Chapter 4, Problem 4.19.6E

Explanation of Solution

Energy spent by the instruction memory in each cycle:

The energy spent by the instruction memory in each cycle is shown below:

Given:

$\begin{array}{l}\text{Active energy of I-Mem}\text{=140 pJ}\\ \text{Latency of the I-Mem}\text{=200 ps}\\ \text{Clock cycle time}\text{=250 ps}\end{array}$

$\begin{array}{c}\text{Total I-Mem Energy = Active energy + Idle energy}\\ \text{=140pJ}\text{+}\frac{\left(\left(\text{250-200}\right)\text{×0}\text{.1×140}\right)}{\text{200}}\\ \text{=140}\text{pJ+}(\frac{(\text{50×0}}{}\end{array}$