Chapter 4, Problem 4.64QP

(a)

Interpretation Introduction

To determine: The milliliters of $0.100\text{M}{\text{HNO}}_3$ that are required to neutralize the given solution.

Interpretation: The milliliters of $0.100\text{M}{\text{HNO}}_3$ that are required to neutralize the given solution is to be calculated.

Concept introduction: Neutralization is the state of the substance where formation of water takes place by the reaction of an acid and a base. The value of $\text{pH}$ of water is $7$. This is the neutral point of the solution. The volume of ${\text{HNO}}_3$ required to neutralize the solution is calculated by the formula,

$M_1{V}_1=M_2{V}_2$

(b)

Interpretation Introduction

To determine: The milliliters of $0.100\text{M}{\text{HNO}}_3$ that are required to neutralize the given solution.

Interpretation: The milliliters of $0.100\text{M}{\text{HNO}}_3$ that are required to neutralize the given solution is to be calculated.

Concept introduction: Neutralization is the state of the substance where formation of water takes place by the reaction of an acid and a base.

The value of $\text{pH}$ of water is $7$. This is the neutral point of the solution. The volume of ${\text{HNO}}_3$ required to neutralize the solution is calculated by the formula,

$M_1{V}_1=M_2{V}_2$

(c)

Interpretation Introduction

To determine: The milliliters of $0.100\text{M}{\text{HNO}}_3$ that are required to neutralize the given solution.

Interpretation: The milliliters of $0.100\text{M}{\text{HNO}}_3$ that are required to neutralize the given solution is to be calculated.

Concept introduction: Neutralization is the state of the substance where formation of water takes place by the reaction of an acid and a base. The value of $\text{pH}$ of water is $7$. This is the neutral point of the solution. The volume of ${\text{HNO}}_3$ required to neutralize the solution is calculated by the formula,

$M_1{V}_1=M_2{V}_2$