The volume ( mL ) of 2.26 M potassium hydroxide that contains 8.42 g of solute is to be calculated. Concept introduction: Molarity ( M ) is one of the concentration terms that determine the number of moles of solute present in per litre of solution. Unit of molarity is mol/L . The expression to calculate the volume of the solution when the amount of compound in moles and molarity of solution are given is as follows: Volume of solution ( L ) = moles of solute ( mol ) ( 1 L of solution molarity of solution ( mol ) ) The expression to calculate the moles of solute when given mass and molecular mass of compound are given is as follows: Moles of compound ( mol ) = [ given mass of compound ( g ) ( 1mole of compound ( mol ) molecular mass of compound ( g ) ) ]
The volume ( mL ) of 2.26 M potassium hydroxide that contains 8.42 g of solute is to be calculated. Concept introduction: Molarity ( M ) is one of the concentration terms that determine the number of moles of solute present in per litre of solution. Unit of molarity is mol/L . The expression to calculate the volume of the solution when the amount of compound in moles and molarity of solution are given is as follows: Volume of solution ( L ) = moles of solute ( mol ) ( 1 L of solution molarity of solution ( mol ) ) The expression to calculate the moles of solute when given mass and molecular mass of compound are given is as follows: Moles of compound ( mol ) = [ given mass of compound ( g ) ( 1mole of compound ( mol ) molecular mass of compound ( g ) ) ]
The volume (mL) of 2.26M potassium hydroxide that contains 8.42 g of solute is to be calculated.
Concept introduction:
Molarity (M) is one of the concentration terms that determine the number of moles of solute present in per litre of solution. Unit of molarity is mol/L.
The expression to calculate the volume of the solution when the amount of compound in moles and molarity of solution are given is as follows:
Volume of solution(L)=moles of solute(mol)(1L of solutionmolarity of solution(mol))
The expression to calculate the moles of solute when given mass and molecular mass of compound are given is as follows:
Moles of compound(mol)=[given massof compound(g)(1moleof compound(mol)molecular mass of compound(g))]
(b)
Interpretation Introduction
Interpretation:
The number of Cu2+ ions in 52L of 2.3Mcopper(II)chloride is to be calculated.
Concept introduction:
Molarity (M) is one of the concentration terms that determine the number of moles of solute present in per litre of solution. Unit of molarity is mol/L.
The expression to calculate the moles of the compound when molarity of solution and volume of solution are given is as follows:
Moles of compound(mol)=[volume of solution(L)(molarityofsolution(mol)1L of solution)]
The expression to calculate the amount of ions in moles is as follows:
amountofion(mol)=(moles of compound(mol))(moles of ion(mol)1mole of compound)
The expression to calculate the number of ions is as follows:
numberof ions=(moles of ions(mol))(6.022×1023ions1mole of ions)
(c)
Interpretation Introduction
Interpretation:
Molarity of 275 mL of solution containing 135 mmol of glucose is to be calculated.
Concept introduction:
Molarity (M) is one of the concentration terms that determine the number of moles of solute present in per litre of solution. Unit of molarity is mol/L.
The expression to calculate the molarity of a solution when moles of solute and volume of solution are given is as follows:
Molarity of solution(M)=moles of solute(mol)volume of solution(L)
Check the box under each structure in the table that is an enantiomer of the molecule shown below. If none of them are, check the none of the above box under
the table.
Molecule 1
Molecule 2
IZ
IN
Molecule 4
Molecule 5
ZI
none of the above
☐
Molecule 3
Х
IN
www
Molecule 6
NH
G
Highlight each chiral center in the following molecule. If there are none, then check the box under the drawing area.
There are no chiral centers.
Cl
Cl
Highlight
A student proposes the following two-step synthesis of an ether from an alcohol A:
1. strong base
A
2. R
Is the student's proposed synthesis likely to work?
If you said the proposed synthesis would work, enter the chemical
formula or common abbreviation for an appropriate strong base to use
in Step 1:
If you said the synthesis would work, draw the structure of an alcohol
A, and the structure of the additional reagent R needed in Step 2, in
the drawing area below.
If there's more than one reasonable choice for a good reaction yield,
you can draw any of them.
☐
Click and drag to start drawing a structure.
Yes
No
ロ→ロ
0|0
G
Х
D
: ☐
ப
Chapter 4 Solutions
Student Study Guide for Silberberg Chemistry: The Molecular Nature of Matter and Change