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MindTap Engineering for Glover/Overbye/Sarma's Power System Analysis and Design, 6th Edition, [Instant Access], 1 term (6 months)
6th Edition
ISBN: 9781305636309
Author: J. Duncan Glover; Thomas Overbye; Mulukutla S. Sarma
Publisher: Cengage Learning US
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Chapter 4, Problem 4.50P
To determine
The value of electric field strength at the surface conductor and at ground level directly under one conductor.
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Example2:-
8. = e.A nia +2.1 =
Find the maximum steady-state power capability of a system consisting of a
generator equivalent reactance of 0.4pu connected to an infinite bus through a
series reactance of 1.0 p.u. The terminal voltage of the generator is held at1.10 p.u.
and the voltage of the infinite bus is 1.0 p.u.
B) A 60-Hz generator is supplying 60% of P max to an infinite bus through a reactive network.
A fault occurs which increases the reactance of the network between the generator internal
voltage and the infinite bus by 400%. When the fault is cleared, the maximum power that can
be delivered is 80% of the original maximum value. Determine the critical clearing angle for
the condition described.
In the circuit shown, let Vs-9, R₁-8, R2-2, and R3-4. Use Nodal analysis to determine the current lo. In
particular find:
V2=
10=
A
The relative tolerance for this problem is 5 %.
R₁
V₁
+
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R₂
Vs
V₂
21
x
R3
Chapter 4 Solutions
MindTap Engineering for Glover/Overbye/Sarma's Power System Analysis and Design, 6th Edition, [Instant Access], 1 term (6 months)
Ch. 4 - ACSR stands for Aluminum-clad steel conductor...Ch. 4 - Overhead transmission-line conductors are bare...Ch. 4 - Alumoweld is an aluminum-clad steel conductor....Ch. 4 - EHV lines often have more than one conductor per...Ch. 4 - Shield wires located above the phase conductors...Ch. 4 - Conductor spacings, types, and sizes do have an...Ch. 4 - A circle with diameter Din.=1000Dmil=dmil has an...Ch. 4 - An ac resistance is higher than a dc resistance....Ch. 4 - Prob. 4.9MCQCh. 4 - Transmission line conductance is usually neglected...
Ch. 4 - Prob. 4.11MCQCh. 4 - Prob. 4.12MCQCh. 4 - For a single-phase, two-wire line consisting of...Ch. 4 - For a three-phase three-wire line consisting of...Ch. 4 - For a balanced three-phase positive-sequence...Ch. 4 - A stranded conductor is an example of a composite...Ch. 4 - lnAk=lnAk True FalseCh. 4 - Prob. 4.18MCQCh. 4 - Expand 6k=13m=12Dkm.Ch. 4 - Prob. 4.20MCQCh. 4 - For a single-phase two-conductor line with...Ch. 4 - In a three-phase line, in order to avoid unequal...Ch. 4 - For a completely transposed three-phase line...Ch. 4 - Prob. 4.24MCQCh. 4 - Does bundling reduce the series reactance of the...Ch. 4 - Does r=e14r=0.788r, which comes in calculation of...Ch. 4 - In terms of line-to-line capacitance, the...Ch. 4 - For either single-phase two-wire line or balanced...Ch. 4 - Prob. 4.29MCQCh. 4 - Prob. 4.30MCQCh. 4 - Prob. 4.31MCQCh. 4 - Prob. 4.32MCQCh. 4 - Prob. 4.33MCQCh. 4 - Prob. 4.34MCQCh. 4 - The affect of the earth plane is to slightly...Ch. 4 - When the electric field strength at a conductor...Ch. 4 - Prob. 4.37MCQCh. 4 - Prob. 4.38MCQCh. 4 - Considering two parallel three-phase circuits that...Ch. 4 - The Aluminum Electrical Conductor Handbook lists a...Ch. 4 - The temperature dependence of resistance is also...Ch. 4 - A transmission-line cable with a length of 2 km...Ch. 4 - One thousand circular mils or 1 kcmil is sometimes...Ch. 4 - A 60-Hz, 765-kV, three-phase overhead transmission...Ch. 4 - A three-phase overhead transmission line is...Ch. 4 - If the per-phase line loss in a 70-km-long...Ch. 4 - A 60-Hz, single-phase two-wire overhead line has...Ch. 4 - Prob. 4.9PCh. 4 - A 60-Hz, three-phase three-wire overhead line has...Ch. 4 - Prob. 4.11PCh. 4 - Find the inductive reactance per mile of a...Ch. 4 - A single-phase overhead transmission line consists...Ch. 4 - Prob. 4.14PCh. 4 - Find the GMR of a stranded conductor consisting of...Ch. 4 - Prob. 4.16PCh. 4 - Determine the GMR of each of the unconventional...Ch. 4 - A 230-kV, 60-Hz, three-phase completely transposed...Ch. 4 - Prob. 4.19PCh. 4 - Calculate the inductive reactance in /km of a...Ch. 4 - Rework Problem 4.20 if the bundled line has (a)...Ch. 4 - Prob. 4.22PCh. 4 - Prob. 4.23PCh. 4 - Prob. 4.24PCh. 4 - For the overhead line of configuration shown in...Ch. 4 - Prob. 4.26PCh. 4 - Figure 4.34 shows double-circuit conductors'...Ch. 4 - For the case of double-circuit, bundle-conductor...Ch. 4 - Prob. 4.29PCh. 4 - Figure 4.37 shows the conductor configuration of a...Ch. 4 - Prob. 4.32PCh. 4 - Prob. 4.33PCh. 4 - Prob. 4.34PCh. 4 - Prob. 4.35PCh. 4 - Prob. 4.36PCh. 4 - Prob. 4.38PCh. 4 - Calculate the capacitance-to-neutral in F/m and...Ch. 4 - Prob. 4.40PCh. 4 - Prob. 4.41PCh. 4 - Prob. 4.42PCh. 4 - Three ACSR Drake conductors are used for a...Ch. 4 - Consider the line of Problem 4.25. Calculate the...Ch. 4 - Prob. 4.45PCh. 4 - Prob. 4.46PCh. 4 - Prob. 4.47PCh. 4 - The capacitance of a single-circuit, three-phase...Ch. 4 - Prob. 4.49PCh. 4 - Prob. 4.50PCh. 4 - Prob. 4.51PCh. 4 - Approximately how many physical transmission...Ch. 4 - Prob. BCSQCh. 4 - Prob. CCSQCh. 4 - Prob. DCSQ
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- 1. Choose all nodes that must be included, if any, to construct the supernode for Nodal analysis. OV1, V3 OV1, V2 ○ V2, V3 OV1, V2, V4 OV1, V2, V3 O V2, V3, V4 2. Write KCL equation (Nodal equation) at super-node. Write your expression in terms of node voltages V1, V2, V3 and V4 and of the form (G11 V1+G12 V2+G13 V3+G14 V4 = 11), then enter the corresponding values: At super-node KCL: 1/Q G11 1/0 G12 1/Ω G13 1/Q G14 A 3. Use the above equation, the circuit and and super-node inner expression to calculate V3 and then lo : V3= V 10 = R3 Vst + A V₁ + VS2 V₂ V3 w W R₁ R₂ R4 ww R5 V4 V$3arrow_forwardEnter the matrix values (numerical) to solve for voltages at nodes v1, and v2, for the circuit shown, using Nodal equations. In the matrix, row 1, and row 2, correspond to node v1, and node v2 current expressions, respectively. Let Is1=14, Is2=7, R₁=5, R₂-8, R3=2, and R4-5. [G11 G12] [Vi₁ The matrix values are shown here: = G21 G22 [V2] [41] [12] {Hint: As discussed in class and to avoid sign errors, assume nodal currents are locally defined at each node (leaving) and use node labeling as indicated in the circuit. } The relative tolerance for this problem is 5%. VI R2 ww Isl 12 NODE v1 G11 G12 RI 1/Q 1/0 A 4= NODE v2 G21- 1/Q G22 1/0 12 W A === www R3 R4 www Use Cramer's rule (matrix), substitution, or any other method to calculate the voltages: v1 = V v2= V Is2arrow_forwardOnly expert should attemptarrow_forward
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