
The most likely event in a random sample of 100.
To determine: The likelihood of the most likely event.

Answer to Problem 1UA
The most likely event in a random sample of 100 is that 40 people prefer Brand A toothpaste.
The likelihood of the most likely event, “40 people prefer Brand A toothpaste” is 0.0812191.
Explanation of Solution
Given info:
The claim of a manufacturer is that, of all the toothpaste buyers, 40% prefer the toothpaste of Brand A.
Justification:
Define the random variable x as the number of toothpaste buyers who prefer the toothpaste of Brand A, in a random sample of 100.
A close inspection of the graph shows that the
The graph reveals that the value of the probability of the event “40 people prefer Brand A toothpaste” is a 0.081.
Calculation:
Here, the claim of the manufacturer is 40% (or 0.40 proportion) of buyers prefer Brand A and preference of each buyer is independent of the other. The size of the random sample (n) is 100. The probability of success (p) is the probability that a buyer prefers Brand A, which is 0.40. Hence, the random variable follows Binomial distribution.
The binomial probability distribution formula is as follows:
Where, n is the number of trials, x is the number of successes among n trials, p is the probability of success and q is the probability of failure.
Consider n as 100, p as 0.40 and q as
The probability that 40 people prefer Brand A is given below:
Software procedure:
Software procedure for calculating the probability is given below:
- Choose Calc > Probability Distributions > Binomial probability distribution.
- Choose Probability.
- Enter Number of trials as 100 and Event probability as 0.40.
- In Input constant, enter the value 40.
- Click OK.
Output obtained from MINITAB is given below:
Thus, the probability that 40 people prefer Brand A is 0.0812191.
Conclusion:
From the graph, it can be seen that the event “40 people prefer Brand A toothpaste” has the highest probability, implying that this is the most likely event. On close inspection of the graph, the likelihood of the event appears to be around 0.081.
From the MINITAB output, the probability that 40 people prefer Brand A toothpaste is 0.0812191.
Want to see more full solutions like this?
Chapter 4 Solutions
Elementary Statistics: Picturing the World (6th Edition)
- I need help with this problem and an explanation of the solution for the image described below. (Statistics: Engineering Probabilities)arrow_forwardI need help with this problem and an explanation of the solution for the image described below. (Statistics: Engineering Probabilities)arrow_forwardI need help with this problem and an explanation of the solution for the image described below. (Statistics: Engineering Probabilities)arrow_forward
- I need help with this problem and an explanation of the solution for the image described below. (Statistics: Engineering Probabilities)arrow_forwardI need help with this problem and an explanation of the solution for the image described below. (Statistics: Engineering Probabilities)arrow_forward3. Consider the following regression model: Yi Bo+B1x1 + = ···· + ßpxip + Єi, i = 1, . . ., n, where are i.i.d. ~ N (0,0²). (i) Give the MLE of ẞ and σ², where ẞ = (Bo, B₁,..., Bp)T. (ii) Derive explicitly the expressions of AIC and BIC for the above linear regression model, based on their general formulae.arrow_forward
- How does the width of prediction intervals for ARMA(p,q) models change as the forecast horizon increases? Grows to infinity at a square root rate Depends on the model parameters Converges to a fixed value Grows to infinity at a linear ratearrow_forwardConsider the AR(3) model X₁ = 0.6Xt-1 − 0.4Xt-2 +0.1Xt-3. What is the value of the PACF at lag 2? 0.6 Not enough information None of these values 0.1 -0.4 이arrow_forwardSuppose you are gambling on a roulette wheel. Each time the wheel is spun, the result is one of the outcomes 0, 1, and so on through 36. Of these outcomes, 18 are red, 18 are black, and 1 is green. On each spin you bet $5 that a red outcome will occur and $1 that the green outcome will occur. If red occurs, you win a net $4. (You win $10 from red and nothing from green.) If green occurs, you win a net $24. (You win $30 from green and nothing from red.) If black occurs, you lose everything you bet for a loss of $6. a. Use simulation to generate 1,000 plays from this strategy. Each play should indicate the net amount won or lost. Then, based on these outcomes, calculate a 95% confidence interval for the total net amount won or lost from 1,000 plays of the game. (Round your answers to two decimal places and if your answer is negative value, enter "minus" sign.) I worked out the Upper Limit, but I can't seem to arrive at the correct answer for the Lower Limit. What is the Lower Limit?…arrow_forward
- Let us suppose we have some article reported on a study of potential sources of injury to equine veterinarians conducted at a university veterinary hospital. Forces on the hand were measured for several common activities that veterinarians engage in when examining or treating horses. We will consider the forces on the hands for two tasks, lifting and using ultrasound. Assume that both sample sizes are 6, the sample mean force for lifting was 6.2 pounds with standard deviation 1.5 pounds, and the sample mean force for using ultrasound was 6.4 pounds with standard deviation 0.3 pounds. Assume that the standard deviations are known. Suppose that you wanted to detect a true difference in mean force of 0.25 pounds on the hands for these two activities. Under the null hypothesis, 40 0. What level of type II error would you recommend here? = Round your answer to four decimal places (e.g. 98.7654). Use α = 0.05. β = 0.0594 What sample size would be required? Assume the sample sizes are to be…arrow_forwardConsider the hypothesis test Ho: 0 s² = = 4.5; s² = 2.3. Use a = 0.01. = σ against H₁: 6 > σ2. Suppose that the sample sizes are n₁ = 20 and 2 = 8, and that (a) Test the hypothesis. Round your answers to two decimal places (e.g. 98.76). The test statistic is fo = 1.96 The critical value is f = 6.18 Conclusion: fail to reject the null hypothesis at a = 0.01. (b) Construct the confidence interval on 02/2/622 which can be used to test the hypothesis: (Round your answer to two decimal places (e.g. 98.76).) 035arrow_forwardUsing the method of sections need help solving this please explain im stuckarrow_forward
- MATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th...StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C...StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage Learning
- Elementary Statistics: Picturing the World (7th E...StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. Freeman





