The beaker that has volume triple times of the volume in beaker A is to be identified. Concept introduction: Dilution is the process of converting a concentrated solution into a dilute solution by adding the solvent. In the resultant solution, amount of solute remain fixed but the volume of the solution increases. The moles of solute before and after dilution remain fixed. The expression to calculate the number of spheres in diluted solution when number of spheres and volume of concentrated solution and volume of diluted solution are given is as follows: N dil = N conc V conc V dil Here, N dil is the number of sphere present in diluted solution. V dil is the volume of diluted solution. N conc the number of sphere present in the concentrated solution. V conc is the volume of concentrated solution.
The beaker that has volume triple times of the volume in beaker A is to be identified. Concept introduction: Dilution is the process of converting a concentrated solution into a dilute solution by adding the solvent. In the resultant solution, amount of solute remain fixed but the volume of the solution increases. The moles of solute before and after dilution remain fixed. The expression to calculate the number of spheres in diluted solution when number of spheres and volume of concentrated solution and volume of diluted solution are given is as follows: N dil = N conc V conc V dil Here, N dil is the number of sphere present in diluted solution. V dil is the volume of diluted solution. N conc the number of sphere present in the concentrated solution. V conc is the volume of concentrated solution.
The beaker that has volume triple times of the volume in beaker A is to be identified.
Concept introduction:
Dilution is the process of converting a concentrated solution into a dilute solution by adding the solvent. In the resultant solution, amount of solute remain fixed but the volume of the solution increases. The moles of solute before and after dilution remain fixed.
The expression to calculate the number of spheres in diluted solution when number of spheres and volume of concentrated solution and volume of diluted solution are given is as follows:
Ndil=NconcVconcVdil
Here,
Ndil is the number of sphere present in diluted solution.
Vdil is the volume of diluted solution.
Nconc the number of sphere present in the concentrated solution.
Vconc is the volume of concentrated solution.
(b)
Interpretation Introduction
Interpretation:
The beaker that has volume double of the volume in beaker A is to be identified.
Concept introduction:
Dilution is the process of converting a concentrated solution into a dilute solution by adding the solvent. In the resultant solution, amount of solute remain fixed but the volume of the solution increases. The moles of solute before and after dilution remain fixed.
The expression to calculate the number of spheres in diluted solution when number of spheres and volume of concentrated solution and volume of diluted solution are given is as follows:
Ndil=NconcVconcVdil
Here,
Ndil is the number of sphere present in diluted solution.
Vdil is the volume of diluted solution.
Nconc the number of sphere present in the concentrated solution.
Vconc is the volume of concentrated solution.
(c)
Interpretation Introduction
Interpretation:
The beaker that has volume quadruple of the volume in beaker A is to be identified.
Concept introduction:
Dilution is the process of converting a concentrated solution into a dilute solution by adding the solvent. In the resultant solution, amount of solute remain fixed but the volume of the solution increases. The moles of solute before and after dilution remain fixed.
The expression to calculate the number of spheres in diluted solution when number of spheres and volume of concentrated solution and volume of diluted solution are given is as follows:
Ndil=NconcVconcVdil
Here,
Ndil is the number of sphere present in diluted solution.
Vdil is the volume of diluted solution.
Nconc the number of sphere present in the concentrated solution.
Draw the major products of the
following reaction:
HCI
For each molecule, assign each stereocenter as R or S. Circle the meso compounds. Label each compound as chiral or achiral.
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Organic Chemistry II Lecture (mx
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Curved arrows are used to illustrate the flow of electrons. Using
the provided starting and product structures, draw the curved
electron-pushing arrows for the following reaction or
mechanistic step(s).
Be sure to account for all bond-breaking and bond-making
steps.
Problem 25 of 35
Select to Edit Arrows
CH3CH2OK, CH3CH2OH
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Gemini
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