The number of hydrogen atoms in the saturated hydrocarbons that contain 23, 25, and 27 carbon atoms is to be calculated. Concept introduction: The aliphatic hydrocarbons that have only C − C and C − H bonds are called alkanes . They are classified as acyclic or cyclic. The acyclic alkanes are known as saturated hydrocarbons. The general molecular formula of acyclic alkanes is C n H 2 n + 2 .

Question

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Answer 1

Question

Chapter 4, Problem 4.1P

Interpretation Introduction

Interpretation: The number of hydrogen atoms in the saturated hydrocarbons that contain $23, 25, and 27$ carbon atoms is to be calculated.

Concept introduction: The aliphatic hydrocarbons that have only $C−C$ and $C−H$ bonds are called alkanes. They are classified as acyclic or cyclic. The acyclic alkanes are known as saturated hydrocarbons. The general molecular formula of acyclic alkanes is $CnH2n+2$ .

Expert Solution & Answer

Answer to Problem 4.1P

The number of $H$ atoms present in the saturated hydrocarbons of sex pheromone that contain $23, 25, and 27$ carbon atoms are $48, 52, and 56$ respectively.

Explanation of Solution

The given hydrocarbons of sex pheromone are saturated acyclic alkanes.

The aliphatic hydrocarbons that have only $C−C$ and $C−H$ sigma bonds are called alkanes. They are classified as acyclic or cyclic. The acyclic alkanes are known as saturated hydrocarbons.

The general molecular formula of acyclic alkanes is $CnH2n+2$ .

Where,

• n is an integer, that represents number of carbon atoms.

For the hydrocarbon of sex pheromone that contains $23$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$C23H(2×23)+2C23H48$

Thus, the molecular formula of hydrocarbon that contains $23$ carbon atoms is $C23H48$ .

Hence, the number of hydrogen atoms is $48$ .

For the hydrocarbon of sex pheromone that contains $25$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$=C25H(2×25)+2=C25H52$

Thus, the molecular formula of hydrocarbon that contains $25$ carbon atoms is $C25H52$ .

Hence, the number of hydrogen atoms is $52$ .

For the hydrocarbon of sex pheromone that contains $27$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$=C27H(2×27)+2=C27H56$

Thus, the molecular formula of hydrocarbon that contains $27$ carbon atoms is $C27H56$ .

Hence, the number of hydrogen atoms is $56$ .

Conclusion

The number of $H$ atoms in hydrocarbons of sex pheromone that contain $23, 25, and 27$ carbon atoms are $48, 52, and 56$ respectively.

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Answer 2

Question

Chapter 4, Problem 4.1P

Interpretation Introduction

Interpretation: The number of hydrogen atoms in the saturated hydrocarbons that contain $23, 25, and 27$ carbon atoms is to be calculated.

Concept introduction: The aliphatic hydrocarbons that have only $C−C$ and $C−H$ bonds are called alkanes. They are classified as acyclic or cyclic. The acyclic alkanes are known as saturated hydrocarbons. The general molecular formula of acyclic alkanes is $CnH2n+2$ .

Expert Solution & Answer

Answer to Problem 4.1P

The number of $H$ atoms present in the saturated hydrocarbons of sex pheromone that contain $23, 25, and 27$ carbon atoms are $48, 52, and 56$ respectively.

Explanation of Solution

The given hydrocarbons of sex pheromone are saturated acyclic alkanes.

The aliphatic hydrocarbons that have only $C−C$ and $C−H$ sigma bonds are called alkanes. They are classified as acyclic or cyclic. The acyclic alkanes are known as saturated hydrocarbons.

The general molecular formula of acyclic alkanes is $CnH2n+2$ .

Where,

• n is an integer, that represents number of carbon atoms.

For the hydrocarbon of sex pheromone that contains $23$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$C23H(2×23)+2C23H48$

Thus, the molecular formula of hydrocarbon that contains $23$ carbon atoms is $C23H48$ .

Hence, the number of hydrogen atoms is $48$ .

For the hydrocarbon of sex pheromone that contains $25$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$=C25H(2×25)+2=C25H52$

Thus, the molecular formula of hydrocarbon that contains $25$ carbon atoms is $C25H52$ .

Hence, the number of hydrogen atoms is $52$ .

For the hydrocarbon of sex pheromone that contains $27$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$=C27H(2×27)+2=C27H56$

Thus, the molecular formula of hydrocarbon that contains $27$ carbon atoms is $C27H56$ .

Hence, the number of hydrogen atoms is $56$ .

Conclusion

The number of $H$ atoms in hydrocarbons of sex pheromone that contain $23, 25, and 27$ carbon atoms are $48, 52, and 56$ respectively.

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Answer 3

Question

Chapter 4, Problem 4.1P

Interpretation Introduction

Interpretation: The number of hydrogen atoms in the saturated hydrocarbons that contain $23, 25, and 27$ carbon atoms is to be calculated.

Concept introduction: The aliphatic hydrocarbons that have only $C−C$ and $C−H$ bonds are called alkanes. They are classified as acyclic or cyclic. The acyclic alkanes are known as saturated hydrocarbons. The general molecular formula of acyclic alkanes is $CnH2n+2$ .

Expert Solution & Answer

Answer to Problem 4.1P

The number of $H$ atoms present in the saturated hydrocarbons of sex pheromone that contain $23, 25, and 27$ carbon atoms are $48, 52, and 56$ respectively.

Explanation of Solution

The given hydrocarbons of sex pheromone are saturated acyclic alkanes.

The aliphatic hydrocarbons that have only $C−C$ and $C−H$ sigma bonds are called alkanes. They are classified as acyclic or cyclic. The acyclic alkanes are known as saturated hydrocarbons.

The general molecular formula of acyclic alkanes is $CnH2n+2$ .

Where,

• n is an integer, that represents number of carbon atoms.

For the hydrocarbon of sex pheromone that contains $23$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$C23H(2×23)+2C23H48$

Thus, the molecular formula of hydrocarbon that contains $23$ carbon atoms is $C23H48$ .

Hence, the number of hydrogen atoms is $48$ .

For the hydrocarbon of sex pheromone that contains $25$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$=C25H(2×25)+2=C25H52$

Thus, the molecular formula of hydrocarbon that contains $25$ carbon atoms is $C25H52$ .

Hence, the number of hydrogen atoms is $52$ .

For the hydrocarbon of sex pheromone that contains $27$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$=C27H(2×27)+2=C27H56$

Thus, the molecular formula of hydrocarbon that contains $27$ carbon atoms is $C27H56$ .

Hence, the number of hydrogen atoms is $56$ .

Conclusion

The number of $H$ atoms in hydrocarbons of sex pheromone that contain $23, 25, and 27$ carbon atoms are $48, 52, and 56$ respectively.

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Answer 4

Question

Chapter 4, Problem 4.1P

Interpretation Introduction

Interpretation: The number of hydrogen atoms in the saturated hydrocarbons that contain $23, 25, and 27$ carbon atoms is to be calculated.

Concept introduction: The aliphatic hydrocarbons that have only $C−C$ and $C−H$ bonds are called alkanes. They are classified as acyclic or cyclic. The acyclic alkanes are known as saturated hydrocarbons. The general molecular formula of acyclic alkanes is $CnH2n+2$ .

Expert Solution & Answer

Answer to Problem 4.1P

The number of $H$ atoms present in the saturated hydrocarbons of sex pheromone that contain $23, 25, and 27$ carbon atoms are $48, 52, and 56$ respectively.

Explanation of Solution

The given hydrocarbons of sex pheromone are saturated acyclic alkanes.

The aliphatic hydrocarbons that have only $C−C$ and $C−H$ sigma bonds are called alkanes. They are classified as acyclic or cyclic. The acyclic alkanes are known as saturated hydrocarbons.

The general molecular formula of acyclic alkanes is $CnH2n+2$ .

Where,

• n is an integer, that represents number of carbon atoms.

For the hydrocarbon of sex pheromone that contains $23$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$C23H(2×23)+2C23H48$

Thus, the molecular formula of hydrocarbon that contains $23$ carbon atoms is $C23H48$ .

Hence, the number of hydrogen atoms is $48$ .

For the hydrocarbon of sex pheromone that contains $25$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$=C25H(2×25)+2=C25H52$

Thus, the molecular formula of hydrocarbon that contains $25$ carbon atoms is $C25H52$ .

Hence, the number of hydrogen atoms is $52$ .

For the hydrocarbon of sex pheromone that contains $27$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$=C27H(2×27)+2=C27H56$

Thus, the molecular formula of hydrocarbon that contains $27$ carbon atoms is $C27H56$ .

Hence, the number of hydrogen atoms is $56$ .

Conclusion

The number of $H$ atoms in hydrocarbons of sex pheromone that contain $23, 25, and 27$ carbon atoms are $48, 52, and 56$ respectively.

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Answer 5

Chapter 4, Problem 4.1P

Interpretation Introduction

Interpretation: The number of hydrogen atoms in the saturated hydrocarbons that contain $23, 25, and 27$ carbon atoms is to be calculated.

Concept introduction: The aliphatic hydrocarbons that have only $C−C$ and $C−H$ bonds are called alkanes. They are classified as acyclic or cyclic. The acyclic alkanes are known as saturated hydrocarbons. The general molecular formula of acyclic alkanes is $CnH2n+2$ .

Expert Solution & Answer

Answer to Problem 4.1P

The number of $H$ atoms present in the saturated hydrocarbons of sex pheromone that contain $23, 25, and 27$ carbon atoms are $48, 52, and 56$ respectively.

Explanation of Solution

The given hydrocarbons of sex pheromone are saturated acyclic alkanes.

The aliphatic hydrocarbons that have only $C−C$ and $C−H$ sigma bonds are called alkanes. They are classified as acyclic or cyclic. The acyclic alkanes are known as saturated hydrocarbons.

The general molecular formula of acyclic alkanes is $CnH2n+2$ .

Where,

• n is an integer, that represents number of carbon atoms.

For the hydrocarbon of sex pheromone that contains $23$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$C23H(2×23)+2C23H48$

Thus, the molecular formula of hydrocarbon that contains $23$ carbon atoms is $C23H48$ .

Hence, the number of hydrogen atoms is $48$ .

For the hydrocarbon of sex pheromone that contains $25$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$=C25H(2×25)+2=C25H52$

Thus, the molecular formula of hydrocarbon that contains $25$ carbon atoms is $C25H52$ .

Hence, the number of hydrogen atoms is $52$ .

For the hydrocarbon of sex pheromone that contains $27$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$=C27H(2×27)+2=C27H56$

Thus, the molecular formula of hydrocarbon that contains $27$ carbon atoms is $C27H56$ .

Hence, the number of hydrogen atoms is $56$ .

Conclusion

The number of $H$ atoms in hydrocarbons of sex pheromone that contain $23, 25, and 27$ carbon atoms are $48, 52, and 56$ respectively.

Answer 6

Chapter 4, Problem 4.1P

Interpretation Introduction

Interpretation: The number of hydrogen atoms in the saturated hydrocarbons that contain $23, 25, and 27$ carbon atoms is to be calculated.

Concept introduction: The aliphatic hydrocarbons that have only $C−C$ and $C−H$ bonds are called alkanes. They are classified as acyclic or cyclic. The acyclic alkanes are known as saturated hydrocarbons. The general molecular formula of acyclic alkanes is $CnH2n+2$ .

Expert Solution & Answer

Answer to Problem 4.1P

The number of $H$ atoms present in the saturated hydrocarbons of sex pheromone that contain $23, 25, and 27$ carbon atoms are $48, 52, and 56$ respectively.

Explanation of Solution

The given hydrocarbons of sex pheromone are saturated acyclic alkanes.

The aliphatic hydrocarbons that have only $C−C$ and $C−H$ sigma bonds are called alkanes. They are classified as acyclic or cyclic. The acyclic alkanes are known as saturated hydrocarbons.

The general molecular formula of acyclic alkanes is $CnH2n+2$ .

Where,

• n is an integer, that represents number of carbon atoms.

For the hydrocarbon of sex pheromone that contains $23$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$C23H(2×23)+2C23H48$

Thus, the molecular formula of hydrocarbon that contains $23$ carbon atoms is $C23H48$ .

Hence, the number of hydrogen atoms is $48$ .

For the hydrocarbon of sex pheromone that contains $25$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$=C25H(2×25)+2=C25H52$

Thus, the molecular formula of hydrocarbon that contains $25$ carbon atoms is $C25H52$ .

Hence, the number of hydrogen atoms is $52$ .

For the hydrocarbon of sex pheromone that contains $27$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$=C27H(2×27)+2=C27H56$

Thus, the molecular formula of hydrocarbon that contains $27$ carbon atoms is $C27H56$ .

Hence, the number of hydrogen atoms is $56$ .

Conclusion

The number of $H$ atoms in hydrocarbons of sex pheromone that contain $23, 25, and 27$ carbon atoms are $48, 52, and 56$ respectively.

Answer 7

Chapter 4, Problem 4.1P

Interpretation Introduction

Interpretation: The number of hydrogen atoms in the saturated hydrocarbons that contain $23, 25, and 27$ carbon atoms is to be calculated.

Concept introduction: The aliphatic hydrocarbons that have only $C−C$ and $C−H$ bonds are called alkanes. They are classified as acyclic or cyclic. The acyclic alkanes are known as saturated hydrocarbons. The general molecular formula of acyclic alkanes is $CnH2n+2$ .

Answer 8

Expert Solution & Answer

Answer to Problem 4.1P

The number of $H$ atoms present in the saturated hydrocarbons of sex pheromone that contain $23, 25, and 27$ carbon atoms are $48, 52, and 56$ respectively.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

The given hydrocarbons of sex pheromone are saturated acyclic alkanes.

The aliphatic hydrocarbons that have only $C−C$ and $C−H$ sigma bonds are called alkanes. They are classified as acyclic or cyclic. The acyclic alkanes are known as saturated hydrocarbons.

The general molecular formula of acyclic alkanes is $CnH2n+2$ .

Where,

• n is an integer, that represents number of carbon atoms.

For the hydrocarbon of sex pheromone that contains $23$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$C23H(2×23)+2C23H48$

Thus, the molecular formula of hydrocarbon that contains $23$ carbon atoms is $C23H48$ .

Hence, the number of hydrogen atoms is $48$ .

For the hydrocarbon of sex pheromone that contains $25$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$=C25H(2×25)+2=C25H52$

Thus, the molecular formula of hydrocarbon that contains $25$ carbon atoms is $C25H52$ .

Hence, the number of hydrogen atoms is $52$ .

For the hydrocarbon of sex pheromone that contains $27$ carbon atoms:

Substitute the value of number of carbon atoms $(n)$ in general molecular formula of acyclic alkanes.

$=C27H(2×27)+2=C27H56$

Thus, the molecular formula of hydrocarbon that contains $27$ carbon atoms is $C27H56$ .

Hence, the number of hydrogen atoms is $56$ .

Answer 12

Conclusion

The number of $H$ atoms in hydrocarbons of sex pheromone that contain $23, 25, and 27$ carbon atoms are $48, 52, and 56$ respectively.

Answer 13

Ch. 4 - Prob. 4.1P Ch. 4 - Problem 4.2 Which of the following is not another...Ch. 4 - Problem 4.3 Draw the five constitutional isomers...Ch. 4 - Prob. 4.4P Ch. 4 - Prob. 4.5P Ch. 4 - Draw the five constitutional isomers that have...Ch. 4 - Problem 4.7 Give the IUPAC name for each...Ch. 4 - Give the IUPAC name for each compound. a....Ch. 4 - Problem 4.9 Give the structure corresponding to...Ch. 4 - Prob. 4.10P

Concept explainers

Answer to Problem 4.1P

Explanation of Solution

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Chapter 4 Solutions