Chapter 4, Problem 4.97P

Interpretation Introduction

Interpretation:

The formation of ${\text{KClO}}_{\text{4}}$ can be explained with the given three sequential reactions. The percentage yield of each individual reaction is given in brackets.

${\text{Cl}}_{\text{2}}\text{(g) + 2KOH(aq) }\stackrel{}{\to }{\text{ KCl(aq) + KClO(aq) + H}}_{\text{2}}\text{O(l) [92}\text{.1\%]}$

$\text{ 3KClO(aq) }\stackrel{}{\to }{\text{ 2KCl(aq) + KClO}}_{\text{3}}\text{(aq) [86}\text{.7\%]}$

${\text{ 4KClO}}_{\text{3}}\text{(aq) }\stackrel{}{\to }{\text{ KCl(aq) + 3KClO}}_4\text{(aq) [75}\text{.3\%]}$

What mass of ${\text{KClO}}_{\text{4}}$ will be obtained following above three reaction if a student has started with 966 kg of chlorine gas?

Concept Introduction:

The yield of sequential reactions is based on yield of each previous reaction also.

The percentage yield is calculated as.

$\text{\% yield = }\frac{\text{The amount of product formed }\times \text{ 100}}{\text{the amount of product expected}}$

Also.

Moles is related to mass of a compound as.

$\text{Moles = }\frac{\text{mass}}{\text{molar mass}}$

The atomic mass of each element ($\text{g/mol)}$

1. Chlorine is 35.5
2. Potassium is 39
3. Hydrogen is 1
4. Oxygen is 16