The substance that must be present in an aqueous solution for it to conduct an electric current and the general class of compound that form conductive solution is to be determined. Concept introduction: A solution is a combination of two parts: solute and solvent. The solute is the substance that is present in small quantity and solvent is the substance in which solute is dissolved. When water acts as a solvent then it is known as an aqueous solution. An electrolyte is a substance that conducts electricity when it is dissolved in water. Ionic compounds are the compounds that are composed of charged ions. There are held together by electrostatic forces. Example of an ionic compound is NaCl .
The substance that must be present in an aqueous solution for it to conduct an electric current and the general class of compound that form conductive solution is to be determined. Concept introduction: A solution is a combination of two parts: solute and solvent. The solute is the substance that is present in small quantity and solvent is the substance in which solute is dissolved. When water acts as a solvent then it is known as an aqueous solution. An electrolyte is a substance that conducts electricity when it is dissolved in water. Ionic compounds are the compounds that are composed of charged ions. There are held together by electrostatic forces. Example of an ionic compound is NaCl .
The substance that must be present in an aqueous solution for it to conduct an electric current and the general class of compound that form conductive solution is to be determined.
Concept introduction:
A solution is a combination of two parts: solute and solvent. The solute is the substance that is present in small quantity and solvent is the substance in which solute is dissolved. When water acts as a solvent then it is known as an aqueous solution.
An electrolyte is a substance that conducts electricity when it is dissolved in water.
Ionic compounds are the compounds that are composed of charged ions. There are held together by electrostatic forces. Example of an ionic compound is NaCl.
When two solutions, one of 0.1 M KCl (I) and the other of 0.1 M MCl (II), are brought into contact by a membrane. The cation M cannot cross the membrane. At equilibrium, x moles of K+ will have passed from solution (I) to (II). To maintain the neutrality of the two solutions, x moles of Cl- will also have to pass from I to II. Explain this equality: (0.1 - x)/x = (0.1 + x)/(0.1 - x)
Calculate the variation in the potential of the Pt/MnO4-, Mn2+ pair with pH, indicating the value of the standard potential. Data: E0 = 1.12.
Given the cell: Pt l H2(g) l dis X:KCl (sat) l Hg2Cl2(s) l Hg l Pt. Calculate the emf of the cell as a function of pH.
Chapter 4 Solutions
Loose Leaf for Chemistry: The Molecular Nature of Matter and Change
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