Program to convert a decimal number into any base between “2” and “9”: Program Plan: In “main()” function Declare variables “stackk1” for stack, “base_to” for base to which convert and “numm” for number in decimal to be convert. Read values for “base_to” and “numm” from user. If base is between “2” and “9” and “numm” is greater than “0”, Push the value of “numm” mod “base_to” into stack “stackk1”. Then Divide “numm” by “base_to” and take this value as next “numm”. Continue above two steps till “numm” becomes “0”. Pop all numbers from “stackk1” and print it till “stackk1” becomes empty. If base is not between “2” and “9”, print error message.

Question

Want to see the full answer?

Answer 1

Question

Chapter 4, Problem 2PA

Program Plan Intro

Program to convert a decimal number into any base between “2” and “9”:

Program Plan:

In “main()” function

Declare variables “stackk1” for stack, “base_to” for base to which convert and “numm” for number in decimal to be convert.

Read values for “base_to” and “numm” from user.

If base is between “2” and “9” and “numm” is greater than “0”,

Push the value of “numm” mod “base_to” into stack “stackk1”.

Then Divide “numm” by “base_to” and take this value as next “numm”.

Continue above two steps till “numm” becomes “0”.

Pop all numbers from “stackk1” and print it till “stackk1” becomes empty.

If base is not between “2” and “9”, print error message.

Program Plan Intro

Modified program to convert a decimal number into any base between “11” and “27”:

Program Plan:

In “main()” function

Declare variables “stackk1” for stack, “base_to” for base to which convert and “numm” for number in decimal to be convert.

Read values for “base_to” and “numm” from user.

If base is between “11” and “27” and “numm” is greater than “0”,

Push the value of “numm” mod “base_to” into stack “stackk1”.

Then Divide “numm” by “base_to” and take this value as next “numm”.

Continue above two steps till “numm” becomes “0”.

Pop each number “ele” from “stackk1”

If “ele” is less than or equal to “9”, print itself.

If “ele” is greater than “9” and less than “27”, print character corresponding to ASCII value of “ele+55”

If base is not between “11” and “27”, print error message.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

make corrections of this program based on the errors shown. this is CIS 227 .

Create 6 users: Don, Liz, Shamir, Jose, Kate, and Sal. Create 2 groups: marketing and research. Add Shamir, Jose, and Kate to the marketing group. Add Don, Liz, and Sal to the research group. Create a shared directory for each group. Create two files to put into each directory: spreadsheetJanuary.txt meetingNotes.txt Assign access permissions to the directories: Groups should have Read+Write access Leave owner permissions as they are “Everyone else” should not have any access Submit for grade: Screenshot of /etc/passwd contents showing your new users Screenshot of /etc/group contents showing new groups with their members Screenshot of shared directories you created with files and permissions

⚫ your circuit diagrams for your basic bricks, such as AND, OR, XOR gates and 1 bit multiplexers, ⚫ your circuit diagrams for your extended full adder, designed in Section 1 and ⚫ your circuit diagrams for your 8-bit arithmetical-logical unit, designed in Section 2. 1 An Extended Full Adder In this Section, we are going to design an extended full adder circuit (EFA). That EFA takes 6 one bit inputs: aj, bj, Cin, Tin, t₁ and to. Depending on the four possible combinations of values on t₁ and to, the EFA produces 3 one bit outputs: sj, Cout and rout. The EFA can be specified in principle by a truth table with 26 = 64 entries and 3 outputs. However, as the EFA ignores certain inputs in certain cases, it is easier to work with the following overview specification, depending only on t₁ and to in the first place: t₁ to Description 00 Output Relationship Ignored Inputs Addition Mode 2 Coutsjaj + bj + Cin, Tout= 0 Tin 0 1 Shift Left Mode Sj = Cin, Cout=bj, rout = 0 rin, aj 10 1 1 Shift Right…

Answer 2

Question

Chapter 4, Problem 2PA

Program Plan Intro

Program to convert a decimal number into any base between “2” and “9”:

Program Plan:

In “main()” function

Declare variables “stackk1” for stack, “base_to” for base to which convert and “numm” for number in decimal to be convert.

Read values for “base_to” and “numm” from user.

If base is between “2” and “9” and “numm” is greater than “0”,

Push the value of “numm” mod “base_to” into stack “stackk1”.

Then Divide “numm” by “base_to” and take this value as next “numm”.

Continue above two steps till “numm” becomes “0”.

Pop all numbers from “stackk1” and print it till “stackk1” becomes empty.

If base is not between “2” and “9”, print error message.

Program Plan Intro

Modified program to convert a decimal number into any base between “11” and “27”:

Program Plan:

In “main()” function

Declare variables “stackk1” for stack, “base_to” for base to which convert and “numm” for number in decimal to be convert.

Read values for “base_to” and “numm” from user.

If base is between “11” and “27” and “numm” is greater than “0”,

Push the value of “numm” mod “base_to” into stack “stackk1”.

Then Divide “numm” by “base_to” and take this value as next “numm”.

Continue above two steps till “numm” becomes “0”.

Pop each number “ele” from “stackk1”

If “ele” is less than or equal to “9”, print itself.

If “ele” is greater than “9” and less than “27”, print character corresponding to ASCII value of “ele+55”

If base is not between “11” and “27”, print error message.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 4, Problem 2PA

Program Plan Intro

Program to convert a decimal number into any base between “2” and “9”:

Program Plan:

In “main()” function

Declare variables “stackk1” for stack, “base_to” for base to which convert and “numm” for number in decimal to be convert.

Read values for “base_to” and “numm” from user.

If base is between “2” and “9” and “numm” is greater than “0”,

Push the value of “numm” mod “base_to” into stack “stackk1”.

Then Divide “numm” by “base_to” and take this value as next “numm”.

Continue above two steps till “numm” becomes “0”.

Pop all numbers from “stackk1” and print it till “stackk1” becomes empty.

If base is not between “2” and “9”, print error message.

Program Plan Intro

Modified program to convert a decimal number into any base between “11” and “27”:

Program Plan:

In “main()” function

Declare variables “stackk1” for stack, “base_to” for base to which convert and “numm” for number in decimal to be convert.

Read values for “base_to” and “numm” from user.

If base is between “11” and “27” and “numm” is greater than “0”,

Push the value of “numm” mod “base_to” into stack “stackk1”.

Then Divide “numm” by “base_to” and take this value as next “numm”.

Continue above two steps till “numm” becomes “0”.

Pop each number “ele” from “stackk1”

If “ele” is less than or equal to “9”, print itself.

If “ele” is greater than “9” and less than “27”, print character corresponding to ASCII value of “ele+55”

If base is not between “11” and “27”, print error message.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 4, Problem 2PA

Program Plan Intro

Program to convert a decimal number into any base between “2” and “9”:

Program Plan:

In “main()” function

Declare variables “stackk1” for stack, “base_to” for base to which convert and “numm” for number in decimal to be convert.

Read values for “base_to” and “numm” from user.

If base is between “2” and “9” and “numm” is greater than “0”,

Push the value of “numm” mod “base_to” into stack “stackk1”.

Then Divide “numm” by “base_to” and take this value as next “numm”.

Continue above two steps till “numm” becomes “0”.

Pop all numbers from “stackk1” and print it till “stackk1” becomes empty.

If base is not between “2” and “9”, print error message.

Program Plan Intro

Modified program to convert a decimal number into any base between “11” and “27”:

Program Plan:

In “main()” function

Declare variables “stackk1” for stack, “base_to” for base to which convert and “numm” for number in decimal to be convert.

Read values for “base_to” and “numm” from user.

If base is between “11” and “27” and “numm” is greater than “0”,

Push the value of “numm” mod “base_to” into stack “stackk1”.

Then Divide “numm” by “base_to” and take this value as next “numm”.

Continue above two steps till “numm” becomes “0”.

Pop each number “ele” from “stackk1”

If “ele” is less than or equal to “9”, print itself.

If “ele” is greater than “9” and less than “27”, print character corresponding to ASCII value of “ele+55”

If base is not between “11” and “27”, print error message.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 4, Problem 2PA

Program Plan Intro

Program to convert a decimal number into any base between “2” and “9”:

Program Plan:

In “main()” function

Declare variables “stackk1” for stack, “base_to” for base to which convert and “numm” for number in decimal to be convert.

Read values for “base_to” and “numm” from user.

If base is between “2” and “9” and “numm” is greater than “0”,

Push the value of “numm” mod “base_to” into stack “stackk1”.

Then Divide “numm” by “base_to” and take this value as next “numm”.

Continue above two steps till “numm” becomes “0”.

Pop all numbers from “stackk1” and print it till “stackk1” becomes empty.

If base is not between “2” and “9”, print error message.

Program Plan Intro

Modified program to convert a decimal number into any base between “11” and “27”:

Program Plan:

In “main()” function

Declare variables “stackk1” for stack, “base_to” for base to which convert and “numm” for number in decimal to be convert.

Read values for “base_to” and “numm” from user.

If base is between “11” and “27” and “numm” is greater than “0”,

Push the value of “numm” mod “base_to” into stack “stackk1”.

Then Divide “numm” by “base_to” and take this value as next “numm”.

Continue above two steps till “numm” becomes “0”.

Pop each number “ele” from “stackk1”

If “ele” is less than or equal to “9”, print itself.

If “ele” is greater than “9” and less than “27”, print character corresponding to ASCII value of “ele+55”

If base is not between “11” and “27”, print error message.

Answer 6

Chapter 4, Problem 2PA

Program Plan Intro

Program to convert a decimal number into any base between “2” and “9”:

Program Plan:

In “main()” function

Declare variables “stackk1” for stack, “base_to” for base to which convert and “numm” for number in decimal to be convert.

Read values for “base_to” and “numm” from user.

If base is between “2” and “9” and “numm” is greater than “0”,

Push the value of “numm” mod “base_to” into stack “stackk1”.

Then Divide “numm” by “base_to” and take this value as next “numm”.

Continue above two steps till “numm” becomes “0”.

Pop all numbers from “stackk1” and print it till “stackk1” becomes empty.

If base is not between “2” and “9”, print error message.

Answer 7

Chapter 4, Problem 2PA

Program Plan Intro

Program to convert a decimal number into any base between “2” and “9”:

Program Plan:

In “main()” function

Declare variables “stackk1” for stack, “base_to” for base to which convert and “numm” for number in decimal to be convert.

Read values for “base_to” and “numm” from user.

If base is between “2” and “9” and “numm” is greater than “0”,

Push the value of “numm” mod “base_to” into stack “stackk1”.

Then Divide “numm” by “base_to” and take this value as next “numm”.

Continue above two steps till “numm” becomes “0”.

Pop all numbers from “stackk1” and print it till “stackk1” becomes empty.

If base is not between “2” and “9”, print error message.

Answer 8

Program Plan Intro

Modified program to convert a decimal number into any base between “11” and “27”:

Program Plan:

In “main()” function

Declare variables “stackk1” for stack, “base_to” for base to which convert and “numm” for number in decimal to be convert.

Read values for “base_to” and “numm” from user.

If base is between “11” and “27” and “numm” is greater than “0”,

Push the value of “numm” mod “base_to” into stack “stackk1”.

Then Divide “numm” by “base_to” and take this value as next “numm”.

Continue above two steps till “numm” becomes “0”.

Pop each number “ele” from “stackk1”

If “ele” is less than or equal to “9”, print itself.

If “ele” is greater than “9” and less than “27”, print character corresponding to ASCII value of “ele+55”

If base is not between “11” and “27”, print error message.

Answer 9

Program Plan Intro

Modified program to convert a decimal number into any base between “11” and “27”:

Program Plan:

In “main()” function

Declare variables “stackk1” for stack, “base_to” for base to which convert and “numm” for number in decimal to be convert.

Read values for “base_to” and “numm” from user.

If base is between “11” and “27” and “numm” is greater than “0”,

Push the value of “numm” mod “base_to” into stack “stackk1”.

Then Divide “numm” by “base_to” and take this value as next “numm”.

Continue above two steps till “numm” becomes “0”.

Pop each number “ele” from “stackk1”

If “ele” is less than or equal to “9”, print itself.

If “ele” is greater than “9” and less than “27”, print character corresponding to ASCII value of “ele+55”

If base is not between “11” and “27”, print error message.

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 13

Ch. 4 - Prob. 1E Ch. 4 - Prob. 2E Ch. 4 - Prob. 3E Ch. 4 - Prob. 4E Ch. 4 - Prob. 5E Ch. 4 - Prob. 6E Ch. 4 - Prob. 7E Ch. 4 - Prob. 8E Ch. 4 - Prob. 9E Ch. 4 - Prob. 10E

Concept explainers

Want to see the full answer?

Chapter 4 Solutions