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A loaded elevator with very worn cables has a total mass of 2200 kg, and the cables can withstand a maximum tension of 28,000 N. (a) Draw the free-body force diagram for the elevator. In terms of the forces on your diagram, what is the net force on the elevator? Apply Newton’s second law to the elevator and find the maximum upward acceleration for the elevator if the cables are not to break. (b) What would be the answer to part (a) if the elevator were on the moon, where g = 1.62 m/s2?
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Chapter 4 Solutions
University Physics (14th Edition)
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- Truck suspensions often have "helper springs" that engage at high loads. One such arrangement is a leaf spring with a helper coil spring mounted on the axle, as shown in the figure below. When the main leaf spring is compressed by distance yo, the helper spring engages and then helps to support any additional load. Suppose the leaf spring constant is 5.05 × 105 N/m, the helper spring constant is 3.50 × 105 N/m, and y = 0.500 m. Truck body yo Main leaf spring -"Helper" spring Axle (a) What is the compression of the leaf spring for a load of 6.00 × 105 N? Your response differs from the correct answer by more than 10%. Double check your calculations. m (b) How much work is done in compressing the springs? ☑ Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. Jarrow_forwardA spring is attached to an inclined plane as shown in the figure. A block of mass m = 2.71 kg is placed on the incline at a distance d = 0.285 m along the incline from the end of the spring. The block is given a quick shove and moves down the incline with an initial speed v = 0.750 m/s. The incline angle is = 20.0°, the spring constant is k = 505 N/m, and we can assume the surface is frictionless. By what distance (in m) is the spring compressed when the block momentarily comes to rest? m m 0 k wwwwarrow_forwardA block of mass m = 2.50 kg situated on an incline at an angle of k=100 N/m www 50.0° is connected to a spring of negligible mass having a spring constant of 100 N/m (Fig. P8.54). The pulley and incline are frictionless. The block is released from rest with the spring initially unstretched. Ө m i (a) How far does it move down the frictionless incline before coming to rest? m (b) What is its acceleration at its lowest point? Magnitude m/s² Direction O up the incline down the inclinearrow_forward
- (a) A 15.0 kg block is released from rest at point A in the figure below. The track is frictionless except for the portion between points B and C, which has a length of 6.00 m. The block travels down the track, hits a spring of force constant 2,100 N/m, and compresses the spring 0.250 m from its equilibrium position before coming to rest momentarily. Determine the coefficient of kinetic friction between the block and the rough surface between points B and C. -A 3.00 m B C -6.00 m i (b) What If? The spring now expands, forcing the block back to the left. Does the block reach point B? Yes No If the block does reach point B, how far up the curved portion of the track does it reach, and if it does not, how far short of point B does the block come to a stop? (Enter your answer in m.) marrow_forwardA ball of mass m = 1.95 kg is released from rest at a height h = 57.0 cm above a light vertical spring of force constant k as in Figure [a] shown below. The ball strikes the top of the spring and compresses it a distance d = 7.80 cm as in Figure [b] shown below. Neglecting any energy losses during the collision, find the following. т m a d T m b i (a) Find the speed of the ball just as it touches the spring. 3.34 m/s (b) Find the force constant of the spring. Your response differs from the correct answer by more than 10%. Double check your calculations. kN/marrow_forwardI need help with questions 1-10 on my solubility curve practice sheet. I tried to my best ability on the answers, however, i believe they are wrong and I would like to know which ones a wrong and just need help figuring it out.arrow_forward
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