Explanation Given info: The NASA claimed that the probability of a failure of the O ring seal in the joint between the two lower segments, was about 1 / 90 , 000 or about one in every 60,000 flights. According to risk-assessment study conducted for the Air force at about the same time assessed the probability to be 1 / 35 . Calculation: Let, the random variable X be the number of disasters in 25 trials. Binomial Distribution: A random variable X is said to follow Binomial distribution if X has only two outcomes “success” and “failure” and the mass function of X is, p ( x ) = ( n x ) p x q n − x , x = 0 , 1 , 2 , ... , n , Where n is the number of trials and p is the probability of success, q = 1 − p . The mean is μ = n p and the standard deviation is σ = ( n p q ) . If NASA’s assessment is correct, then X be a binomial random variable with n = 25 and p = 1 60 , 000 = 0.00001667 . If Air Force’s assessment is correct, then X be a binomial random variable with n = 25 and p = 1 35 = 0.02857 . It is known that, P ( X ≥ 1 ) = 1 − P ( X = 0 )

13th Edition

ISBN: 9780134080215

Author: James T. McClave, Terry T Sincich

Publisher: PEARSON

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

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Chapter 4, Problem 160CTC

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To find: The risk assessment appears to be more appropriate.

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