To determine Calculate the power developed in the dependent voltage source in the given circuit using PSPICE. Explanation The given circuit is redrawn as shown in Figure 1. Apply Kirchhoff’s voltage law for Loop 1 in Figure 1. 3 ( i 1 − i 2 ) + 5 ( i 1 − i 3 ) = − 53 i Δ 3 i 1 − 3 i 2 + 5 i 1 − 5 i 3 = − 53 i Δ 8 i 1 − 3 i 2 − 5 i 3 = − 53 i Δ (1) Apply Kirchhoff’s voltage law for Loop 2 in Figure 1. 3 ( i 2 − i 1 ) + 20 ( i 2 − i 3 ) + 7 i 2 = 30 3 i 2 − 3 i 1 + 20 i 2 − 20 i 3 + 7 i 2 = 30 − 3 i 1 + 30 i 2 − 20 i 3 = 30 (2) Apply Kirchhoff’s voltage law for Loop 3 in Figure 1. 5 ( i 3 − i 1 ) + 20 ( i 3 − i 2 ) + 2 i 3 = 30 5 i 3 − 5 i 1 + 20 i 3 − 20 i 2 + 2 i 3 = 30 − 5 i 1 − 20 i 2 + 27 i 3 = 30 (3) In Figure 1, the current i Δ is calculated as follows. i Δ = i 2 − i 3 (4) Substitute equation (4) in equation (1). 8 i 1 − 3 i 2 − 5 i 3 = − 53 ( i 2 − i 3 ) 8 i 1 − 3 i 2 − 5 i 3 = − 53 i 2 + 53 i 3 8 i 1 − 3 i 2 − 5 i 3 + 53 i 2 − 53 i 3 = 0 8 i 1 + 50 i 2 − 58 i 3 = 0 Rearrange the equation as follows, 58 i 3 = 8 i 1 + 50 i 2 i 3 = 8 i 1 + 50 i 2 58 i 3 = 0.1379 i 1 + 0.8621 i 2 (5) Substitute equation (5) in equation (2). − 3 i 1 + 30 i 2 − 20 ( 0.1379 i 1 + 0.8621 i 2 ) = 30 − 3 i 1 + 30 i 2 − 2.758 i 1 − 17.242 i 2 = 30 − 5.758 i 1 + 12.758 i 2 = 30 Rearrange the equation as follows, 5.758 i 1 = 12.758 i 2 − 30 i 1 = 12.758 i 2 − 30 5.758 i 1 = 2.2157 i 2 − 5.2101 (6) Substitute equation (6) in equation (5)

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ISBN: 9780100801790

Author: Riedel

Publisher: YUZU

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Nodal Analysis

In the analysis of any electric circuit, nodal analysis is the method of determining the potential difference or voltage between different nodes in an electric circuit. A node is a point where two or more branches connect each other. In the nodal analysi…

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Chapter 4, Problem 42P

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Calculate the power developed in the dependent voltage source in the given circuit using PSPICE.

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Chapter 4, Problem 41P

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EBK ELECTRIC CIRCUITS

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