Mind on Statistics
5th Edition
ISBN: 9781285463186
Author: Jessica M. Utts, Robert F. Heckard
Publisher: Brooks Cole
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Chapter 4, Problem 4.49E
To determine
To explain:
Whether the relationship has practical significance if it is statically significant.
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Crumbs Cookies was interested in seeing if there was an association between cookie flavor and whether or not there was frosting. Given are the results of the last week's orders.
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Chapter 4 Solutions
Mind on Statistics
Ch. 4 - Prob. 4.1ECh. 4 - Prob. 4.2ECh. 4 - Each fall, auditions for the band and orchestra...Ch. 4 - Prob. 4.4ECh. 4 - For each pair of variables, indicate whether or...Ch. 4 - For each pair of variables, indicate whether or...Ch. 4 - Suppose a study on the relationship between gender...Ch. 4 - Prob. 4.8ECh. 4 - Prob. 4.9ECh. 4 - Do grumpy old men have a greater risk of having...
Ch. 4 - Prob. 4.11ECh. 4 - Prob. 4.12ECh. 4 - Prob. 4.13ECh. 4 - Prob. 4.14ECh. 4 - Prob. 4.15ECh. 4 - Prob. 4.16ECh. 4 - For Exercise 4.17 and 4.18: A study is done to...Ch. 4 - For Exercise 4.17 and 4.18: A study is done to...Ch. 4 - Prob. 4.19ECh. 4 - a. For a relative risk of 2.1, what is the percent...Ch. 4 - a. For a relative risk of 1.53, what is the...Ch. 4 - Science News (February 25, 1995, p. 124) reported...Ch. 4 - Prob. 4.23ECh. 4 - Prob. 4.24ECh. 4 - Exercise 4.10 described a study in which men were...Ch. 4 - Prob. 4.26ECh. 4 - Prob. 4.27ECh. 4 - Suppose a newspaper article states that drinking...Ch. 4 - Prob. 4.29ECh. 4 - Prob. 4.30ECh. 4 - Prob. 4.31ECh. 4 - Case Study 1.5 (p. 4) was called Does Prayer Lower...Ch. 4 - Prob. 4.33ECh. 4 - Prob. 4.34ECh. 4 - Prob. 4.35ECh. 4 - Prob. 4.36ECh. 4 - Prob. 4.37ECh. 4 - Prob. 4.38ECh. 4 - Prob. 4.39ECh. 4 - Researchers studied a random sample of North...Ch. 4 - Refer to Exercise 4.40. a. Write a two-way table...Ch. 4 - In a national survey, n=1000 randomly selected...Ch. 4 - Prob. 4.43ECh. 4 - Prob. 4.44ECh. 4 - Prob. 4.45ECh. 4 - Prob. 4.46ECh. 4 - Prob. 4.47ECh. 4 - Prob. 4.48ECh. 4 - Prob. 4.49ECh. 4 - Prob. 4.50ECh. 4 - Prob. 4.51ECh. 4 - Prob. 4.52ECh. 4 - Refer to the Minitab output for Exercise 4.52. The...Ch. 4 - Prob. 4.54ECh. 4 - Prob. 4.55ECh. 4 - Prob. 4.56ECh. 4 - Prob. 4.57ECh. 4 - Prob. 4.58ECh. 4 - Exercise 4.2 (p.136) gave the following data from...Ch. 4 - In Example 4.15 (p. 130), a statistically...Ch. 4 - Prob. 4.61ECh. 4 - Prob. 4.62ECh. 4 - Prob. 4.63ECh. 4 - Prob. 4.64ECh. 4 - Prob. 4.65ECh. 4 - Prob. 4.66ECh. 4 - Prob. 4.67ECh. 4 - Prob. 4.68ECh. 4 - Prob. 4.69ECh. 4 - Prob. 4.70ECh. 4 - Prob. 4.71ECh. 4 - Prob. 4.72ECh. 4 - Prob. 4.73ECh. 4 - Prob. 4.74ECh. 4 - Prob. 4.75ECh. 4 - Prob. 4.76ECh. 4 - Prob. 4.77ECh. 4 - Prob. 4.78ECh. 4 - Prob. 4.79ECh. 4 - Prob. 4.80ECh. 4 - Prob. 4.81ECh. 4 - Prob. 4.82ECh. 4 - Prob. 4.83ECh. 4 - Prob. 4.84E
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- a) Let X and Y be independent random variables both with the same mean µ=0. Define a new random variable W = aX +bY, where a and b are constants. (i) Obtain an expression for E(W).arrow_forwardThe table below shows the estimated effects for a logistic regression model with squamous cell esophageal cancer (Y = 1, yes; Y = 0, no) as the response. Smoking status (S) equals 1 for at least one pack per day and 0 otherwise, alcohol consumption (A) equals the average number of alcohoic drinks consumed per day, and race (R) equals 1 for blacks and 0 for whites. Variable Effect (β) P-value Intercept -7.00 <0.01 Alcohol use 0.10 0.03 Smoking 1.20 <0.01 Race 0.30 0.02 Race × smoking 0.20 0.04 Write-out the prediction equation (i.e., the logistic regression model) when R = 0 and again when R = 1. Find the fitted Y S conditional odds ratio in each case. Next, write-out the logistic regression model when S = 0 and again when S = 1. Find the fitted Y R conditional odds ratio in each case.arrow_forwardThe chi-squared goodness-of-fit test can be used to test if data comes from a specific continuous distribution by binning the data to make it categorical. Using the OpenIntro Statistics county_complete dataset, test the hypothesis that the persons_per_household 2019 values come from a normal distribution with mean and standard deviation equal to that variable's mean and standard deviation. Use signficance level a = 0.01. In your solution you should 1. Formulate the hypotheses 2. Fill in this table Range (-⁰⁰, 2.34] (2.34, 2.81] (2.81, 3.27] (3.27,00) Observed 802 Expected 854.2 The first row has been filled in. That should give you a hint for how to calculate the expected frequencies. Remember that the expected frequencies are calculated under the assumption that the null hypothesis is true. FYI, the bounderies for each range were obtained using JASP's drag-and-drop cut function with 8 levels. Then some of the groups were merged. 3. Check any conditions required by the chi-squared…arrow_forward
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