Concept explainers
Reason why the muzzle of a rifle is not aimed at the centre of the target. The reason why this is more important for longer ranges.

Answer to Problem 1CQ
The muzzle of a rifle is not directly aimed at target to compensate the effect of gravity. For longer range it is more important as gravity gets longer time to affect the path of the bullet.
Explanation of Solution
While travelling from the muzzle to rifle towards the target, the bullet is influenced by gravity. Gravitational force accelerates the bullet down. If the bullet is pointed directly, the acceleration due to gravity will cause the bullet land below the target. Thus the muzzle of a rifle is not aimed directly at the centre of the target.
When the range of the bullet is long, the time spent in air is proportionally longer, gravity will no longer influence bullet’s path. Therefore, for a longer path it is more important to not to aim directly at the target, but at a suitable point land exactly on the target.
Conclusion
The muzzle of a rifle is not directly aimed at target to compensate the effect of gravity. For longer range it is more important as gravity gets longer time to affect the path of the bullet.
Want to see more full solutions like this?
Chapter 4 Solutions
COLLEGE PHYICS
- Aromatic molecules like those in perfume have a diffusion coefficient in air of approximately 2×10−5m2/s2×10−5m2/s. Part A Estimate, to one significant figure, how many hours it takes perfume to diffuse 2.5 mm, about 6.5 ftft, in still air. Express your answer in hours to one significant figure.arrow_forwardRocket Science: CH 83. A rocket of mass M moving at speed v ejects an infinitesimal mass dm out its exhaust nozzle at speed vex. (a) Show that con- servation of momentum implies that M dy = vex dm, where dy is the change in the rocket's speed. (b) Integrate this equation from some initial speed v; and mass M; to a final speed vf and mass Mf Vf to show that the rocket's final velocity is given by the expression V₁ = V¡ + Vex ln(M¡/M₁).arrow_forwardFormant Freqmcy The horizontal dotted lines represent the formants. The first box represents the schwa sound. The second box is a different vowel. The scale is the same on each of these two vowels. Use the two formant contours to answer questions 12-16 SCHWA VOWEL 2 0.179362213 Time (s) 0.92125285 0.0299637119 4000 1079 Time(s) unknown 0.6843 13. Please describe what the tongue is doing to shift from the schwa to vowel 2? 14. Is vowel 2 a rounded or unrounded vowel? 15. Is vowel 2 a front or back vowel? 16. What vowel is vowel 2 (00, ee, ah) 0684285714arrow_forward
- microwavearrow_forward4) Consider the pulley (Mass = 20kg, Radius 0.3m) shown in the picture. Model this pulley as a uniform solid disk (1 = (1/2) MR2) that is hinged at its center of mass. If the hanging mass is 30 kg, and is released, (a) compute the angular acceleration of the pulley (b) calculate the acceleration of the hanging mass. A o 0.3 3019 20KSarrow_forwardRefer to the image attachedarrow_forward
- Shrinking Loop. A circular loop of flexible iron wire has an initial circumference of 161 cm , but its circumference is decreasing at a constant rate of 15.0 cm/s due to a tangential pull on the wire. The loop is in a constant uniform magnetic field of magnitude 1.00 T , which is oriented perpendicular to the plane of the loop. Assume that you are facing the loop and that the magnetic field points into the loop. Find the magnitude of the emf E induced in the loop after exactly time 9.00 s has passed since the circumference of the loop started to decrease. Find the direction of the induced current in the loop as viewed looking along the direction of the magnetic field. Please explain all stepsarrow_forwardMake up an application physics principle problem that provides three (3) significant equations based on the concepts of capacitors and ohm's law.arrow_forwardA straight horizontal garden hose 38.0 m long with an interior diameter of 1.50 cm is used to deliver 20oC water at the rate of 0.590 liters/s. Assuming that Poiseuille's Law applies, estimate the pressure drop (in Pa) from one end of the hose to the other.arrow_forward
- A rectangle measuring 30.0 cm by 40.0 cm is located inside a region of a spatially uniform magnetic field of 1.70 T , with the field perpendicular to the plane of the coil (the figure (Figure 1)). The coil is pulled out at a steady rate of 2.00 cm/s traveling perpendicular to the field lines. The region of the field ends abruptly as shown. Find the emf induced in this coil when it is all inside the field, when it is partly in the field, and when it is fully outside. Please show all steps.arrow_forwardA rectangular circuit is moved at a constant velocity of 3.00 m/s into, through, and then out of a uniform 1.25 T magnetic field, as shown in the figure (Figure 1). The magnetic field region is considerably wider than 50.0 cm . Find the direction (clockwise or counterclockwise) of the current induced in the circuit as it is going into the magnetic field (the first case), totally within the magnetic field but still moving (the second case), and moving out of the field (the third case). Find the magnitude of the current induced in the circuit as it is going into the magnetic field . Find the magnitude of the current induced in the circuit as it is totally within the magnetic field but still moving. Find the magnitude of the current induced in the circuit as it is moving out of the field. Please show all stepsarrow_forwardShrinking Loop. A circular loop of flexible iron wire has an initial circumference of 161 cm , but its circumference is decreasing at a constant rate of 15.0 cm/s due to a tangential pull on the wire. The loop is in a constant uniform magnetic field of magnitude 1.00 T , which is oriented perpendicular to the plane of the loop. Assume that you are facing the loop and that the magnetic field points into the loop. Find the magnitude of the emf E induced in the loop after exactly time 9.00 s has passed since the circumference of the loop started to decrease. Find the direction of the induced current in the loop as viewed looking along the direction of the magnetic field. Please explain all stepsarrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON





