Chapter 4, Problem 4.145CP

Interpretation Introduction

Interpretation:

Identity of a metal which (1g) reacts with $O_2$ to produce an oxide 1.890 g with formula $M_2{O}_3$ should be determined.

Concept introduction:

• Amount of any substance which combines with either 8 g O or 1 g H or 35.5 g Cl is known as equivalent weight (E).
Equivalent is related with valency (V) as $E=A/V$
• where A is the atomic weight of the metal.

Given:

1 g metal reacts with O to form 1.890 g metal oxide $M_2{O}_3$. The metal reacts with $HCl$ and steam but not with water at room temperature.