
Concept explainers
The Bandana Republic is a small country consisting of four states: Apure (population 3,310,000), Barinas (population 2,670,000), Carabobo (population 1,330,000), and Dolores (population 690,000). Suppose that there are M = 160 seats in the Bandana Congress, to be apportioned among the four states based on their respective populations.
a. Find the standard divisor.
b. Find each state’s standard quota.

(a)
To find:
The standard divisor of given population.
Answer to Problem 1E
Solution:
The standard divisor for each seat of Bandana congress is
Explanation of Solution
Given:
It is given that the four states of country Bandana Republic has respective population as, Apure of 3, 310, 000 people, Barinas of 2, 670, 000 people, Carabobo of 1, 330, 000 people and Dolores of 690, 000 people. The number of seats for Bandana congress is 160 to be apportioned from four states.
The standard divisor (SD) states the number of population per unit seat, or it can be calculated as the ratio of the total population to the number of seats allocated of the congress, that is,
Calculation:
From the given information the total population is the addition of 3, 310, 000, 2, 670, 000, 1, 330, 000 and 690, 000 people, that is,
The required standard divisor is given as,
It is given that the number of seats is 160.
From equation
Conclusion:
Thus, the standard divisor for each seat of Bandana congress is

(b)
To find:
The standard quota of each state.
Answer to Problem 1E
Solution:
Conclusion:
Thus the standard quota for respective state is,
States | Apure | Barinas | Carabobo | Dolores |
Population | 3, 310, 000 | 2, 670, 000 | 1, 330, 000 | 690, 000 |
Standard quota |
Explanation of Solution
Given:
It is given that the four states of country Bandana Republic has respective population as, Apure of 3, 310, 000 people, Barinas of 2, 670, 000 people, Carabobo of 1, 330, 000 people and Dolores of 690, 000 people. The number of seats for Bandana congress is 160 to be apportioned from four states.
The standard quotas (
Calculation:
From part 1, the standard divisor of given population is,
The standard quota of state Apure is given as,
It is given that the population of Apure is 3, 310, 000 people.
From equation
The standard quota of state Barinas is given as,
It is given that the population of Barinas is 2, 670, 000 people.
From equation
The standard quota of state Carabobo is given as,
It is given that the population of Carabobo is 1, 330, 000 people.
From equation
The standard quota of state Dolores is given as,
It is given that the population of Dolores is 690, 000 people.
From equation
Conclusion:
Thus the standard quota for respective state is,
States | Apure | Barinas | Carabobo | Dolores |
Population | 3, 310, 000 | 2, 670, 000 | 1, 330, 000 | 690, 000 |
Standard quota |
Want to see more full solutions like this?
Chapter 4 Solutions
Excursions in Modern Mathematics (9th Edition)
Additional Math Textbook Solutions
Finite Mathematics for Business, Economics, Life Sciences and Social Sciences
Pathways To Math Literacy (looseleaf)
College Algebra (Collegiate Math)
Calculus: Early Transcendentals (2nd Edition)
Elementary Statistics: A Step By Step Approach
Intro Stats, Books a la Carte Edition (5th Edition)
- Let A = {a, b, c, d}, B = {a,b,c}, and C = {s, t, u,v}. Draw an arrow diagram of a function for each of the following descriptions. If no such function exists, briefly explain why. (a) A function f : AC whose range is the set C. (b) A function g: BC whose range is the set C. (c) A function g: BC that is injective. (d) A function j : A → C that is not bijective.arrow_forwardLet f:R->R be defined by f(x)=x^(3)+5.(a) Determine if f is injective. why?(b) Determine if f is surjective. why?(c) Based upon (a) and (b), is f bijective? why?arrow_forwardLet f:R->R be defined by f(x)=x^(3)+5.(a) Determine if f is injective.(b) Determine if f is surjective. (c) Based upon (a) and (b), is f bijective?arrow_forward
- Please as many detarrow_forward8–23. Sketching vector fields Sketch the following vector fieldsarrow_forward25-30. Normal and tangential components For the vector field F and curve C, complete the following: a. Determine the points (if any) along the curve C at which the vector field F is tangent to C. b. Determine the points (if any) along the curve C at which the vector field F is normal to C. c. Sketch C and a few representative vectors of F on C. 25. F = (2½³, 0); c = {(x, y); y − x² = 1} 26. F = x (23 - 212) ; C = {(x, y); y = x² = 1}) , 2 27. F(x, y); C = {(x, y): x² + y² = 4} 28. F = (y, x); C = {(x, y): x² + y² = 1} 29. F = (x, y); C = 30. F = (y, x); C = {(x, y): x = 1} {(x, y): x² + y² = 1}arrow_forward
- ٣/١ B msl kd 180 Ka, Sin (1) I sin () sin(30) Sin (30) اذا ميريد شرح الكتب بس 0 بالفراغ 3) Cos (30) 0.866 4) Rotating 5) Synchronous speed, 120 x 50 G 5005 1000 s = 1000-950 Copper bosses 5kW Rotor input 5 0.05 : loo kw 6) 1 /0001 ined sove in peaper I need a detailed solution on paper please وه اذا ميريد شرح الكتب فقط ١٥٠ DC 7) rotor a ' (y+xlny + xe*)dx + (xsiny + xlnx + dy = 0. Q1// Find the solution of: ( 357arrow_forward۳/۱ R₂ = X2 2) slots per pole per phase 3/31 B. 180 msl Kas Sin (I) 1sin() sin(30) Sin (30) اذا ميريد شرح الكتب بس 0 بالفراغ 3) Cos (30): 0.866 4) Rotating 5) Synchronous speeds 120×50 looo G 1000-950 1000 Copper losses 5kw Rotor input 5 loo kw 0.05 6) 1 اذا ميريد شرح الكتب فقط look 7) rotor DC ined sove in peaper I need a detailed solution on paper please 0 64 Find the general solution of the following equations: QI//y(4)-16y= 0. Find the general solution of the following equations: Q2ll yll-4y/ +13y=esinx.arrow_forwardR₂ = X2 2) slots per pole per phase = 3/31 B-180 60 msl kd Kas Sin () 2 I sin (6) sin(30) Sin (30) اذا مريد شرح الكتب بس 0 بالفراغ 3 Cos (30) 0.866 4) Rotating ined sove in peaper 5) Synchronous speed s 120×50 6 s = 1000-950 1000 Copper losses 5kw Rotor input 5 0.05 6) 1 loo kw اذا ميريد شرح الكتب فقط Look 7) rotov DC I need a detailed solution on paper please 0 64 Solve the following equations: 0 Q1// Find the solution of: ( y • with y(0) = 1. dx x²+y²arrow_forward
- R₂ = X2 2) slots per pole per phase = 3/3 1 B-180-60 msl Ka Sin (1) Isin () sin(30) Sin (30) اذا ميريد شرح الكتب بس 0 بالفراغ 3) Cos (30) 0.866 4) Rotating 5) Synchronous speed, 120 x 50 s = 1000-950 1000 Copper losses 5kw Rotor input 5 6) 1 0.05 G 50105 loo kw اذا ميريد شرح الكتب فقط look 7) rotov DC ined sove in peaper I need a detailed solution on paper please 064 2- A hot ball (D=15 cm ) is cooled by forced air T.-30°C, the rate of heat transfer from the ball is 460.86 W. Take for the air -0.025 Wim °C and Nu=144.89, find the ball surface temperature a) 300 °C 16 b) 327 °C c) 376 °C d) None か = 750 01arrow_forwardAnswer questions 8.3.3 and 8.3.4 respectively 8.3.4 .WP An article in Medicine and Science in Sports and Exercise [“Electrostimulation Training Effects on the Physical Performance of Ice Hockey Players” (2005, Vol. 37, pp. 455–460)] considered the use of electromyostimulation (EMS) as a method to train healthy skeletal muscle. EMS sessions consisted of 30 contractions (4-second duration, 85 Hz) and were carried out three times per week for 3 weeks on 17 ice hockey players. The 10-meter skating performance test showed a standard deviation of 0.09 seconds. Construct a 95% confidence interval of the standard deviation of the skating performance test.arrow_forward8.6.7 Consider the tire-testing data in Exercise 8.2.3. Compute a 95% tolerance interval on the life of the tires that has confidence level 95%. Compare the length of the tolerance interval with the length of the 95% CI on the population mean. Which interval is shorter? Discuss the difference in interpretation of these two intervals.arrow_forward
