - Ni (Nickel) phase diagram shown below. This phase diagram contains two eutectic reactions and two intermediate phases (Mg2Ni and MgNi2). At a temperature of 505oC, determine what the composition of an alloy would need to be to contain a mass fraction of 0.20 Mg and 0.80 Mg2Ni."arrow_forwardThe triangular plate, having a 90∘∘ angle at AA, supports the load PP = 370 lblb as shown in (Figure 1).arrow_forward
- Design a 4-bar linkage to carry the body in Figure 1 through the two positions P1 and P2 at the angles shown in the figure. Use analytical synthesis with the free choice values z = 1.075, q= 210°, ß2 = −27° for left side and s = 1.24, y= 74°, ½ = − 40° for right side. φ 1.236 P2 147.5° 210° 2.138 P1 Figure 1 Xarrow_forwardDesign a 4-bar linkage to carry the body in Figure 1 through the two positions P1 and P2 at the angles shown in the figure. Use analytical synthesis with the free choice values z = 1.075, q= 210°, B₂ = −27° for left side and s = 1.24, y= 74°, ½ = − 40° for right side. 1.236 P2 147.5° 210° P1 Figure 1 2.138 Xarrow_forwardcan you explain how in a coordinate frame transformation: v = {v_n}^T {n-hat} and then it was found that {n-hat} = [C]^T {b-hat} so v_n = {v_n}^T [C]^T {b-hat}, how does that equation go from that to this --> v_n = [C]^T v_barrow_forward
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