Pearson eText for Manufacturing Processes for Engineering Materials -- Instant Access (Pearson+)
Pearson eText for Manufacturing Processes for Engineering Materials -- Instant Access (Pearson+)
6th Edition
ISBN: 9780137503520
Author: Serope Kalpakjian, Steven Schmid
Publisher: PEARSON+
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Chapter 4, Problem 4.69P
To determine

The control limits.

Expert Solution & Answer
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Answer to Problem 4.69P

The Upper control limit for averages, lower control limit for averages, upper control limit for ranges and lower control limit for ranges is 0.72433 , 0.62227 , 0.15974 and 0 .

Explanation of Solution

Given:

The number of sample subsets are 6 .

The number of measured values in each subset are 4 .

Formula used:

The expression for average of sample subset is given as,x¯=x1+x2+x3+x44

Here, x1 , x2 , x3 and x4 are the variables of subset.

The expression forrange of sample subset is given as,R=xmaxxmin

Here, xmax is the maximum value in subset and xmin is the minimum value in subset.

The expression for average of averages is given as,x¯¯=x¯1+x¯2+x¯3+x¯4+x¯5+x¯66

The expression for average of ranges is given as,R¯=R1+R2+R3+R4+R5+R66

The expression for upper control limit for the averages is given as,UCLx=x¯¯+A2R¯

Here, A2 is constant.

The expression for lower control limit for the averages is given as,LCLx=x¯¯A2R¯

The expression for upper control limit for the ranges is given as,

  UCLR=D4R¯

Here, D4 is the constant.

The expression for lower control limit for the ranges is given as,

  LCLR=D3R¯

Here, D3 is the constant.

Calculation:

Refer to table 4.2 “Constant for control charts” for sample size 4 values obtained,

  A2=0.729D4=2.282D3=0

The average of the first subset can be calculated as,

  x¯1=0.65+0.75+0.67+0.654x¯1=2.724x¯1=0.68

The range of the first subset can be calculated as,

  R1=0.750.65R1=0.10

The average of the second subset can be calculated as,

  x¯2=0.69+0.73+0.70+0.684x¯2=2.84x¯2=0.7

The range of the second subset can be calculated as,

  R2=0.730.68R2=0.05

The average of the third subset can be calculated as,

  x¯3=0.65+0.68+0.65+0.614x¯3=2.594x¯3=0.6475

The range of the third subset can be calculated as,

  R3=0.680.61R3=0.07

The average of the fourth subset can be calculated as,

  x¯4=0.64+0.65+0.60+0.604x¯4=2.494x¯4=0.6225

The range of the fourth subset can be calculated as,

  R4=0.650.60R4=0.05

The average of the fifth subset can be calculated as,

  x¯5=0.68+0.72+0.70+0.664x¯5=2.764x¯5=0.69

The range of the fifth subset can be calculated as,

  R5=0.720.66R5=0.06

The average of the sixth subset can be calculated as,

  x¯6=0.70+0.74+0.65+0.714x¯6=2.84x¯6=0.7

The range of the sixth subset can be calculated as,

  R6=0.740.65R6=0.09

The average of averages can be calculated as,

  x¯¯= x ¯1+ x ¯2+ x ¯3+ x ¯4+ x ¯5+ x ¯66x¯¯=0.68+0.7+0.6475+0.6225+0.69+0.76x¯¯=4.046x¯¯=0.6733

The average of ranges can be calculated as,

  R¯=R1+R2+R3+R4+R5+R66R¯=0.10+0.05+0.07+0.05+0.06+0.096R¯=0.426R¯=0.07

The upper control limit for the averages can be calculated as,

  UCLx=x¯¯+A2R¯UCLx=0.6733+(0.729×0.07)UCLx=0.72433

The lower control limit for the averages can be calculated as,

  LCLx=x¯¯A2R¯LCLx=0.6733(0.729×0.07)LCLx=0.62227

The upper control limit for the ranges can be calculated as,

  UCLR=D4R¯UCLR=2.282×0.07UCLR=0.15974

The lower control limit for the ranges can be calculated as,

  LCLR=D3R¯LCLR=0×0.07LCLR=0

Conclusion:

Therefore, the Upper control limit for averages, lower control limit for averages, upper control limit for ranges and lower control limit for ranges is 0.72433 , 0.62227 , 0.15974 and 0 .

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