(a)
Interpretation:Whether the zinc chloride soluble in water or not is to be predicted.
Concept introduction:The solubility of any substance depends upon the solubility product and ionic product of that substance in water. If the value of the solubility product is greater than the tonic product then that substance would get soluble in water but if the value of the ionic product is greater than the solubility product then that substance would get precipitate.
(b)
Interpretation:Whether the lead(II) nitrate soluble in water or not is to be predicted.
Concept introduction:The solubility of any substance depends upon the solubility product and ionic product of that substance in water. If the value of the solubility product is greater than the tonic product then that substance would get soluble in water but if the value of the ionic product is greater than the solubility product then that substance would get precipitate.
(c)
Interpretation:Whether the lead (II) sulfate soluble in water or not is to be predicted.
Concept introduction:The solubility of any substance depends upon the solubility product and ionic product of that substance in water. If the value of the solubility product is greater than the tonic product then that substance would get soluble in water but if the value of the ionic product is greater than the solubility product then that substance would get precipitate.
(d)
Interpretation:Whether the sodium iodide soluble in water or not is to be predicted.
Concept introduction:The solubility of any substance depends upon the solubility product and ionic product of that substance in water. If the value of the solubility product is greater than the tonic product then that substance would get soluble in water but if the value of the ionic product is greater than the solubility product then that substance would get precipitate.
(e)
Interpretation:Whether the cobalt (III)sulfide soluble in water or not is to be predicted.
Concept introduction:The solubility of any substance depends upon the solubility product and ionic product of that substance in water. If the value of the solubility product is greater than the tonic product then that substance would get soluble in water but if the value of the ionic product is greater than the solubility product then that substance would get precipitate.
(f)
Interpretation:Whether the chromium (III) hydroxide soluble in water or not is to be predicted.
Concept introduction:The solubility of any substance depends upon the solubility product and ionic product of that substance in water. If the value of the solubility product is greater than the tonic product then that substance would get soluble in water but if the value of the ionic product is greater than the solubility product then that substance would get precipitate.
(g)
Interpretation:Whether the magnesiumcarbonate soluble in water or not is to be predicted.
Concept introduction:The solubility of any substance depends upon the solubility product and ionic product of that substance in water. If the value of the solubility product is greater than the tonic product then that substance would get soluble in water but if the value of the ionic product is greater than the solubility product then that substance would get precipitate.
(h)
Interpretation:Whether the ammonium carbonate soluble in water or not is to be predicted.
Concept introduction:The solubility of any substance depends upon the solubility product and ionic product of that substance in water. If the value of the solubility product is greater than the tonic product then that substance would get soluble in water but if the value of the ionic product is greater than the solubility product then that substance would get precipitate.
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- uppose you are trying to help your friend understand the general solubility rules for ionic substances in water. Explain in general terms to your friend what the solubility rules mean, and give an example of how the rules could be applied in determining the identity of the precipitate in a reaction between solutions of two ionic compounds.arrow_forwardOn the basis of the general solubility rules given in Table 7.1, predict the identity of the precipitate that forms when aqueous solutions of the following Substances are mixed. If no precipitate is likely, indicate which rules apply. mg src=Images/HTML_99425-7-16ALQ_image001.jpg alt="" align="top"/>arrow_forwardUsing the general solubility rules discussed in Chapter 7, give the formulas of live substances that would be expected to be readily soluble in water and five substances that would be expected to not be very soluble in water. For each of the substances you choose, indicate the specific solubility rule you applied to make your prediction.arrow_forward
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- Lead(II) nitrate is added to four separate beakers that contain the following: aker 1 (sodium chloride) eaker 2 (sodium hydroxide) eaker 3 (sodium phosphate) eaker 4 (sodium sulfate) ter the addition of the lead(II) nitrate solution to each beaker, in which beaker(s) will a precipitate form? Use the general solubility rules given in Table 7.1 to guide you.arrow_forwardHow many grams of precipitate are formed if 175 mL of a 0.750 M aluminum sulfate solution and 375 mL of a 1.15 M sodium hydroxide solution are mixed together?arrow_forwardummarize the simple solubility rules for ionic compounds. How do we use these rules in determining the identity of the solid formed in a precipitation reaction? Give examples including balanced complete and net ionic equations.arrow_forward
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