EBK USING MIS
10th Edition
ISBN: 9780134658919
Author: KROENKE
Publisher: YUZU
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Chapter 4, Problem 4.14CS4
Explanation of Solution
Apple can be successful without Steve:
In one’s point of view, Apple company had shown that they can be successful without Steve. It has been approximately 6 years since his death and till now people continue to buy Apple products.
- When the company’s founder passed away, it causes the vast amount of insecurity and opposition between shareholders.
- Some shareholders lost their faith but some of them continues to support the Apple company.
- The primary goal of the founder is to construct the company strong enough where it can survive even after the death of the founder.
Therefore, some people might feel that Apple will not be able to maintain its success without its leadership and some people might feel that Apple will be capable of continuing to lead effectively without its leadership.
Jobs role and its response of his loss in Apple:
The role of Jobs in the Apple Company was extraordinary; because, Steve pulled company from the ruins and made them to become the top of market.
- Steve was the Apple Company’s chief innovator and his job had a very practical involvement in business...
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D. S. Malik, Data Structures Using C++, 2nd Edition, 2010
Methods (Ch6) - Review
1. (The MyRoot method) Below is a manual implementation of the Math.sqrt() method in Java.
There are two methods, method #1 which calculates the square root for positive integers, and
method #2, which calculates the square root of positive doubles (also works for integers).
public class SquareRoot {
public static void main(String[] args) {
}
// implement a loop of your choice here
// Method that calculates the square root of integer variables
public static double myRoot(int number) {
double root;
root=number/2;
double root old;
do {
root old root;
root (root_old+number/root_old)/2;
} while (Math.abs(root_old-root)>1.8E-6);
return root;
}
// Method that calculates the square root of double variables
public static double myRoot(double number) {
double root;
root number/2;
double root_old;
do {
root old root;
root (root_old+number/root_old)/2;
while (Math.abs (root_old-root)>1.0E-6);
return root;
}
}
Program-it-Yourself: In the main method, create a program that…
I would like to know the main features about the following 3 key concepts:1. Backup Domain Controller (BDC)2. Access Control List (ACL)3. Dynamic Memory
Chapter 4 Solutions
EBK USING MIS
Ch. 4.4 - Prob. 1NFCQCh. 4.4 - Prob. 2NFCQCh. 4.4 - Why might doctors and nutritionists be interested...Ch. 4.4 - Prob. 4NFCQCh. 4.4 - Prob. 5NFCQCh. 4.4 - Prob. 6NFCQCh. 4.6 - Prob. 1EGDQCh. 4.6 - Prob. 3EGDQCh. 4.6 - Prob. 4EGDQCh. 4.8 - Prob. 1SGDQ
Ch. 4.8 - Prob. 2SGDQCh. 4.8 - Prob. 3SGDQCh. 4.8 - Prob. 4SGDQCh. 4.8 - Prob. 4.1ARQCh. 4.8 - Prob. 4.2ARQCh. 4.8 - Prob. 4.3ARQCh. 4.8 - Prob. 4.4ARQCh. 4.8 - Prob. 4.5ARQCh. 4.8 - Prob. 4.6ARQCh. 4.8 - Prob. 4.7ARQCh. 4.8 - Prob. 4.8ARQCh. 4 - Prob. 4.1UYKCh. 4 - Prob. 4.2UYKCh. 4 - Prob. 4.3UYKCh. 4 - Prob. 4.4UYKCh. 4 - Prob. 4.5UYKCh. 4 - Prob. 4.6UYKCh. 4 - Prob. 4.7CE4Ch. 4 - Prob. 4.8CE4Ch. 4 - Prob. 4.9CE4Ch. 4 - Prob. 4.1CE4Ch. 4 - Prob. 4.11CE4Ch. 4 - Prob. 4.12CS4Ch. 4 - Prob. 4.13CS4Ch. 4 - Prob. 4.14CS4Ch. 4 - Prob. 4.15CS4Ch. 4 - Prob. 4.16CS4Ch. 4 - Prob. 4.17MMLCh. 4 - Prob. 4.18MML
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