A fish swimming in a horizontal plane has velocity v = (4.00 î + 1.00 j) m/s at a point in the ocean where the position relative to a certain rock is T = (10.0 î – 4.00 j) m . After the fish swims with constant acceleration for 20.0 s, its velocity is v = (20.0 î – 5.00 j) m/s . 1. What are the components of the acceleration of the fish? 2. What is the direction of its acceleration with respect to unit vector î ? 3. If the fish maintains constant acceleration, where is it at t = 25.0 s and in what direction is it moving?

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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A fish swimming in a horizontal plane has velocity v = (4.00 î + 1.00 j) m/s at a point in the ocean where
the position relative to a certain rock is ï = (10.0 î – 4.00 j) m . After the fish swims with constant acceleration
for 20.0 s, its velocity is v = (20.0 î – 5.00 j) m/s .
1. What are the components of the acceleration of the fish?
2. What is the direction of its acceleration with respect to unit vector î ?
3. If the fish maintains constant acceleration, where is it at t = 25.0 s and in what direction is it moving?
Transcribed Image Text:A fish swimming in a horizontal plane has velocity v = (4.00 î + 1.00 j) m/s at a point in the ocean where the position relative to a certain rock is ï = (10.0 î – 4.00 j) m . After the fish swims with constant acceleration for 20.0 s, its velocity is v = (20.0 î – 5.00 j) m/s . 1. What are the components of the acceleration of the fish? 2. What is the direction of its acceleration with respect to unit vector î ? 3. If the fish maintains constant acceleration, where is it at t = 25.0 s and in what direction is it moving?
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