Organic Chemistry: Principles And Mechanisms (second Edition)
2nd Edition
ISBN: 9780393630749
Author: KARTY, Joel
Publisher: W. W. Norton & Company
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 4, Problem 4.45P
Interpretation Introduction
Interpretation:
The most stable isomer among the cis and trans isomers of the given compound is to be determined.
Concept introduction:
When the bulkier substituent attached to a cyclohexane ring is in the equatorial position, the chair conformation is more favored. In the disubstituted cyclohexane, the substituents which are on the opposite side of the ring are trans to each other. If there are more than one substituent attached, then the conformation in which maximum substituents are in the equatorial position is favored and is more stable.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
20.17 Predict the structure of the major product formed by 1,2-addition of HBr to
3-methylenecyclohexene.
3-Methylenecyclohexene
20.18 Predict the major product formed by 1,4-addition of HBr to 3-methylenecyclohexene.
+
Draw a vicinal alkyl bromide that would produce the following alkene in an E2
elimination. Use a dash or wedge bond to indicate stereochemistry on
asymmetric centers, where applicable. Ignore any inorganic byproducts.
Br
Drawing
Strong Base
H
Q
Atoms, Bonds
Charges
and Rings
Draw or tap a new bond to see suggestions.
Remove
Done
語
Reset
Undo
+
Drag To Pan
Draw a vicinal alkyl bromide that would produce the following alkene in an
E2 elimination. Use a dash or wedge bond to indicate stereochemistry on
asymmetric centers, where applicable. Ignore any inorganic byproducts.
+
Drawing
Į
Strong Base
H
Br
Q
Atoms, Bonds
and Rings
Charges
Draw or tap a new bond to see suggestions.
Undo
Reset
謂
Remove
Done
Drag To Pan
+
Chapter 4 Solutions
Organic Chemistry: Principles And Mechanisms (second Edition)
Ch. 4 - Prob. 4.1PCh. 4 - Prob. 4.2PCh. 4 - Prob. 4.3PCh. 4 - Prob. 4.4PCh. 4 - Prob. 4.5PCh. 4 - Prob. 4.6PCh. 4 - Prob. 4.7PCh. 4 - Prob. 4.8PCh. 4 - Prob. 4.9PCh. 4 - Prob. 4.10P
Ch. 4 - Prob. 4.11PCh. 4 - Prob. 4.12PCh. 4 - Prob. 4.13PCh. 4 - Prob. 4.14PCh. 4 - Prob. 4.15PCh. 4 - Prob. 4.16PCh. 4 - Prob. 4.17PCh. 4 - Prob. 4.18PCh. 4 - Prob. 4.19PCh. 4 - Prob. 4.20PCh. 4 - Prob. 4.21PCh. 4 - Prob. 4.22PCh. 4 - Prob. 4.23PCh. 4 - Prob. 4.24PCh. 4 - Prob. 4.25PCh. 4 - Prob. 4.26PCh. 4 - Prob. 4.27PCh. 4 - Prob. 4.28PCh. 4 - Prob. 4.29PCh. 4 - Prob. 4.30PCh. 4 - Prob. 4.31PCh. 4 - Prob. 4.32PCh. 4 - Prob. 4.33PCh. 4 - Prob. 4.34PCh. 4 - Prob. 4.35PCh. 4 - Prob. 4.36PCh. 4 - Prob. 4.37PCh. 4 - Prob. 4.38PCh. 4 - Prob. 4.39PCh. 4 - Prob. 4.40PCh. 4 - Prob. 4.41PCh. 4 - Prob. 4.42PCh. 4 - Prob. 4.43PCh. 4 - Prob. 4.44PCh. 4 - Prob. 4.45PCh. 4 - Prob. 4.46PCh. 4 - Prob. 4.47PCh. 4 - Prob. 4.48PCh. 4 - Prob. 4.49PCh. 4 - Prob. 4.50PCh. 4 - Prob. 4.51PCh. 4 - Prob. 4.52PCh. 4 - Prob. 4.53PCh. 4 - Prob. 4.54PCh. 4 - Prob. 4.55PCh. 4 - Prob. 4.56PCh. 4 - Prob. 4.57PCh. 4 - Prob. 4.58PCh. 4 - Prob. 4.59PCh. 4 - Prob. 4.60PCh. 4 - Prob. 4.61PCh. 4 - Prob. 4.62PCh. 4 - Prob. 4.63PCh. 4 - Prob. 4.64PCh. 4 - Prob. 4.65PCh. 4 - Prob. 4.66PCh. 4 - Prob. 4.67PCh. 4 - Prob. 4.68PCh. 4 - Prob. 4.69PCh. 4 - Prob. 4.70PCh. 4 - Prob. 4.71PCh. 4 - Prob. 4.72PCh. 4 - Prob. 4.73PCh. 4 - Prob. 4.1YTCh. 4 - Prob. 4.2YTCh. 4 - Prob. 4.3YTCh. 4 - Prob. 4.4YTCh. 4 - Prob. 4.5YTCh. 4 - Prob. 4.6YTCh. 4 - Prob. 4.7YTCh. 4 - Prob. 4.8YTCh. 4 - Prob. 4.9YTCh. 4 - Prob. 4.10YTCh. 4 - Prob. 4.11YTCh. 4 - Prob. 4.12YTCh. 4 - Prob. 4.13YTCh. 4 - Prob. 4.14YTCh. 4 - Prob. 4.15YTCh. 4 - Prob. 4.16YTCh. 4 - Prob. 4.17YTCh. 4 - Prob. 4.18YTCh. 4 - Prob. 4.19YTCh. 4 - Prob. 4.20YTCh. 4 - Prob. 4.21YTCh. 4 - Prob. 4.22YTCh. 4 - Prob. 4.23YTCh. 4 - Prob. 4.24YTCh. 4 - Prob. 4.25YT
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Draw the product of the E2 reaction shown below. Include the correct stereochemistry. Ignore any inorganic byproducts. + Br CH3 Q Strong Base Drawing Atoms, Bonds and Rings Charges Undo Reset H "Br H N Br. Remove Done .N. Drag To Panarrow_forwardCurved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the curved arrows to draw the product of this elementary step in an elimination mechanism. Include all lone pairs and charges as appropriate. Ignore stereochemistry. Ignore byproducts. + Br: .. 8 0.01 M NaOH heat Drawing Q Atoms, Bonds and Rings Charges and Lone Pairs Draw or tap a new bond to see suggestions. Undo Reset Remove Done + Drag To Panarrow_forward+ Draw the product of the E2 reaction shown below. Include the correct stereochemistry. Ignore any inorganic byproducts. Ph CH2CH3 H H3C H Br DBN [૪] Drawing Atoms, Bonds and Rings H | OH Charges ―00 H. C | Undo Reset Br I Remove Done Drag To Pan +arrow_forward
- Reaction A Now the production A ΠIn the product of reaction i 12 Dear the product of actionarrow_forwardMacmillan Learnin When an unknown amine reacts with an unknown acid chloride, an amide with a molecular mass of 163 g/mol (M* = 163 m/z) is formed. In the infrared spectrum, important absorptions appear at 1661, 750 and 690 cm-1. The 13C NMR and DEPT spectra are provided. Draw the structure of the product as the resonance contributor lacking any formal charges. 13C NMR DEPT 90 200 160 120 80 40 0 200 160 120 80 DEPT 135 200 160 120 80 40 0 Draw the unknown amide. 40 40 0arrow_forwardDraw the major product karmed when I reach with the epoxide. Use walge dah bonds, including hydrogen al alcach genic center, to show the chemistry of the product Beeldraw any hydrogen akams on coxygen where applicablearrow_forward
- Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. H I Select to Add Arrows + H H 'H Q H2O H2O CI:O .H H H H I Select to Add Arrows I : C H2O H H H Select to Add Arrows 'Harrow_forward+ Draw an alkyl halide that produces ONLY the following alkene in an E2 elimination. Ignore any inorganic byproducts. Drawing Strong Base Q Atoms, Bonds and Rings Charges HO Br H2N Undo Reset Remove Done Drag To Panarrow_forwardFor the dehydrohalogenation (E2) reaction shown, draw the major organic product. Хок Br tert-butanol heat Select Drew Templates More Erase CH QQQarrow_forward
- Macmillan Learning Draw the major, neutral organic product for each substitution reaction. For this question, assume that each substitution reaction goes to completion. Disregard elimination. Reaction A. CI H₂O Select Draw Templates More Erase C Harrow_forwardMacmillan Learning Reaction B: CI HO_ 곳으 / Select Draw Templates More с € H D Erasearrow_forwardWhen 2-bromo-93-dimethylbutane is heated with sodium methoxide, one majors.. në la formed. 4th attempt Part 1 (0.5 point) t Ji See Periodic Table See Hint Draw the major alkene product and all other byproducts. Be sure to include lone-pair electrons and charges. Part 2 (0.5 point) What type of mechanism is occuring? Choose one: AS1 3rd attempt X H 41 See Hint Part 1 (0.5 point) Feedback See Periodic Table See Hintarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
Organic Chemistry: A Guided Inquiry
Chemistry
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Cengage Learning