Explanation Given data: Car’s speed at initial v i = 35 mph , which is v i = 15.6464 m s . Car’s mass is 1650 kg. Refer to Figure 1, it shows the car’s acceleration into the wall. The initial acceleration is 0 m s 2 . The final acceleration (maximum acceleration) by the car approximately is 300 m s 2 at 62 ms . Change in time interval is Δ t = 62 ms to reach maximum point. Formula used: The formula for the maximum force experienced by the car is F = m a x (1) Write an acceleration in terms of initial and final velocity of the car, a x = v f − v i Δ t Substitute v f − v i Δ t for a x in equation (1). F = m ( v f − v i ) Δ t (2) Here, m is the mass of the car. a x is the acceleration of the car. The maximum final speed is, v f = a x Δ t (3) Explanation: Draw the diagram by the indications of maximum acceleration and time at maximum force exerts. Refer to Figure 1, the maximum acceleration 300 m s 2 is occurs at the time approximately 62 ms . When the car has maximum acceleration it gains maximum speed and exerts maximum force on the wall

College Physics: A Strategic Approach, Books a la Carte Edition (4th Edition)

4th Edition

ISBN: 9780134700502

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

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Chapter 4, Problem 22P

To determine

The maximum force exerted by the car.

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Chapter 4, Problem 21P

Chapter 4, Problem 23P

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Chapter 4 Solutions

College Physics: A Strategic Approach, Books a la Carte Edition (4th Edition)

Ch. 4 - If an object is not moving, does that mean that...Ch. 4 - An object moves in a straight line at a constant...Ch. 4 - If you know all of the forces acting on a moving...Ch. 4 - Three arrows are shot horizontally. They have left...Ch. 4 - Prob. 5CQ Ch. 4 - Internal injuries in vehicular acci-dents may be...Ch. 4 - Heres a great everyday use of the physics...Ch. 4 - Prob. 8CQ Ch. 4 - Suppose you are an astronaut in deep space, far...Ch. 4 - Jonathan accelerates away from a stop sign. His...

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