Physics for Scientists and Engineers
Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
bartleby

Videos

Question
Book Icon
Chapter 4, Problem 37P
To determine

The magnitude of the acceleration of object for the given figures.

Expert Solution & Answer
Check Mark

Answer to Problem 37P

The magnitude of the acceleration of object for case (a) is 4.24m/s2 and for case (b) is 8.39m/s2 .

Explanation of Solution

Given:

The given diagram is shown in Figure 1.

  Physics for Scientists and Engineers, Chapter 4, Problem 37P

Figure 1

The acceleration when it acts on object on frictionless surface is, a=3.0m/s2

Formula used:

The expression for the force is given by,

  F0=ma

Here, F0 is the required force.

The net force acting on object due to F0 and F0 which are 90° apart is given by,

  Fnet=F0+F0|Fnet|= | F 0 |2+ | F 0 |2+2 | F 0 |2cosθ

The net force acting on object due to F0 and 2F0 which are 45° apart is given by,

  Fnet=F0+2F0|Fnet|= | 2 F 0 |2+ | F 0 |2+2×2× | F 0 |2cosθ

Calculation:

The value of the force is calculated as,

  F0=ma=m(3.0m/ s 2)=3mN

For the case (a),

The net force acting on object due to F0 and F0 which are 90° apart is calculated as,

  |Fnet|= | F 0 |2+ | F 0 |2+2 | F 0 |2cosθ= ( 3m )2+ ( 3m )2+2 ( 3m )2cos90°=18m2=32mN

The value of the acceleration is calculated as,

  Fnet=m|a1|32mN=m|a1||a1|=32m/s2|a1|=4.24m/s2

For the case (b),

The net force acting on object due to F0 and 2F0 which are 45° apart is calculated as,

  |Fnet|= | 2 F 0 |2+ | F 0 |2+2×2× | F 0 |2cosθ= ( ( 2 )3m )2+ ( 3m )2+2×2× ( 3m )2cos45°=( 36+9+ 36 2 )mN=8.39mN

The value of the acceleration is calculated as,

  Fnet=m|a2|8.39mN=m|a2||a2|=8.39m/s2

Conclusion:

Therefore, the magnitude of the acceleration of object for case (a) is 4.24m/s2 and for case (b) is 8.39m/s2 .

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
(a) What magnification in multiples is produced by a 0.150 cm focal length microscope objective that is 0.160 cm from the object being viewed? 15.9 (b) What is the overall magnification in multiples if an eyepiece that produces a magnification of 7.90x is used? 126 × ×
Gravitational Potential Energy
E = кедо Xo A continuous line of charge lies along the x axis, extending from x = +x to positive infinity. The line carries positive charge with a uniform linear charge density 10. (a) What is the magnitude of the electric field at the origin? (Use the following as necessary: 10, Xo, and ke.) (b) What is the direction of the electric field at the origin? O O O O O O G -y +z ○ -z +x -x +y

Chapter 4 Solutions

Physics for Scientists and Engineers

Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Text book image
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
Classical Dynamics of Particles and Systems
Physics
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Cengage Learning
Text book image
Glencoe Physics: Principles and Problems, Student...
Physics
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Glencoe/McGraw-Hill
Text book image
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
Drawing Free-Body Diagrams With Examples; Author: The Physics Classroom;https://www.youtube.com/watch?v=3rZR7FSSidc;License: Standard Youtube License