Concepts of Programming Languages (11th Edition)
11th Edition
ISBN: 9780133943023
Author: Robert W. Sebesta
Publisher: PEARSON
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Expert Solution & Answer
Chapter 4, Problem 13RQ
Explanation of Solution
The reason named constants are used:
The lexical analyzers collect the characters of the input string and group them into logical groups according to the pattern matching rules. These logical groupings are called as lexemes.
Lexical analyzer assigns some internal (numeric) codes to the lexemes (logical groupings) according to their structure. Instead of assigning numeric codes, named constants are used for token codes due to the following reasons:
- Gives better readability to the code...
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make corrections of this program based on the errors shown. this is CIS 227 .
Create 6 users: Don, Liz, Shamir, Jose, Kate, and Sal.
Create 2 groups: marketing and research.
Add Shamir, Jose, and Kate to the marketing group.
Add Don, Liz, and Sal to the research group.
Create a shared directory for each group.
Create two files to put into each directory:
spreadsheetJanuary.txt
meetingNotes.txt
Assign access permissions to the directories:
Groups should have Read+Write access
Leave owner permissions as they are
“Everyone else” should not have any access
Submit for grade:
Screenshot of /etc/passwd contents showing your new users
Screenshot of /etc/group contents showing new groups with their members
Screenshot of shared directories you created with files and permissions
⚫ your circuit diagrams for your basic bricks, such as AND, OR, XOR gates and 1 bit multiplexers,
⚫ your circuit diagrams for your extended full adder, designed in Section 1 and
⚫ your circuit diagrams for your 8-bit arithmetical-logical unit, designed in Section 2.
1 An Extended Full Adder
In this Section, we are going to design an extended full adder circuit (EFA). That EFA takes 6 one bit inputs: aj, bj,
Cin, Tin, t₁ and to. Depending on the four possible combinations of values on t₁ and to, the EFA produces 3 one bit
outputs: sj, Cout and rout.
The EFA can be specified in principle by a truth table with 26 = 64 entries and 3 outputs. However, as the EFA
ignores certain inputs in certain cases, it is easier to work with the following overview specification, depending only
on t₁ and to in the first place:
t₁ to Description
00
Output Relationship
Ignored
Inputs
Addition Mode
2 Coutsjaj + bj + Cin, Tout= 0
Tin
0 1
Shift Left Mode
Sj = Cin,
Cout=bj, rout = 0
rin, aj
10
1 1
Shift Right…
Chapter 4 Solutions
Concepts of Programming Languages (11th Edition)
Ch. 4 - Prob. 1RQCh. 4 - Prob. 2RQCh. 4 - Prob. 3RQCh. 4 - Prob. 4RQCh. 4 - Prob. 5RQCh. 4 - Prob. 6RQCh. 4 - Prob. 7RQCh. 4 - Prob. 8RQCh. 4 - Prob. 9RQCh. 4 - Prob. 10RQ
Ch. 4 - Prob. 11RQCh. 4 - Prob. 12RQCh. 4 - Prob. 13RQCh. 4 - Prob. 14RQCh. 4 - Prob. 15RQCh. 4 - Prob. 16RQCh. 4 - Prob. 17RQCh. 4 - Prob. 18RQCh. 4 - Prob. 19RQCh. 4 - Prob. 20RQCh. 4 - Prob. 21RQCh. 4 - Prob. 22RQCh. 4 - Prob. 23RQCh. 4 - What was Knuths insight in developing the LR...Ch. 4 - Prob. 25RQCh. 4 - Prob. 26RQCh. 4 - Is left recursion a problem for LR parsers?Ch. 4 - Prob. 1PSCh. 4 - Prob. 2PSCh. 4 - Prob. 3PSCh. 4 - Prob. 4PSCh. 4 - Prob. 7PSCh. 4 - Prob. 8PS
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