The industrial productionof hydrazine ( N 2 H 2 ) by the Ranching process is the topic of the Focus On feature for Chapter 4 on www.masteringchemistry.com. The following chemical equation represents the overall process, which actually involves three consecutive reasons. 2NH 3 ( aq ) +CI 2 ( g ) +2NaOH ( aq ) ®N 2 H 4 ( aq ) +2NaCI ( aq ) +2H 2 O ( 1 ) a. Use the definition of percent atom economy (AE) from exercise 130 to calculate, to the nearest percent, the percent AE for the Ranching process. b. Propose a reaction for the synthesis of N 2 H 4 that has AE of 100%.
The industrial productionof hydrazine ( N 2 H 2 ) by the Ranching process is the topic of the Focus On feature for Chapter 4 on www.masteringchemistry.com. The following chemical equation represents the overall process, which actually involves three consecutive reasons. 2NH 3 ( aq ) +CI 2 ( g ) +2NaOH ( aq ) ®N 2 H 4 ( aq ) +2NaCI ( aq ) +2H 2 O ( 1 ) a. Use the definition of percent atom economy (AE) from exercise 130 to calculate, to the nearest percent, the percent AE for the Ranching process. b. Propose a reaction for the synthesis of N 2 H 4 that has AE of 100%.
The industrial productionof hydrazine
(
N
2
H
2
)
by the Ranching process is the topic of the Focus On feature for Chapter 4 on www.masteringchemistry.com. The following chemical equation represents the overall process, which actually involves three consecutive reasons.
2NH
3
(
aq
)
+CI
2
(
g
)
+2NaOH
(
aq
)
®N
2
H
4
(
aq
)
+2NaCI
(
aq
)
+2H
2
O
(
1
)
a. Use the definition of percent atom economy (AE) from exercise 130 to calculate, to the nearest percent, the percent AE for the Ranching process. b. Propose a reaction for the synthesis of
N
2
H
4
that has AE of 100%.
Use the average molarity of acetic acid (0.0867M) to calculate the concentration in % (m/v).
Then calculate the % difference between the calculated concentrations of your unknown vinegar solution with the 5.00% (w/v%) vinegar solution (check the formula for % difference in the previous lab or online). Before calculating the difference with vinegar, remember that this %(m/v) is of the diluted solution. It has been diluted 10 times.
What deprotonates or what can be formed? Please help me understand the problem.
Chapter 4 Solutions
General Chemistry: Principles And Modern Applications Plus Mastering Chemistry With Pearson Etext -- Access Card Package (11th Edition)
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell